"Judy" meaning in All languages combined

See Judy on Wiktionary

Proper name [Anglais]

IPA: \ˈdʒuːdi\ Audio: En-au-Judy.ogg , LL-Q1860 (eng)-Grendelkhan-Judy.wav
  1. Prénom féminin.
    Sense id: fr-Judy-en-name-7nGGHJaY
The following are not (yet) sense-disambiguated
Related terms: Judie

Noun [Tchèque]

  1. Génitif singulier de Juda. Form of: Juda
    Sense id: fr-Judy-cs-noun--KlHAbrt
  2. Accusatif pluriel de Juda. Form of: Juda
    Sense id: fr-Judy-cs-noun-wt6zVrd3
  3. Instrumental pluriel de Juda. Form of: Juda
    Sense id: fr-Judy-cs-noun-HzHLj629
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "Prénoms féminins en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "Diminutif de Judith."
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Prénom",
  "related": [
    {
      "word": "Judie"
    }
  ],
  "senses": [
    {
      "glosses": [
        "Prénom féminin."
      ],
      "id": "fr-Judy-en-name-7nGGHJaY"
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈdʒuːdi\\"
    },
    {
      "audio": "En-au-Judy.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/0e/En-au-Judy.ogg/En-au-Judy.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-au-Judy.ogg",
      "raw_tags": [
        "Australie"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Grendelkhan-Judy.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/2/28/LL-Q1860_(eng)-Grendelkhan-Judy.wav/LL-Q1860_(eng)-Grendelkhan-Judy.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/2/28/LL-Q1860_(eng)-Grendelkhan-Judy.wav/LL-Q1860_(eng)-Grendelkhan-Judy.wav.ogg",
      "raw_tags": [
        "Connecticut (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Judy.wav"
    }
  ],
  "tags": [
    "first name"
  ],
  "word": "Judy"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Formes de noms communs en tchèque",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Tchèque",
      "orig": "tchèque",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "Tchèque",
  "lang_code": "cs",
  "pos": "noun",
  "pos_title": "Forme de nom commun",
  "senses": [
    {
      "form_of": [
        {
          "word": "Juda"
        }
      ],
      "glosses": [
        "Génitif singulier de Juda."
      ],
      "id": "fr-Judy-cs-noun--KlHAbrt"
    },
    {
      "form_of": [
        {
          "word": "Juda"
        }
      ],
      "glosses": [
        "Accusatif pluriel de Juda."
      ],
      "id": "fr-Judy-cs-noun-wt6zVrd3"
    },
    {
      "form_of": [
        {
          "word": "Juda"
        }
      ],
      "glosses": [
        "Instrumental pluriel de Juda."
      ],
      "id": "fr-Judy-cs-noun-HzHLj629"
    }
  ],
  "tags": [
    "form-of"
  ],
  "word": "Judy"
}
{
  "categories": [
    "Prénoms féminins en anglais",
    "anglais"
  ],
  "etymology_texts": [
    "Diminutif de Judith."
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Prénom",
  "related": [
    {
      "word": "Judie"
    }
  ],
  "senses": [
    {
      "glosses": [
        "Prénom féminin."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈdʒuːdi\\"
    },
    {
      "audio": "En-au-Judy.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/0e/En-au-Judy.ogg/En-au-Judy.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-au-Judy.ogg",
      "raw_tags": [
        "Australie"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Grendelkhan-Judy.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/2/28/LL-Q1860_(eng)-Grendelkhan-Judy.wav/LL-Q1860_(eng)-Grendelkhan-Judy.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/2/28/LL-Q1860_(eng)-Grendelkhan-Judy.wav/LL-Q1860_(eng)-Grendelkhan-Judy.wav.ogg",
      "raw_tags": [
        "Connecticut (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Judy.wav"
    }
  ],
  "tags": [
    "first name"
  ],
  "word": "Judy"
}

{
  "categories": [
    "Formes de noms communs en tchèque",
    "tchèque"
  ],
  "lang": "Tchèque",
  "lang_code": "cs",
  "pos": "noun",
  "pos_title": "Forme de nom commun",
  "senses": [
    {
      "form_of": [
        {
          "word": "Juda"
        }
      ],
      "glosses": [
        "Génitif singulier de Juda."
      ]
    },
    {
      "form_of": [
        {
          "word": "Juda"
        }
      ],
      "glosses": [
        "Accusatif pluriel de Juda."
      ]
    },
    {
      "form_of": [
        {
          "word": "Juda"
        }
      ],
      "glosses": [
        "Instrumental pluriel de Juda."
      ]
    }
  ],
  "tags": [
    "form-of"
  ],
  "word": "Judy"
}

Download raw JSONL data for Judy meaning in All languages combined (1.5kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-03 from the frwiktionary dump dated 2024-10-20 using wiktextract (d6bf104 and a5af179). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.