"quadrilliard" meaning in English

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      "expansion": "French quadrilliard",
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        "2": "quadri",
        "3": "illiard"
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      "expansion": "quadri- + -illiard",
      "name": "confix"
    }
  ],
  "etymology_text": "From French quadrilliard, equivalent to quadri- + -illiard.",
  "forms": [
    {
      "form": "quadrilliards",
      "tags": [
        "plural"
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      "expansion": "quadrilliard (plural quadrilliards)",
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  "lang": "English",
  "lang_code": "en",
  "pos": "num",
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      "examples": [
        {
          "ref": "2002 June 19, bruce, “Re: Australians did it again! (?)”, in alt.fan.robert-jordan (Usenet), message-ID <cs9qea.as3.ln@ID-92747.user.dfncis.de>",
          "text": "Ugh. An Australian should use Australian numbers (the same as British), not American. 10^27 is 1,000 quadrillion (or a quadrilliard). An octillion would be 10^48.",
          "type": "quotation"
        },
        {
          "ref": "2003 December 3, arie, “Re: Why Women \"Test\" Men, and What Men can Do About It”, in alt.support.loneliness (Usenet), message-ID <bqkc2m$dg9$1@news.tudelft.nl>",
          "text": "Your estimation was quite accurate. In a body of 75 kg of water, there are roughly 2.5 x 10^28. That's 25 octillion (US) or 25 quadrilliard (EU).",
          "type": "quotation"
        },
        {
          "ref": "2007, Reinhard Wobst, “Life After DES: New Methods, New Attacks”, in Angelika Shafir, transl., Cryptology Unlocked, John Wiley & Sons, Ltd, section 3 (IDEA: A Special-Class Algoritmh), subsection 5 (Cryptanalyzing IDEA), page 239",
          "text": "There are weak keys in the sense that their use by foisting chosen plaintexts can be proved, which could be interesting for chip cards with a ‘burnt-in key’. First of all, however, these keys can be easily avoided—one only needs to XOR all subkeys with the hexadecimal number 0x0dae—and second, the probability that such a key can be caught is 2⁻⁹⁶; that is about one out of 10²⁹ randomly selected keys (this number even has a name: 100 quadrilliards).",
          "type": "quotation"
        },
        {
          "ref": "2014 May 16, Lela Buckingham, “Chapter 3: Systems of Measurement”, in Fundamental Laboratory Mathematics: Required Calculations for the Medical Laboratory Professional, Philadelphia: F. A. Davis Company, Box 3-3: Terms for Large Numbers, page 47",
          "text": "In the European system, 10⁹ is a milliard, 10¹² is a billion, 10¹⁵ is a billiard, 10¹⁸ is a trillion, 10²¹ is a trilliard, 10²⁴ is a quadrillion, and 10²⁷ is a quadrilliard. To avoid confusion in expressing these numbers, the SI prefixes are preferred.",
          "type": "quotation"
        }
      ],
      "glosses": [
        "A thousand million million million million: 1 followed by twenty-seven zeros, 10²⁷."
      ],
      "id": "en-quadrilliard-en-num-l-7qu9Ok",
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      "related": [
        {
          "word": "Previous: quadrillion. Next: quintillion."
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      "synonyms": [
        {
          "word": "a short scale octillion"
        }
      ],
      "tags": [
        "rare"
      ]
    }
  ],
  "word": "quadrilliard"
}

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      "expansion": "French quadrilliard",
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      "expansion": "quadri- + -illiard",
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  ],
  "etymology_text": "From French quadrilliard, equivalent to quadri- + -illiard.",
  "forms": [
    {
      "form": "quadrilliards",
      "tags": [
        "plural"
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  "lang_code": "en",
  "pos": "num",
  "related": [
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      "word": "Previous: quadrillion. Next: quintillion."
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          "ref": "2002 June 19, bruce, “Re: Australians did it again! (?)”, in alt.fan.robert-jordan (Usenet), message-ID <cs9qea.as3.ln@ID-92747.user.dfncis.de>",
          "text": "Ugh. An Australian should use Australian numbers (the same as British), not American. 10^27 is 1,000 quadrillion (or a quadrilliard). An octillion would be 10^48.",
          "type": "quotation"
        },
        {
          "ref": "2003 December 3, arie, “Re: Why Women \"Test\" Men, and What Men can Do About It”, in alt.support.loneliness (Usenet), message-ID <bqkc2m$dg9$1@news.tudelft.nl>",
          "text": "Your estimation was quite accurate. In a body of 75 kg of water, there are roughly 2.5 x 10^28. That's 25 octillion (US) or 25 quadrilliard (EU).",
          "type": "quotation"
        },
        {
          "ref": "2007, Reinhard Wobst, “Life After DES: New Methods, New Attacks”, in Angelika Shafir, transl., Cryptology Unlocked, John Wiley & Sons, Ltd, section 3 (IDEA: A Special-Class Algoritmh), subsection 5 (Cryptanalyzing IDEA), page 239",
          "text": "There are weak keys in the sense that their use by foisting chosen plaintexts can be proved, which could be interesting for chip cards with a ‘burnt-in key’. First of all, however, these keys can be easily avoided—one only needs to XOR all subkeys with the hexadecimal number 0x0dae—and second, the probability that such a key can be caught is 2⁻⁹⁶; that is about one out of 10²⁹ randomly selected keys (this number even has a name: 100 quadrilliards).",
          "type": "quotation"
        },
        {
          "ref": "2014 May 16, Lela Buckingham, “Chapter 3: Systems of Measurement”, in Fundamental Laboratory Mathematics: Required Calculations for the Medical Laboratory Professional, Philadelphia: F. A. Davis Company, Box 3-3: Terms for Large Numbers, page 47",
          "text": "In the European system, 10⁹ is a milliard, 10¹² is a billion, 10¹⁵ is a billiard, 10¹⁸ is a trillion, 10²¹ is a trilliard, 10²⁴ is a quadrillion, and 10²⁷ is a quadrilliard. To avoid confusion in expressing these numbers, the SI prefixes are preferred.",
          "type": "quotation"
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      ],
      "glosses": [
        "A thousand million million million million: 1 followed by twenty-seven zeros, 10²⁷."
      ],
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  "synonyms": [
    {
      "word": "a short scale octillion"
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  "word": "quadrilliard"
}