"Lloyd" meaning in Anglais

See Lloyd in All languages combined, or Wiktionary

Proper name

IPA: \lɔɪd\, \lɔɪd\ Audio: LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav , LL-Q1860 (eng)-Vealhurl-Lloyd.wav Forms: Floyd
  1. Nom de famille.
    Sense id: fr-Lloyd-en-name-Wdkkzxrr Categories (other): Exemples en anglais, Exemples en anglais à traduire
The following are not (yet) sense-disambiguated

Proper name

IPA: \lɔɪd\, \lɔɪd\ Audio: LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav , LL-Q1860 (eng)-Vealhurl-Lloyd.wav Forms: Floyd
  1. Prénom masculin.
    Sense id: fr-Lloyd-en-name-qg7gT5tW Categories (other): Exemples en anglais, Exemples en anglais à traduire
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "Noms de famille en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Noms propres en anglais issus d’un mot en gallois",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "Du gallois llwyd (« gris »), Legris en français."
  ],
  "forms": [
    {
      "form": "Floyd"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Nom de famille",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Exemples en anglais",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Exemples en anglais à traduire",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "text": "Alice Spencer Geddes Lloyd (1876–1962), was an American social reformer."
        }
      ],
      "glosses": [
        "Nom de famille."
      ],
      "id": "fr-Lloyd-en-name-Wdkkzxrr"
    }
  ],
  "sounds": [
    {
      "ipa": "\\lɔɪd\\"
    },
    {
      "ipa": "\\lɔɪd\\",
      "raw_tags": [
        "(Royaume-Uni)"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.ogg",
      "raw_tags": [
        "États-Unis (New Jersey)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.ogg",
      "raw_tags": [
        "Sud de l'Angleterre (Royaume-Uni)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Lloyd.wav"
    }
  ],
  "tags": [
    "surename"
  ],
  "word": "Lloyd"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Noms propres en anglais issus d’un mot en gallois",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Prénoms masculins en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "Du gallois llwyd (« gris »), Legris en français."
  ],
  "forms": [
    {
      "form": "Floyd"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Prénom",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Exemples en anglais",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Exemples en anglais à traduire",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "text": "Lloyd Burdick (1909–1945), was an American football player."
        }
      ],
      "glosses": [
        "Prénom masculin."
      ],
      "id": "fr-Lloyd-en-name-qg7gT5tW"
    }
  ],
  "sounds": [
    {
      "ipa": "\\lɔɪd\\"
    },
    {
      "ipa": "\\lɔɪd\\",
      "raw_tags": [
        "(Royaume-Uni)"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.ogg",
      "raw_tags": [
        "États-Unis (New Jersey)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.ogg",
      "raw_tags": [
        "Sud de l'Angleterre (Royaume-Uni)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Lloyd.wav"
    }
  ],
  "tags": [
    "first name"
  ],
  "word": "Lloyd"
}
{
  "categories": [
    "Noms de famille en anglais",
    "Noms propres en anglais issus d’un mot en gallois",
    "anglais"
  ],
  "etymology_texts": [
    "Du gallois llwyd (« gris »), Legris en français."
  ],
  "forms": [
    {
      "form": "Floyd"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Nom de famille",
  "senses": [
    {
      "categories": [
        "Exemples en anglais",
        "Exemples en anglais à traduire"
      ],
      "examples": [
        {
          "text": "Alice Spencer Geddes Lloyd (1876–1962), was an American social reformer."
        }
      ],
      "glosses": [
        "Nom de famille."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\lɔɪd\\"
    },
    {
      "ipa": "\\lɔɪd\\",
      "raw_tags": [
        "(Royaume-Uni)"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.ogg",
      "raw_tags": [
        "États-Unis (New Jersey)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.ogg",
      "raw_tags": [
        "Sud de l'Angleterre (Royaume-Uni)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Lloyd.wav"
    }
  ],
  "tags": [
    "surename"
  ],
  "word": "Lloyd"
}

{
  "categories": [
    "Noms propres en anglais issus d’un mot en gallois",
    "Prénoms masculins en anglais",
    "anglais"
  ],
  "etymology_texts": [
    "Du gallois llwyd (« gris »), Legris en français."
  ],
  "forms": [
    {
      "form": "Floyd"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Prénom",
  "senses": [
    {
      "categories": [
        "Exemples en anglais",
        "Exemples en anglais à traduire"
      ],
      "examples": [
        {
          "text": "Lloyd Burdick (1909–1945), was an American football player."
        }
      ],
      "glosses": [
        "Prénom masculin."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\lɔɪd\\"
    },
    {
      "ipa": "\\lɔɪd\\",
      "raw_tags": [
        "(Royaume-Uni)"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav/LL-Q1860_(eng)-Simplificationalizer-Lloyd.wav.ogg",
      "raw_tags": [
        "États-Unis (New Jersey)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Simplificationalizer-Lloyd.wav"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-Lloyd.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/67/LL-Q1860_(eng)-Vealhurl-Lloyd.wav/LL-Q1860_(eng)-Vealhurl-Lloyd.wav.ogg",
      "raw_tags": [
        "Sud de l'Angleterre (Royaume-Uni)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Lloyd.wav"
    }
  ],
  "tags": [
    "first name"
  ],
  "word": "Lloyd"
}

Download raw JSONL data for Lloyd meaning in Anglais (3.3kB)


This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2025-02-21 from the frwiktionary dump dated 2025-02-21 using wiktextract (9e2b7d3 and f2e72e5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.