"bragd" meaning in 瑞典語

{
  "categories": [
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古瑞典語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古諾爾斯語的瑞典語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古瑞典語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古諾爾斯語的瑞典語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語通性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "繼承自古瑞典語 bragþ，來自或與古諾爾斯語 bráðr相關，來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "notes": [
    "最常見的是現代令人印象深刻的體育表演等。"
  ],
  "pos": "noun",
  "related": [
    {
      "word": "bragdguld"
    },
    {
      "word": "bragdman"
    },
    {
      "word": "bragdmedalj"
    }
  ],
  "senses": [
    {
      "glosses": [
        "非凡的表現或行為"
      ],
      "id": "zh-bragd-sv-noun-QIPmCOVx"
    },
    {
      "glosses": [
        "英勇事蹟"
      ],
      "id": "zh-bragd-sv-noun-kduLpgo6"
    }
  ],
  "synonyms": [
    {
      "word": "hjältebragd"
    },
    {
      "word": "hjältedåd"
    },
    {
      "word": "stordåd"
    },
    {
      "word": "bedrift"
    }
  ],
  "tags": [
    "common"
  ],
  "word": "bragd"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "瑞典語過去分詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語非詞元形式",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "繼承自古瑞典語 bragþ，來自或與古諾爾斯語 bráðr相關，來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "pos": "verb",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "瑞典語過去分詞",
          "parents": [],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "word": "bringa"
        }
      ],
      "glosses": [
        "bringa 的過去時分詞"
      ],
      "id": "zh-bragd-sv-verb-qwg3mEmM",
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "bragd"
}

{
  "categories": [
    "派生自原始日耳曼語的瑞典語詞",
    "派生自古瑞典語的瑞典語詞",
    "派生自古諾爾斯語的瑞典語詞",
    "源自原始日耳曼語的瑞典語繼承詞",
    "源自古瑞典語的瑞典語繼承詞",
    "源自古諾爾斯語的瑞典語繼承詞",
    "瑞典語名詞",
    "瑞典語詞元",
    "瑞典語通性名詞"
  ],
  "etymology_text": "繼承自古瑞典語 bragþ，來自或與古諾爾斯語 bráðr相關，來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "notes": [
    "最常見的是現代令人印象深刻的體育表演等。"
  ],
  "pos": "noun",
  "related": [
    {
      "word": "bragdguld"
    },
    {
      "word": "bragdman"
    },
    {
      "word": "bragdmedalj"
    }
  ],
  "senses": [
    {
      "glosses": [
        "非凡的表現或行為"
      ]
    },
    {
      "glosses": [
        "英勇事蹟"
      ]
    }
  ],
  "synonyms": [
    {
      "word": "hjältebragd"
    },
    {
      "word": "hjältedåd"
    },
    {
      "word": "stordåd"
    },
    {
      "word": "bedrift"
    }
  ],
  "tags": [
    "common"
  ],
  "word": "bragd"
}

{
  "categories": [
    "瑞典語過去分詞",
    "瑞典語非詞元形式"
  ],
  "etymology_text": "繼承自古瑞典語 bragþ，來自或與古諾爾斯語 bráðr相關，來自原始日耳曼語 *brēþaz (“快速”)。",
  "lang": "瑞典語",
  "lang_code": "sv",
  "pos": "verb",
  "senses": [
    {
      "categories": [
        "瑞典語過去分詞"
      ],
      "form_of": [
        {
          "word": "bringa"
        }
      ],
      "glosses": [
        "bringa 的過去時分詞"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "bragd"
}