"abrogator" meaning in 英語

{
  "categories": [
    {
      "kind": "other",
      "name": "含有後綴-or的英語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "abrogate + -or",
  "forms": [
    {
      "form": "abrogators",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "缺少作者和編輯參數的參考模板",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "取消者，廢除者（首次記錄於16世紀晚期。）"
      ],
      "id": "zh-abrogator-en-noun-2HqwwKGU"
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈæb.ɹəˌɡeɪ.tɚ/",
      "raw_tags": [
        "美國"
      ]
    }
  ],
  "word": "abrogator"
}

{
  "categories": [
    "含有後綴-or的英語詞",
    "有2個詞條的頁面",
    "有詞條的頁面",
    "英語可數名詞",
    "英語名詞",
    "英語詞元"
  ],
  "etymology_text": "abrogate + -or",
  "forms": [
    {
      "form": "abrogators",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "categories": [
        "缺少作者和編輯參數的參考模板"
      ],
      "glosses": [
        "取消者，廢除者（首次記錄於16世紀晚期。）"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈæb.ɹəˌɡeɪ.tɚ/",
      "raw_tags": [
        "美國"
      ]
    }
  ],
  "word": "abrogator"
}