"abrogator" meaning in All languages combined

See abrogator on Wiktionary

Verb [拉丁語]

  1. abrogō 的第二人稱/第三人稱單數將來時被動態命令式 Tags: form-of Form of: abrogō
    Sense id: zh-abrogator-la-verb-180gkQqo
The following are not (yet) sense-disambiguated

Noun [英語]

IPA: /ˈæb.ɹəˌɡeɪ.tɚ/ Forms: abrogators [plural]
Etymology: abrogate + -or
  1. 取消者,廢除者(首次記錄於16世紀晚期。)
    Sense id: zh-abrogator-en-noun-2HqwwKGU Categories (other): 缺少作者和編輯參數的參考模板
The following are not (yet) sense-disambiguated

Inflected forms

{
  "categories": [
    {
      "kind": "other",
      "name": "含有後綴-or的英語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "abrogate + -or",
  "forms": [
    {
      "form": "abrogators",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "缺少作者和編輯參數的參考模板",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "取消者,廢除者(首次記錄於16世紀晚期。)"
      ],
      "id": "zh-abrogator-en-noun-2HqwwKGU"
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈæb.ɹəˌɡeɪ.tɚ/",
      "raw_tags": [
        "美國"
      ]
    }
  ],
  "word": "abrogator"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "拉丁語動詞變位形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語非詞元形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "abrogō"
        }
      ],
      "glosses": [
        "abrogō 的第二人稱/第三人稱單數將來時被動態命令式"
      ],
      "id": "zh-abrogator-la-verb-180gkQqo",
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "abrogator"
}
{
  "categories": [
    "拉丁語動詞變位形式",
    "拉丁語非詞元形式",
    "有2個詞條的頁面",
    "有詞條的頁面"
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "abrogō"
        }
      ],
      "glosses": [
        "abrogō 的第二人稱/第三人稱單數將來時被動態命令式"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "abrogator"
}

{
  "categories": [
    "含有後綴-or的英語詞",
    "有2個詞條的頁面",
    "有詞條的頁面",
    "英語可數名詞",
    "英語名詞",
    "英語詞元"
  ],
  "etymology_text": "abrogate + -or",
  "forms": [
    {
      "form": "abrogators",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "缺少作者和編輯參數的參考模板"
      ],
      "glosses": [
        "取消者,廢除者(首次記錄於16世紀晚期。)"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈæb.ɹəˌɡeɪ.tɚ/",
      "raw_tags": [
        "美國"
      ]
    }
  ],
  "word": "abrogator"
}

Download raw JSONL data for abrogator meaning in All languages combined (0.9kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.