"epimorphism" meaning in English

{
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "epi",
        "3": "morphism"
      },
      "expansion": "epi- + morphism",
      "name": "prefix"
    }
  ],
  "etymology_text": "epi- + morphism",
  "forms": [
    {
      "form": "epimorphisms",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {},
      "expansion": "epimorphism (plural epimorphisms)",
      "name": "en-noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "English terms prefixed with epi-",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "topical",
          "langcode": "en",
          "name": "Category theory",
          "orig": "en:Category theory",
          "parents": [
            "Mathematics",
            "Formal sciences",
            "Sciences",
            "All topics",
            "Fundamental"
          ],
          "source": "w"
        }
      ],
      "derived": [
        {
          "word": "epimorphic"
        }
      ],
      "glosses": [
        "A morphism p such that for any other pair of morphisms f and g, if f∘p=g∘p, then f = g."
      ],
      "hyponyms": [
        {
          "sense": "bimorphism | split epimorphism",
          "word": "isomorphism"
        },
        {
          "word": "coequalizer"
        }
      ],
      "id": "en-epimorphism-en-noun-aFSnBdWp",
      "links": [
        [
          "category theory",
          "category theory"
        ],
        [
          "morphism",
          "morphism"
        ]
      ],
      "raw_glosses": [
        "(category theory) A morphism p such that for any other pair of morphisms f and g, if f∘p=g∘p, then f = g."
      ],
      "related": [
        {
          "word": "epic"
        },
        {
          "word": "isomorphism"
        },
        {
          "word": "monomorphism"
        }
      ],
      "synonyms": [
        {
          "word": "epi"
        }
      ],
      "topics": [
        "category-theory",
        "computing",
        "engineering",
        "mathematics",
        "natural-sciences",
        "physical-sciences",
        "sciences"
      ],
      "translations": [
        {
          "code": "de",
          "lang": "German",
          "sense": "mathematics: map f such that whenever g composed with f equals h composed with f, then g=h",
          "tags": [
            "masculine"
          ],
          "word": "Epimorphismus"
        },
        {
          "code": "is",
          "lang": "Icelandic",
          "sense": "mathematics: map f such that whenever g composed with f equals h composed with f, then g=h",
          "tags": [
            "feminine"
          ],
          "word": "ámótun"
        },
        {
          "code": "ru",
          "lang": "Russian",
          "roman": "epimorfizm",
          "sense": "mathematics: map f such that whenever g composed with f equals h composed with f, then g=h",
          "tags": [
            "masculine"
          ],
          "word": "эпиморфизм"
        }
      ]
    }
  ],
  "word": "epimorphism"
}

{
  "derived": [
    {
      "word": "epimorphic"
    }
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "epi",
        "3": "morphism"
      },
      "expansion": "epi- + morphism",
      "name": "prefix"
    }
  ],
  "etymology_text": "epi- + morphism",
  "forms": [
    {
      "form": "epimorphisms",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {},
      "expansion": "epimorphism (plural epimorphisms)",
      "name": "en-noun"
    }
  ],
  "hyponyms": [
    {
      "sense": "bimorphism | split epimorphism",
      "word": "isomorphism"
    },
    {
      "word": "coequalizer"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "noun",
  "related": [
    {
      "word": "epic"
    },
    {
      "word": "isomorphism"
    },
    {
      "word": "monomorphism"
    }
  ],
  "senses": [
    {
      "categories": [
        "English countable nouns",
        "English entries with incorrect language header",
        "English lemmas",
        "English nouns",
        "English terms prefixed with epi-",
        "en:Category theory"
      ],
      "glosses": [
        "A morphism p such that for any other pair of morphisms f and g, if f∘p=g∘p, then f = g."
      ],
      "links": [
        [
          "category theory",
          "category theory"
        ],
        [
          "morphism",
          "morphism"
        ]
      ],
      "raw_glosses": [
        "(category theory) A morphism p such that for any other pair of morphisms f and g, if f∘p=g∘p, then f = g."
      ],
      "topics": [
        "category-theory",
        "computing",
        "engineering",
        "mathematics",
        "natural-sciences",
        "physical-sciences",
        "sciences"
      ]
    }
  ],
  "synonyms": [
    {
      "word": "epi"
    }
  ],
  "translations": [
    {
      "code": "de",
      "lang": "German",
      "sense": "mathematics: map f such that whenever g composed with f equals h composed with f, then g=h",
      "tags": [
        "masculine"
      ],
      "word": "Epimorphismus"
    },
    {
      "code": "is",
      "lang": "Icelandic",
      "sense": "mathematics: map f such that whenever g composed with f equals h composed with f, then g=h",
      "tags": [
        "feminine"
      ],
      "word": "ámótun"
    },
    {
      "code": "ru",
      "lang": "Russian",
      "roman": "epimorfizm",
      "sense": "mathematics: map f such that whenever g composed with f equals h composed with f, then g=h",
      "tags": [
        "masculine"
      ],
      "word": "эпиморфизм"
    }
  ],
  "word": "epimorphism"
}