"poate" meaning in 羅馬尼亞語

See poate in All languages combined, or Wiktionary

Adverb

IPA: /ˈpo̯ate/
Etymology: 源自 putea (“能”) 的第三人稱單數現在時。對照西班牙語 puede que。
  1. 可能
    Sense id: zh-poate-ro-adv-s9EIU7fB Categories (other): 有使用例的羅馬尼亞語詞
The following are not (yet) sense-disambiguated
Derived forms: fără doar și poate, peste poate

Verb

IPA: /ˈpo̯ate/
Etymology: 源自 putea (“能”) 的第三人稱單數現在時。對照西班牙語 puede que。
  1. putea 的第三人稱單數現在時直陳式 Tags: form-of Form of: putea
    Sense id: zh-poate-ro-verb--12R7sNP
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語副词",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "fără doar și poate"
    },
    {
      "word": "peste poate"
    }
  ],
  "etymology_text": "源自 putea (“能”) 的第三人稱單數現在時。對照西班牙語 puede que。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "notes": [
    "引出的句子可加 că 也可不加。但如果不是完整的句子,只跟著 da 或 nu(“可能是/可能不是”),則必須加 că。"
  ],
  "pos": "adv",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "有使用例的羅馬尼亞語詞",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "text": "Poate că nu-și va aminti.",
          "translation": "他可能不會記得的。"
        }
      ],
      "glosses": [
        "可能"
      ],
      "id": "zh-poate-ro-adv-s9EIU7fB"
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈpo̯ate/"
    }
  ],
  "word": "poate"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語動詞變位形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語非詞元形式",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自 putea (“能”) 的第三人稱單數現在時。對照西班牙語 puede que。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "putea"
        }
      ],
      "glosses": [
        "putea 的第三人稱單數現在時直陳式"
      ],
      "id": "zh-poate-ro-verb--12R7sNP",
      "tags": [
        "form-of"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈpo̯ate/"
    }
  ],
  "word": "poate"
}
{
  "categories": [
    "有1個詞條的頁面",
    "羅馬尼亞語副词",
    "羅馬尼亞語詞元"
  ],
  "derived": [
    {
      "word": "fără doar și poate"
    },
    {
      "word": "peste poate"
    }
  ],
  "etymology_text": "源自 putea (“能”) 的第三人稱單數現在時。對照西班牙語 puede que。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "notes": [
    "引出的句子可加 că 也可不加。但如果不是完整的句子,只跟著 da 或 nu(“可能是/可能不是”),則必須加 că。"
  ],
  "pos": "adv",
  "senses": [
    {
      "categories": [
        "有使用例的羅馬尼亞語詞"
      ],
      "examples": [
        {
          "text": "Poate că nu-și va aminti.",
          "translation": "他可能不會記得的。"
        }
      ],
      "glosses": [
        "可能"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈpo̯ate/"
    }
  ],
  "word": "poate"
}

{
  "categories": [
    "有1個詞條的頁面",
    "羅馬尼亞語動詞變位形式",
    "羅馬尼亞語非詞元形式"
  ],
  "etymology_text": "源自 putea (“能”) 的第三人稱單數現在時。對照西班牙語 puede que。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "putea"
        }
      ],
      "glosses": [
        "putea 的第三人稱單數現在時直陳式"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈpo̯ate/"
    }
  ],
  "word": "poate"
}

Download raw JSONL data for poate meaning in 羅馬尼亞語 (1.2kB)


This page is a part of the kaikki.org machine-readable 羅馬尼亞語 dictionary. This dictionary is based on structured data extracted on 2024-10-01 from the zhwiktionary dump dated 2024-09-20 using wiktextract (3fd8a50 and 59b8406). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.