See basis in All languages combined, or Wiktionary
{
"anagrams": [
{
"word": "absis"
},
{
"word": "bassi"
},
{
"word": "isbas"
}
],
"categories": [
{
"kind": "other",
"name": "Lemmes en anglais",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Mots en anglais issus d’un mot en grec ancien",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Mots en anglais issus d’un mot en latin",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Noms communs en anglais",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Anglais",
"orig": "anglais",
"parents": [],
"source": "w"
}
],
"derived": [
{
"word": "accrual basis"
},
{
"word": "basic"
},
{
"word": "basis point"
},
{
"word": "basis spline"
},
{
"word": "basis vector"
},
{
"word": "basiswise"
},
{
"word": "Bernstein basis polynomial"
},
{
"word": "cash basis"
},
{
"word": "cost basis"
},
{
"word": "eigenbasis"
},
{
"word": "fare basis"
},
{
"word": "Fourier basis"
},
{
"word": "Gröbner basis"
},
{
"word": "Hamel basis"
},
{
"word": "Hilbert's basis theorem"
},
{
"word": "normal basis"
},
{
"word": "on a case-by-case basis"
},
{
"word": "on a first-name basis"
},
{
"word": "on a need-to-know basis"
},
{
"word": "on an irregular basis"
},
{
"word": "on a regular basis"
},
{
"word": "on the basis of"
},
{
"word": "polynomial basis"
},
{
"word": "rational basis review"
},
{
"word": "Schauder basis"
},
{
"word": "subbasis"
},
{
"word": "tax basis"
}
],
"etymology_texts": [
"(c. 1570) Du latin basis (« base ») du grec ancien βάσις, básis."
],
"forms": [
{
"form": "bases",
"ipas": [
"\\ˈbeɪ.siːz\\"
],
"tags": [
"plural"
]
}
],
"lang": "Anglais",
"lang_code": "en",
"pos": "noun",
"pos_title": "Nom commun",
"related": [
{
"word": "base"
}
],
"senses": [
{
"categories": [
{
"kind": "other",
"name": "Wiktionnaire:Exemples manquants en anglais",
"parents": [],
"source": "w"
}
],
"glosses": [
"Base, point de départ."
],
"id": "fr-basis-en-noun-jnFHlHCU"
},
{
"categories": [
{
"kind": "other",
"name": "Wiktionnaire:Exemples manquants en anglais",
"parents": [],
"source": "w"
}
],
"glosses": [
"Ingrédient principal, base."
],
"id": "fr-basis-en-noun-CU5qlY31"
},
{
"categories": [
{
"kind": "other",
"name": "Wiktionnaire:Exemples manquants en anglais",
"parents": [],
"source": "w"
}
],
"glosses": [
"Régularité, fréquence."
],
"id": "fr-basis-en-noun-QklE74wU"
},
{
"categories": [
{
"kind": "other",
"name": "Lexique en anglais de l’algèbre linéaire",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Wiktionnaire:Exemples manquants en anglais",
"parents": [],
"source": "w"
}
],
"glosses": [
"Base."
],
"id": "fr-basis-en-noun-WBqHXJeY",
"topics": [
"mathematics"
]
}
],
"sounds": [
{
"ipa": "\\ˈbeɪ.sɪs\\"
},
{
"audio": "En-us-basis.ogg",
"ipa": "ˈbeɪ.sɪs",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/7/70/En-us-basis.ogg/En-us-basis.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-basis.ogg",
"raw_tags": [
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},
{
"audio": "LL-Q1860 (eng)-Back ache-basis.wav",
"ipa": "ˈbeɪ.sɪs",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/ee/LL-Q1860_(eng)-Back_ache-basis.wav/LL-Q1860_(eng)-Back_ache-basis.wav.mp3",
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}
],
"word": "basis"
}
{
"anagrams": [
{
"word": "absis"
},
{
"word": "bassi"
},
{
"word": "isbas"
}
],
"categories": [
"Lemmes en anglais",
"Mots en anglais issus d’un mot en grec ancien",
"Mots en anglais issus d’un mot en latin",
"Noms communs en anglais",
"anglais"
],
"derived": [
{
"word": "accrual basis"
},
{
"word": "basic"
},
{
"word": "basis point"
},
{
"word": "basis spline"
},
{
"word": "basis vector"
},
{
"word": "basiswise"
},
{
"word": "Bernstein basis polynomial"
},
{
"word": "cash basis"
},
{
"word": "cost basis"
},
{
"word": "eigenbasis"
},
{
"word": "fare basis"
},
{
"word": "Fourier basis"
},
{
"word": "Gröbner basis"
},
{
"word": "Hamel basis"
},
{
"word": "Hilbert's basis theorem"
},
{
"word": "normal basis"
},
{
"word": "on a case-by-case basis"
},
{
"word": "on a first-name basis"
},
{
"word": "on a need-to-know basis"
},
{
"word": "on an irregular basis"
},
{
"word": "on a regular basis"
},
{
"word": "on the basis of"
},
{
"word": "polynomial basis"
},
{
"word": "rational basis review"
},
{
"word": "Schauder basis"
},
{
"word": "subbasis"
},
{
"word": "tax basis"
}
],
"etymology_texts": [
"(c. 1570) Du latin basis (« base ») du grec ancien βάσις, básis."
],
"forms": [
{
"form": "bases",
"ipas": [
"\\ˈbeɪ.siːz\\"
],
"tags": [
"plural"
]
}
],
"lang": "Anglais",
"lang_code": "en",
"pos": "noun",
"pos_title": "Nom commun",
"related": [
{
"word": "base"
}
],
"senses": [
{
"categories": [
"Wiktionnaire:Exemples manquants en anglais"
],
"glosses": [
"Base, point de départ."
]
},
{
"categories": [
"Wiktionnaire:Exemples manquants en anglais"
],
"glosses": [
"Ingrédient principal, base."
]
},
{
"categories": [
"Wiktionnaire:Exemples manquants en anglais"
],
"glosses": [
"Régularité, fréquence."
]
},
{
"categories": [
"Lexique en anglais de l’algèbre linéaire",
"Wiktionnaire:Exemples manquants en anglais"
],
"glosses": [
"Base."
],
"topics": [
"mathematics"
]
}
],
"sounds": [
{
"ipa": "\\ˈbeɪ.sɪs\\"
},
{
"audio": "En-us-basis.ogg",
"ipa": "ˈbeɪ.sɪs",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/7/70/En-us-basis.ogg/En-us-basis.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-basis.ogg",
"raw_tags": [
"États-Unis"
]
},
{
"audio": "LL-Q1860 (eng)-Back ache-basis.wav",
"ipa": "ˈbeɪ.sɪs",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/ee/LL-Q1860_(eng)-Back_ache-basis.wav/LL-Q1860_(eng)-Back_ache-basis.wav.mp3",
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"Royaume-Uni (Londres)"
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}
],
"word": "basis"
}
Download raw JSONL data for basis meaning in Anglais (2.6kB)
This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2025-04-23 from the frwiktionary dump dated 2025-04-20 using wiktextract (813e02a and ea19a0a). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.