"converse" meaning in Anglais

See converse in All languages combined, or Wiktionary

Adjective

IPA: \ˈkɒnvɜːs\, \kənˈvɛːs\, kənˈvɝs, \ˈkɒnvɜːs\, ˈkɑnvɝs Audio: En-us-converse.ogg , LL-Q1860 (eng)-Mélange a trois-converse.wav , LL-Q1860 (eng)-Vealhurl-converse (noun).wav
  1. Opposé, inverse.
    Sense id: fr-converse-en-adj-FNrg~Lxg
  2. Réciproque.
    Sense id: fr-converse-en-adj-D1uATqb~ Categories (other): Lexique en anglais de la logique Topics: logic
The following are not (yet) sense-disambiguated
Derived forms: conversely

Noun

IPA: \ˈkɒnvɜːs\, \kənˈvɛːs\, kənˈvɝs, \ˈkɒnvɜːs\, ˈkɑnvɝs Audio: En-us-converse.ogg , LL-Q1860 (eng)-Mélange a trois-converse.wav , LL-Q1860 (eng)-Vealhurl-converse (noun).wav Forms: converses [plural]
  1. Opposé, inverse.
    Sense id: fr-converse-en-noun-FNrg~Lxg
  2. Réciproque.
    Sense id: fr-converse-en-noun-D1uATqb~ Categories (other): Lexique en anglais de la logique Topics: logic
The following are not (yet) sense-disambiguated
Synonyms: talk

Noun

IPA: \kənˈvɛːs\, \kənˈvɛːs\, kənˈvɝs, \ˈkɒnvɜːs\, ˈkɑnvɝs Audio: En-us-converse.ogg , LL-Q1860 (eng)-Mélange a trois-converse.wav , LL-Q1860 (eng)-Vealhurl-converse (noun).wav Forms: converses [plural]
  1. ou Discours familier, conversation, discussion. Tags: archaic, poetic
    Sense id: fr-converse-en-noun-5zWwztFQ Categories (other): Termes archaïques en anglais, Termes poétiques en anglais
The following are not (yet) sense-disambiguated

Verb

IPA: \kənˈvɛːs\, \kənˈvɛːs\, kənˈvɝs, \ˈkɒnvɜːs\, ˈkɑnvɝs Audio: En-us-converse.ogg , LL-Q1860 (eng)-Mélange a trois-converse.wav , LL-Q1860 (eng)-Vealhurl-converse (noun).wav
  1. Converser.
    Sense id: fr-converse-en-verb-AI0XAlub
The following are not (yet) sense-disambiguated
Derived forms: conversation

Inflected forms

{
  "categories": [
    {
      "kind": "other",
      "name": "Adjectifs en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "conversely"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "adj",
  "pos_title": "Adjectif",
  "senses": [
    {
      "glosses": [
        "Opposé, inverse."
      ],
      "id": "fr-converse-en-adj-FNrg~Lxg"
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "Lexique en anglais de la logique",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Réciproque."
      ],
      "id": "fr-converse-en-adj-D1uATqb~",
      "topics": [
        "logic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Mélange a trois-converse.wav",
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      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.ogg",
      "raw_tags": [
        "Royaume-Uni (Sud de l'Angleterre)"
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      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Mélange a trois-converse.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-converse (noun).wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.ogg",
      "raw_tags": [
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      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-converse (noun).wav"
    }
  ],
  "word": "converse"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Mots en anglais issus d’un mot en ancien français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Noms communs en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "De l’ancien français converser, lui-même du latin conversare (« vivre, avoir des relations avec »)."
  ],
  "forms": [
    {
      "form": "converses",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Nom commun 1",
  "senses": [
    {
      "glosses": [
        "Opposé, inverse."
      ],
      "id": "fr-converse-en-noun-FNrg~Lxg"
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "Lexique en anglais de la logique",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Réciproque."
      ],
      "id": "fr-converse-en-noun-D1uATqb~",
      "topics": [
        "logic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Mélange a trois-converse.wav",
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    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-converse (noun).wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.ogg",
      "raw_tags": [
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      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-converse (noun).wav"
    }
  ],
  "synonyms": [
    {
      "word": "talk"
    }
  ],
  "word": "converse"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Mots en anglais issus d’un mot en latin",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Noms communs en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "Du latin conversus (« retourné »), participe parfait de converto (« se retourner »)."
  ],
  "forms": [
    {
      "form": "converses",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Nom commun 2",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Termes archaïques en anglais",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Termes poétiques en anglais",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "ou Discours familier, conversation, discussion."
      ],
      "id": "fr-converse-en-noun-5zWwztFQ",
      "tags": [
        "archaic",
        "poetic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
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    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-converse (noun).wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.mp3",
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      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-converse (noun).wav"
    }
  ],
  "word": "converse"
}

