"superpartient" meaning in English

{
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        "3": "superpartiens"
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      "expansion": "Learned borrowing from Latin superpartiens",
      "name": "lbor"
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    {
      "args": {
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    {
      "args": {
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      "expansion": "participle",
      "name": "glossary"
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  ],
  "etymology_text": "Learned borrowing from Latin superpartiens, from super (“over”) + partiens, the past participle of partire (“to divide”).",
  "head_templates": [
    {
      "args": {
        "1": "-"
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      "expansion": "superpartient (not comparable)",
      "name": "en-adj"
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  "lang": "English",
  "lang_code": "en",
  "pos": "adj",
  "senses": [
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          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [
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          "name": "Mathematics",
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      "examples": [
        {
          "ref": "1734, Isaac Barrow, “Lecture XIX. Of the Species and Differences of Geometrical Reason.”, in John Kirkby, transl., The Usefulness of Mathematical Learning Explained and Demonstrated: Being Mathematical Lectures Read in the Publick Schools at the University of Cambridge. […], London: […] Stephen Austen, […], →OCLC, page 362:",
          "text": "[W]e proceed to a Superpartient Reaſon, which is when the Antecedent exceeds the Conſequent by ſome Aliquot Parts more than one, whence the Name: […] Thus 9 is ſaid to be in a Superpartient Reaſon to 7, because 9 exceeds 7 by two 7th Parts.",
          "type": "quote"
        }
      ],
      "glosses": [
        "Being or relating to a ratio where the larger value exceeds the smaller by more than one unit, as in 3 to 5."
      ],
      "id": "en-superpartient-en-adj-73Z5ZiJ5",
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      "raw_glosses": [
        "(mathematics, archaic) Being or relating to a ratio where the larger value exceeds the smaller by more than one unit, as in 3 to 5."
      ],
      "tags": [
        "archaic",
        "not-comparable"
      ],
      "topics": [
        "mathematics",
        "sciences"
      ]
    }
  ],
  "word": "superpartient"
}

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        "3": "superpartiens"
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      "expansion": "Learned borrowing from Latin superpartiens",
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      "expansion": "participle",
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  "etymology_text": "Learned borrowing from Latin superpartiens, from super (“over”) + partiens, the past participle of partire (“to divide”).",
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  "lang_code": "en",
  "pos": "adj",
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          "ref": "1734, Isaac Barrow, “Lecture XIX. Of the Species and Differences of Geometrical Reason.”, in John Kirkby, transl., The Usefulness of Mathematical Learning Explained and Demonstrated: Being Mathematical Lectures Read in the Publick Schools at the University of Cambridge. […], London: […] Stephen Austen, […], →OCLC, page 362:",
          "text": "[W]e proceed to a Superpartient Reaſon, which is when the Antecedent exceeds the Conſequent by ſome Aliquot Parts more than one, whence the Name: […] Thus 9 is ſaid to be in a Superpartient Reaſon to 7, because 9 exceeds 7 by two 7th Parts.",
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        "Being or relating to a ratio where the larger value exceeds the smaller by more than one unit, as in 3 to 5."
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        "(mathematics, archaic) Being or relating to a ratio where the larger value exceeds the smaller by more than one unit, as in 3 to 5."
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  "word": "superpartient"
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