See gourmet in All languages combined, or Wiktionary
{
"forms": [
{
"form": "gourmet",
"tags": [
"positive"
]
},
{
"form": "–",
"tags": [
"comparative"
]
},
{
"form": "–",
"tags": [
"superlative"
]
}
],
"head_templates": [
{
"expansion": "[POS TABLE]",
"name": "adj"
}
],
"hyphenation": "gourmet",
"lang": "English",
"lang_code": "en",
"pos": "adj",
"senses": [
{
"glosses": [
"If a food is gourmet, it is of superior quality."
],
"id": "simple-gourmet-en-adj-LJPhACFx"
}
],
"sounds": [
{
"ipa": "/ɡʊrˈmeɪ/",
"tags": [
"US"
]
},
{
"ipa": "/ˈɡʊəmeɪ/",
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet2.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
}
],
"word": "gourmet"
}
{
"forms": [
{
"form": "gourmet",
"tags": [
"singular"
]
},
{
"form": "gourmets",
"tags": [
"plural"
]
}
],
"head_templates": [
{
"expansion": "[POS TABLE]",
"name": "noun"
}
],
"hyphenation": "gourmet",
"lang": "English",
"lang_code": "en",
"pos": "noun",
"senses": [
{
"categories": [],
"glosses": [
"A gourmet is a connoisseur in food."
],
"id": "simple-gourmet-en-noun-1YqjDAkO",
"raw_tags": [
"countable"
],
"synonyms": [
{
"word": "foodie"
}
]
}
],
"sounds": [
{
"ipa": "/ɡʊrˈmeɪ/",
"tags": [
"US"
]
},
{
"ipa": "/ˈɡʊəmeɪ/",
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet2.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
}
],
"word": "gourmet"
}
{
"forms": [
{
"form": "gourmet",
"tags": [
"positive"
]
},
{
"form": "–",
"tags": [
"comparative"
]
},
{
"form": "–",
"tags": [
"superlative"
]
}
],
"head_templates": [
{
"expansion": "[POS TABLE]",
"name": "adj"
}
],
"hyphenation": "gourmet",
"lang": "English",
"lang_code": "en",
"pos": "adj",
"senses": [
{
"glosses": [
"If a food is gourmet, it is of superior quality."
]
}
],
"sounds": [
{
"ipa": "/ɡʊrˈmeɪ/",
"tags": [
"US"
]
},
{
"ipa": "/ˈɡʊəmeɪ/",
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet2.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
}
],
"word": "gourmet"
}
{
"forms": [
{
"form": "gourmet",
"tags": [
"singular"
]
},
{
"form": "gourmets",
"tags": [
"plural"
]
}
],
"head_templates": [
{
"expansion": "[POS TABLE]",
"name": "noun"
}
],
"hyphenation": "gourmet",
"lang": "English",
"lang_code": "en",
"pos": "noun",
"senses": [
{
"categories": [
"Countable nouns"
],
"glosses": [
"A gourmet is a connoisseur in food."
],
"raw_tags": [
"countable"
],
"synonyms": [
{
"word": "foodie"
}
]
}
],
"sounds": [
{
"ipa": "/ɡʊrˈmeɪ/",
"tags": [
"US"
]
},
{
"ipa": "/ˈɡʊəmeɪ/",
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-gourmet2.wav",
"raw_tags": [
"Audio"
],
"tags": [
"UK"
]
}
],
"word": "gourmet"
}
Download raw JSONL data for gourmet meaning in English (1.3kB)
This page is a part of the kaikki.org machine-readable English dictionary. This dictionary is based on structured data extracted on 2025-01-08 from the simplewiktionary dump dated 2025-01-01 using wiktextract (9a96ef4 and 4ed51a5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.