{
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      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Verbes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Verbes intransitifs en anglais",
      "parents": [],
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    },
    {
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      "name": "Anglais",
      "orig": "anglais",
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    }
  ],
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      "word": "conversation"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "verb",
  "pos_title": "Verbe",
  "senses": [
    {
      "glosses": [
        "Converser."
      ],
      "id": "fr-converse-en-verb-AI0XAlub"
    }
  ],
  "sounds": [
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
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      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
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      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.ogg",
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    }
  ],
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    "intransitive"
  ],
  "word": "converse"
}
{
  "categories": [
    "Adjectifs en anglais",
    "Lemmes en anglais",
    "anglais"
  ],
  "derived": [
    {
      "word": "conversely"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "adj",
  "pos_title": "Adjectif",
  "senses": [
    {
      "glosses": [
        "Opposé, inverse."
      ]
    },
    {
      "categories": [
        "Lexique en anglais de la logique"
      ],
      "glosses": [
        "Réciproque."
      ],
      "topics": [
        "logic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
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      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.ogg",
      "raw_tags": [
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    },
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      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.ogg",
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      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-converse (noun).wav"
    }
  ],
  "word": "converse"
}

{
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    "Mots en anglais issus d’un mot en ancien français",
    "Noms communs en anglais",
    "anglais"
  ],
  "etymology_texts": [
    "De l’ancien français converser, lui-même du latin conversare (« vivre, avoir des relations avec »)."
  ],
  "forms": [
    {
      "form": "converses",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Nom commun 1",
  "senses": [
    {
      "glosses": [
        "Opposé, inverse."
      ]
    },
    {
      "categories": [
        "Lexique en anglais de la logique"
      ],
      "glosses": [
        "Réciproque."
      ],
      "topics": [
        "logic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
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      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
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      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.ogg",
      "raw_tags": [
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Mélange a trois-converse.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-converse (noun).wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.ogg",
      "raw_tags": [
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-converse (noun).wav"
    }
  ],
  "synonyms": [
    {
      "word": "talk"
    }
  ],
  "word": "converse"
}

{
  "categories": [
    "Lemmes en anglais",
    "Mots en anglais issus d’un mot en latin",
    "Noms communs en anglais",
    "anglais"
  ],
  "etymology_texts": [
    "Du latin conversus (« retourné »), participe parfait de converto (« se retourner »)."
  ],
  "forms": [
    {
      "form": "converses",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Nom commun 2",
  "senses": [
    {
      "categories": [
        "Termes archaïques en anglais",
        "Termes poétiques en anglais"
      ],
      "glosses": [
        "ou Discours familier, conversation, discussion."
      ],
      "tags": [
        "archaic",
        "poetic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Mélange a trois-converse.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.ogg",
      "raw_tags": [
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Mélange a trois-converse.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-converse (noun).wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.ogg",
      "raw_tags": [
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-converse (noun).wav"
    }
  ],
  "word": "converse"
}

{
  "categories": [
    "Lemmes en anglais",
    "Verbes en anglais",
    "Verbes intransitifs en anglais",
    "anglais"
  ],
  "derived": [
    {
      "word": "conversation"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "verb",
  "pos_title": "Verbe",
  "senses": [
    {
      "glosses": [
        "Converser."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "ipa": "\\kənˈvɛːs\\"
    },
    {
      "audio": "En-us-converse.ogg",
      "ipa": "kənˈvɝs",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d7/En-us-converse.ogg/En-us-converse.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-converse.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈkɒnvɜːs\\"
    },
    {
      "ipa": "ˈkɑnvɝs",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Mélange a trois-converse.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/LL-Q1860_(eng)-Mélange_a_trois-converse.wav/LL-Q1860_(eng)-Mélange_a_trois-converse.wav.ogg",
      "raw_tags": [
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Mélange a trois-converse.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-converse (noun).wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/40/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav/LL-Q1860_(eng)-Vealhurl-converse_(noun).wav.ogg",
      "raw_tags": [
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-converse (noun).wav"
    }
  ],
  "tags": [
    "intransitive"
  ],
  "word": "converse"
}

Download raw JSONL data for converse meaning in Anglais (7.9kB)


This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2025-01-10 from the frwiktionary dump dated 2025-01-01 using wiktextract (df33d17 and 4ed51a5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.