"abracadabra" meaning in 意大利语

See abracadabra in All languages combined, or Wiktionary

Interjection

Etymology: 非同化借詞,源自古希臘語 ἀβρακαδάβρα (abrakadábra)。
  1. 阿布拉卡达布拉 (魔咒,魔术或幻术表演时使用)
    Sense id: zh-abracadabra-it-intj--CA0UpAa
The following are not (yet) sense-disambiguated

Noun

Etymology: 非同化借詞,源自古希臘語 ἀβρακαδάβρα (abrakadábra)。
  1. 胡言乱语;深奥难懂的话
    Sense id: zh-abracadabra-it-noun-jLDp~wMZ
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "意大利語可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "意大利語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "意大利語無屈折名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "意大利語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "意大利語陽性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有7個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有不規則複數的意大利語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的意大利語借詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的意大利語非同化借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "非同化借詞,源自古希臘語 ἀβρακαδάβρα (abrakadábra)。",
  "lang": "意大利语",
  "lang_code": "it",
  "pos": "noun",
  "pos_title": "名词",
  "senses": [
    {
      "glosses": [
        "胡言乱语;深奥难懂的话"
      ],
      "id": "zh-abracadabra-it-noun-jLDp~wMZ"
    }
  ],
  "tags": [
    "indeclinable",
    "masculine"
  ],
  "word": "abracadabra"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "意大利語感嘆詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "意大利語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有7個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的意大利語借詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的意大利語非同化借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "非同化借詞,源自古希臘語 ἀβρακαδάβρα (abrakadábra)。",
  "lang": "意大利语",
  "lang_code": "it",
  "pos": "intj",
  "pos_title": "叹词",
  "senses": [
    {
      "glosses": [
        "阿布拉卡达布拉 (魔咒,魔术或幻术表演时使用)"
      ],
      "id": "zh-abracadabra-it-intj--CA0UpAa"
    }
  ],
  "word": "abracadabra"
}
{
  "categories": [
    "意大利語可數名詞",
    "意大利語名詞",
    "意大利語無屈折名詞",
    "意大利語詞元",
    "意大利語陽性名詞",
    "有7個詞條的頁面",
    "有不規則複數的意大利語名詞",
    "有詞條的頁面",
    "派生自古希臘語的意大利語詞",
    "源自古希臘語的意大利語借詞",
    "源自古希臘語的意大利語非同化借詞"
  ],
  "etymology_text": "非同化借詞,源自古希臘語 ἀβρακαδάβρα (abrakadábra)。",
  "lang": "意大利语",
  "lang_code": "it",
  "pos": "noun",
  "pos_title": "名词",
  "senses": [
    {
      "glosses": [
        "胡言乱语;深奥难懂的话"
      ]
    }
  ],
  "tags": [
    "indeclinable",
    "masculine"
  ],
  "word": "abracadabra"
}

{
  "categories": [
    "意大利語感嘆詞",
    "意大利語詞元",
    "有7個詞條的頁面",
    "有詞條的頁面",
    "派生自古希臘語的意大利語詞",
    "源自古希臘語的意大利語借詞",
    "源自古希臘語的意大利語非同化借詞"
  ],
  "etymology_text": "非同化借詞,源自古希臘語 ἀβρακαδάβρα (abrakadábra)。",
  "lang": "意大利语",
  "lang_code": "it",
  "pos": "intj",
  "pos_title": "叹词",
  "senses": [
    {
      "glosses": [
        "阿布拉卡达布拉 (魔咒,魔术或幻术表演时使用)"
      ]
    }
  ],
  "word": "abracadabra"
}

Download raw JSONL data for abracadabra meaning in 意大利语 (1.2kB)


This page is a part of the kaikki.org machine-readable 意大利语 dictionary. This dictionary is based on structured data extracted on 2025-08-06 from the zhwiktionary dump dated 2025-08-01 using wiktextract (8b3c49c and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.