"parody" meaning in Inglés

See parody in All languages combined, or Wiktionary

Noun

IPA: [ˈpærədɪ] Forms: parody [singular], parodies [plural]
Etymology: Del latín parodia Etymology templates: {{etimología|la|parodia|leng=en}} Del latín parodia
  1. Parodia
    Sense id: es-parody-en-noun-B32FCmaR
The following are not (yet) sense-disambiguated
Categories (other): EN:Sustantivos, Inglés

Verb

IPA: [ˈpærədɪ]
Etymology: Del latín parodia Etymology templates: {{etimología|la|parodia|leng=en}} Del latín parodia
  1. Parodiar.
    Sense id: es-parody-en-verb-n5SqvUyA
The following are not (yet) sense-disambiguated
Categories (other): EN:Verbos, Inglés

Inflected forms

{
  "categories": [
    {
      "kind": "other",
      "name": "EN:Sustantivos",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Inglés",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "la",
        "2": "parodia",
        "leng": "en"
      },
      "expansion": "Del latín parodia",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del latín parodia",
  "forms": [
    {
      "form": "parody",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "parodies",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Inglés",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "sustantivo",
  "senses": [
    {
      "glosses": [
        "Parodia"
      ],
      "id": "es-parody-en-noun-B32FCmaR",
      "sense_index": "1"
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈpærədɪ]"
    }
  ],
  "word": "parody"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "EN:Verbos",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Inglés",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "la",
        "2": "parodia",
        "leng": "en"
      },
      "expansion": "Del latín parodia",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del latín parodia",
  "lang": "Inglés",
  "lang_code": "en",
  "pos": "verb",
  "pos_title": "verbo",
  "senses": [
    {
      "glosses": [
        "Parodiar."
      ],
      "id": "es-parody-en-verb-n5SqvUyA",
      "sense_index": "2"
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈpærədɪ]"
    }
  ],
  "word": "parody"
}
{
  "categories": [
    "EN:Sustantivos",
    "Inglés"
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "la",
        "2": "parodia",
        "leng": "en"
      },
      "expansion": "Del latín parodia",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del latín parodia",
  "forms": [
    {
      "form": "parody",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "parodies",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Inglés",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "sustantivo",
  "senses": [
    {
      "glosses": [
        "Parodia"
      ],
      "sense_index": "1"
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈpærədɪ]"
    }
  ],
  "word": "parody"
}

{
  "categories": [
    "EN:Verbos",
    "Inglés"
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "la",
        "2": "parodia",
        "leng": "en"
      },
      "expansion": "Del latín parodia",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del latín parodia",
  "lang": "Inglés",
  "lang_code": "en",
  "pos": "verb",
  "pos_title": "verbo",
  "senses": [
    {
      "glosses": [
        "Parodiar."
      ],
      "sense_index": "2"
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈpærədɪ]"
    }
  ],
  "word": "parody"
}

Download raw JSONL data for parody meaning in Inglés (0.9kB)


This page is a part of the kaikki.org machine-readable Inglés dictionary. This dictionary is based on structured data extracted on 2024-11-28 from the eswiktionary dump dated 2024-11-21 using wiktextract (65a6e81 and 0dbea76). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.