"aguzzino" meaning in 意大利語

See aguzzino in All languages combined, or Wiktionary

Noun

Forms: aguzzini [plural], aguzzina [feminine]
Etymology: 可能經由西西里語和那不勒斯語傳入,源自加泰羅尼亞語 algutzir(及其異體)或西班牙語 alguacil (“撒拉森的執達吏”),源自阿拉伯語 الوَزِير (al-wazīr,“官員”)。visir (“維齊爾”) 的同源對似詞。
  1. 獄卒
    Sense id: zh-aguzzino-it-noun-1HdCm-DW
  2. 拷打者,虐待者 Tags: broadly
    Sense id: zh-aguzzino-it-noun-u9aKJsBl
The following are not (yet) sense-disambiguated
Synonyms (拷打者,虐待者): persecutore, torturatore, vessatore Synonyms (獄卒): carceriere

Verb

  1. aguzzare 的屈折:
    第三人稱複數現在時虛擬式
    Tags: form-of Form of: aguzzare
    Sense id: zh-aguzzino-it-verb-f4zZa5Yv
  2. aguzzare 的屈折:
    第三人稱複數命令式
    Tags: form-of Form of: aguzzare
    Sense id: zh-aguzzino-it-verb-K2SGpabu
The following are not (yet) sense-disambiguated

Inflected forms

Alternative forms

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      "kind": "other",
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      "parents": [],
      "source": "w"
    },
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      "kind": "other",
      "name": "意大利語可數名詞",
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      "kind": "other",
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    {
      "kind": "other",
      "name": "有1個詞條的頁面",
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      "source": "w"
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      "name": "有詞條的頁面",
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      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自加泰羅尼亞語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自西班牙語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自西西里語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自那不勒斯語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自阿拉伯語的意大利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自加泰羅尼亞語的意大利語借詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自西班牙語的意大利語借詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自西西里語的意大利語借詞",
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      "source": "w"
    },
    {
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      "name": "源自那不勒斯語的意大利語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "descendants": [
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "argousin"
    }
  ],
  "etymology_text": "可能經由西西里語和那不勒斯語傳入,源自加泰羅尼亞語 algutzir(及其異體)或西班牙語 alguacil (“撒拉森的執達吏”),源自阿拉伯語 الوَزِير (al-wazīr,“官員”)。visir (“維齊爾”) 的同源對似詞。",
  "forms": [
    {
      "form": "aguzzini",
      "tags": [
        "plural"
      ]
    },
    {
      "form": "aguzzina",
      "tags": [
        "feminine"
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  "lang": "意大利語",
  "lang_code": "it",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "glosses": [
        "獄卒"
      ],
      "id": "zh-aguzzino-it-noun-1HdCm-DW"
    },
    {
      "glosses": [
        "拷打者,虐待者"
      ],
      "id": "zh-aguzzino-it-noun-u9aKJsBl",
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        "broadly"
      ]
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  "synonyms": [
    {
      "sense": "獄卒",
      "word": "carceriere"
    },
    {
      "sense": "拷打者,虐待者",
      "word": "persecutore"
    },
    {
      "sense": "拷打者,虐待者",
      "word": "torturatore"
    },
    {
      "sense": "拷打者,虐待者",
      "word": "vessatore"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "aguzzino"
}

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      "name": "意大利語動詞變位形式",
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      "source": "w"
    },
    {
      "kind": "other",
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      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
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    },
    {
      "kind": "other",
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      "source": "w"
    }
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        {
          "word": "aguzzare"
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      "glosses": [
        "aguzzare 的屈折:",
        "第三人稱複數現在時虛擬式"
      ],
      "id": "zh-aguzzino-it-verb-f4zZa5Yv",
      "tags": [
        "form-of"
      ]
    },
    {
      "form_of": [
        {
          "word": "aguzzare"
        }
      ],
      "glosses": [
        "aguzzare 的屈折:",
        "第三人稱複數命令式"
      ],
      "id": "zh-aguzzino-it-verb-K2SGpabu",
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "aguzzino"
}
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    "意大利語可數名詞",
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    "意大利語詞元",
    "意大利語陽性名詞",
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自加泰羅尼亞語的意大利語詞",
    "派生自西班牙語的意大利語詞",
    "派生自西西里語的意大利語詞",
    "派生自那不勒斯語的意大利語詞",
    "派生自阿拉伯語的意大利語詞",
    "源自加泰羅尼亞語的意大利語借詞",
    "源自西班牙語的意大利語借詞",
    "源自西西里語的意大利語借詞",
    "源自那不勒斯語的意大利語借詞"
  ],
  "descendants": [
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "argousin"
    }
  ],
  "etymology_text": "可能經由西西里語和那不勒斯語傳入,源自加泰羅尼亞語 algutzir(及其異體)或西班牙語 alguacil (“撒拉森的執達吏”),源自阿拉伯語 الوَزِير (al-wazīr,“官員”)。visir (“維齊爾”) 的同源對似詞。",
  "forms": [
    {
      "form": "aguzzini",
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        "plural"
      ]
    },
    {
      "form": "aguzzina",
      "tags": [
        "feminine"
      ]
    }
  ],
  "lang": "意大利語",
  "lang_code": "it",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "glosses": [
        "獄卒"
      ]
    },
    {
      "glosses": [
        "拷打者,虐待者"
      ],
      "tags": [
        "broadly"
      ]
    }
  ],
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    {
      "sense": "獄卒",
      "word": "carceriere"
    },
    {
      "sense": "拷打者,虐待者",
      "word": "persecutore"
    },
    {
      "sense": "拷打者,虐待者",
      "word": "torturatore"
    },
    {
      "sense": "拷打者,虐待者",
      "word": "vessatore"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "aguzzino"
}

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    "意大利語動詞變位形式",
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    "有1個詞條的頁面",
    "有詞條的頁面"
  ],
  "lang": "意大利語",
  "lang_code": "it",
  "pos": "verb",
  "pos_title": "動詞",
  "senses": [
    {
      "form_of": [
        {
          "word": "aguzzare"
        }
      ],
      "glosses": [
        "aguzzare 的屈折:",
        "第三人稱複數現在時虛擬式"
      ],
      "tags": [
        "form-of"
      ]
    },
    {
      "form_of": [
        {
          "word": "aguzzare"
        }
      ],
      "glosses": [
        "aguzzare 的屈折:",
        "第三人稱複數命令式"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "aguzzino"
}

Download raw JSONL data for aguzzino meaning in 意大利語 (2.0kB)


This page is a part of the kaikki.org machine-readable 意大利語 dictionary. This dictionary is based on structured data extracted on 2025-08-06 from the zhwiktionary dump dated 2025-08-01 using wiktextract (8b3c49c and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.