"bragd" meaning in All languages combined

See bragd on Wiktionary

Noun [瑞典語]

Etymology: 繼承自古瑞典語 bragþ,來自或與古諾爾斯語 bráðr相關,來自原始日耳曼語 *brēþaz (“快速”)。
  1. 非凡的表現或行為
    Sense id: zh-bragd-sv-noun-QIPmCOVx
  2. 英勇事蹟
    Sense id: zh-bragd-sv-noun-kduLpgo6
The following are not (yet) sense-disambiguated
Synonyms: hjältebragd, hjältedåd, stordåd, bedrift Related terms: bragdguld, bragdman, bragdmedalj

Verb [瑞典語]

Etymology: 繼承自古瑞典語 bragþ,來自或與古諾爾斯語 bráðr相關,來自原始日耳曼語 *brēþaz (“快速”)。
  1. bringa 的過去時分詞 Tags: form-of Form of: bringa
    Sense id: zh-bragd-sv-verb-qwg3mEmM Categories (other): 瑞典語過去分詞
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古瑞典語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古諾爾斯語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古瑞典語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古諾爾斯語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語通性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "繼承自古瑞典語 bragþ,來自或與古諾爾斯語 bráðr相關,來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "notes": [
    "最常見的是現代令人印象深刻的體育表演等。"
  ],
  "pos": "noun",
  "related": [
    {
      "word": "bragdguld"
    },
    {
      "word": "bragdman"
    },
    {
      "word": "bragdmedalj"
    }
  ],
  "senses": [
    {
      "glosses": [
        "非凡的表現或行為"
      ],
      "id": "zh-bragd-sv-noun-QIPmCOVx"
    },
    {
      "glosses": [
        "英勇事蹟"
      ],
      "id": "zh-bragd-sv-noun-kduLpgo6"
    }
  ],
  "synonyms": [
    {
      "word": "hjältebragd"
    },
    {
      "word": "hjältedåd"
    },
    {
      "word": "stordåd"
    },
    {
      "word": "bedrift"
    }
  ],
  "tags": [
    "common"
  ],
  "word": "bragd"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古瑞典語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古諾爾斯語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古瑞典語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古諾爾斯語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語過去分詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語非詞元形式",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "繼承自古瑞典語 bragþ,來自或與古諾爾斯語 bráðr相關,來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "pos": "verb",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "瑞典語過去分詞",
          "parents": [],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "word": "bringa"
        }
      ],
      "glosses": [
        "bringa 的過去時分詞"
      ],
      "id": "zh-bragd-sv-verb-qwg3mEmM",
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "bragd"
}
{
  "categories": [
    "有1個詞條的頁面",
    "派生自原始日耳曼語的瑞典語詞",
    "派生自古瑞典語的瑞典語詞",
    "派生自古諾爾斯語的瑞典語詞",
    "源自原始日耳曼語的瑞典語繼承詞",
    "源自古瑞典語的瑞典語繼承詞",
    "源自古諾爾斯語的瑞典語繼承詞",
    "瑞典語名詞",
    "瑞典語詞元",
    "瑞典語通性名詞"
  ],
  "etymology_text": "繼承自古瑞典語 bragþ,來自或與古諾爾斯語 bráðr相關,來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "notes": [
    "最常見的是現代令人印象深刻的體育表演等。"
  ],
  "pos": "noun",
  "related": [
    {
      "word": "bragdguld"
    },
    {
      "word": "bragdman"
    },
    {
      "word": "bragdmedalj"
    }
  ],
  "senses": [
    {
      "glosses": [
        "非凡的表現或行為"
      ]
    },
    {
      "glosses": [
        "英勇事蹟"
      ]
    }
  ],
  "synonyms": [
    {
      "word": "hjältebragd"
    },
    {
      "word": "hjältedåd"
    },
    {
      "word": "stordåd"
    },
    {
      "word": "bedrift"
    }
  ],
  "tags": [
    "common"
  ],
  "word": "bragd"
}

{
  "categories": [
    "有1個詞條的頁面",
    "派生自原始日耳曼語的瑞典語詞",
    "派生自古瑞典語的瑞典語詞",
    "派生自古諾爾斯語的瑞典語詞",
    "源自原始日耳曼語的瑞典語繼承詞",
    "源自古瑞典語的瑞典語繼承詞",
    "源自古諾爾斯語的瑞典語繼承詞",
    "瑞典語過去分詞",
    "瑞典語非詞元形式"
  ],
  "etymology_text": "繼承自古瑞典語 bragþ,來自或與古諾爾斯語 bráðr相關,來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "pos": "verb",
  "senses": [
    {
      "categories": [
        "瑞典語過去分詞"
      ],
      "form_of": [
        {
          "word": "bringa"
        }
      ],
      "glosses": [
        "bringa 的過去時分詞"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "bragd"
}

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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-03 from the zhwiktionary dump dated 2024-10-20 using wiktextract (d6bf104 and a5af179). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.