"stomaco" meaning in Italiano

See stomaco in All languages combined, or Wiktionary

Noun

IPA: [ˈstɔ.ma.ko] Forms: stomaco [singular], stomaci [plural], stomaco [singular], stomachi [plural]
Etymology: Del latín stomachus. Etymology templates: {{etimología|la|stomachus|leng=it}} Del latín stomachus
  1. Estómago.
    Sense id: es-stomaco-it-noun-1Nrdu9TA Categories (other): IT:Anatomía, IT:Zootomía Topics: anatomy, zootomy
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "IT:Sustantivos",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "IT:Sustantivos masculinos",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Italiano",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "la",
        "2": "stomachus",
        "leng": "it"
      },
      "expansion": "Del latín stomachus",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del latín stomachus.",
  "forms": [
    {
      "form": "stomaco",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "stomaci",
      "tags": [
        "plural"
      ]
    },
    {
      "form": "stomaco",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "stomachi",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Italiano",
  "lang_code": "it",
  "pos": "noun",
  "pos_title": "sustantivo masculino",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "IT:Anatomía",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "IT:Zootomía",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Estómago."
      ],
      "id": "es-stomaco-it-noun-1Nrdu9TA",
      "sense_index": "1",
      "topics": [
        "anatomy",
        "zootomy"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈstɔ.ma.ko]"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "stomaco"
}
{
  "categories": [
    "IT:Sustantivos",
    "IT:Sustantivos masculinos",
    "Italiano"
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "la",
        "2": "stomachus",
        "leng": "it"
      },
      "expansion": "Del latín stomachus",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del latín stomachus.",
  "forms": [
    {
      "form": "stomaco",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "stomaci",
      "tags": [
        "plural"
      ]
    },
    {
      "form": "stomaco",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "stomachi",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Italiano",
  "lang_code": "it",
  "pos": "noun",
  "pos_title": "sustantivo masculino",
  "senses": [
    {
      "categories": [
        "IT:Anatomía",
        "IT:Zootomía"
      ],
      "glosses": [
        "Estómago."
      ],
      "sense_index": "1",
      "topics": [
        "anatomy",
        "zootomy"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈstɔ.ma.ko]"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "stomaco"
}

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This page is a part of the kaikki.org machine-readable Italiano dictionary. This dictionary is based on structured data extracted on 2024-12-18 from the eswiktionary dump dated 2024-12-04 using wiktextract (681a778 and 4401a4c). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.