"quadrilliard" meaning in All languages combined

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        "3": "quadrilliard"
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      "expansion": "French quadrilliard",
      "name": "bor"
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        "2": "quadri",
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      "expansion": "quadri- + -illiard",
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  "etymology_text": "From French quadrilliard, equivalent to quadri- + -illiard.",
  "forms": [
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      "form": "quadrilliards",
      "tags": [
        "plural"
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  "lang_code": "en",
  "pos": "num",
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        },
        {
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          "source": "w"
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      "examples": [
        {
          "ref": "2002 June 19, bruce, “Re: Australians did it again! (?)”, in alt.fan.robert-jordan (Usenet), message-ID <cs9qea.as3.ln@ID-92747.user.dfncis.de>:",
          "text": "Ugh. An Australian should use Australian numbers (the same as British), not American. 10^27 is 1,000 quadrillion (or a quadrilliard). An octillion would be 10^48.",
          "type": "quote"
        },
        {
          "ref": "2003 December 3, arie, “Re: Why Women \"Test\" Men, and What Men can Do About It”, in alt.support.loneliness (Usenet), message-ID <bqkc2m$dg9$1@news.tudelft.nl>:",
          "text": "Your estimation was quite accurate. In a body of 75 kg of water, there are roughly 2.5 x 10^28. That's 25 octillion (US) or 25 quadrilliard (EU).",
          "type": "quote"
        },
        {
          "ref": "2007, Reinhard Wobst, “Life After DES: New Methods, New Attacks”, in Angelika Shafir, transl., Cryptology Unlocked, John Wiley & Sons, Ltd, →ISBN, section 3 (IDEA: A Special-Class Algoritmh), subsection 5 (Cryptanalyzing IDEA), page 239:",
          "text": "There are weak keys in the sense that their use by foisting chosen plaintexts can be proved, which could be interesting for chip cards with a ‘burnt-in key’. First of all, however, these keys can be easily avoided—one only needs to XOR all subkeys with the hexadecimal number 0x0dae—and second, the probability that such a key can be caught is 2⁻⁹⁶; that is about one out of 10²⁹ randomly selected keys (this number even has a name: 100 quadrilliards).",
          "type": "quote"
        },
        {
          "ref": "2014 May 16, Lela Buckingham, “Chapter 3: Systems of Measurement”, in Fundamental Laboratory Mathematics: Required Calculations for the Medical Laboratory Professional, Philadelphia: F. A. Davis Company, →ISBN, Box 3-3: Terms for Large Numbers, page 47:",
          "text": "In the European system, 10⁹ is a milliard, 10¹² is a billion, 10¹⁵ is a billiard, 10¹⁸ is a trillion, 10²¹ is a trilliard, 10²⁴ is a quadrillion, and 10²⁷ is a quadrilliard. To avoid confusion in expressing these numbers, the SI prefixes are preferred.",
          "type": "quote"
        }
      ],
      "glosses": [
        "A thousand million million million million: 1 followed by twenty-seven zeros, 10²⁷."
      ],
      "id": "en-quadrilliard-en-num-l-7qu9Ok",
      "links": [
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          "thousand",
          "thousand"
        ],
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          "million",
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      ],
      "related": [
        {
          "word": "Previous: quadrillion. Next: quintillion."
        }
      ],
      "synonyms": [
        {
          "word": "a short scale octillion"
        }
      ],
      "tags": [
        "rare"
      ]
    }
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  "word": "quadrilliard"
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        "2": "quadri-",
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        "t1": "four"
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      "expansion": "quadri- (“four”) + -illiard",
      "name": "af"
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  ],
  "etymology_text": "From quadri- (“four”) + -illiard.",
  "forms": [
    {
      "form": "quadrilliards",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "French",
  "lang_code": "fr",
  "pos": "num",
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          "english": "fr. 53ⱽᴵ 695 236ⱽ 076 014ᴵⱽ 489 752ᴵᴵᴵ 446 593ᴵᴵ 034 515ᴵ 466 398,33 / According to our proposals, this number would be stated as follows: 53 undecillion 695 decillion 236 nonillion 76 octillion 14 septillion 489 sextillion 752 quintillion 446 quadrillion 593 trillion 34 billion 515 million 466 thousand 398 francs and 33 centimes.",
          "ref": "1921, Louis-Gustave Du Pasquier, Le développement de la notion de nombre [The Development of the Notion of Number] (Mémoires de l’Université de Neuchâtel [Memoirs of the University of Neuchâtel]; 3), page 125:",
          "text": "fr. 53ⱽᴵ 695 236ⱽ 076 014ᴵⱽ 489 752ᴵᴵᴵ 446 593ᴵᴵ 034 515ᴵ 466 398,33 / D’après nos propositions, ce nombre s’énoncerait ainsi : 53 sextillions 695 quintilliards 236 quintillions 76 quadrilliards 14 quadrillions 489 trilliards 752 trillions 446 billiards 593 billions 34 milliards 515 millions 466 mille 398 francs et 33 centimes.",
          "type": "quote"
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        {
          "english": "If we calculate the total number of protons and electrons that make up ordinary atomic matter, the result is 1 followed by 80 zeros, or 100 quinvigintillion! This is equivalent to 25 octillion (25 x 10²⁷) planet Earths.",
          "ref": "2017, Deepak Chopra, Menas Kafatos, translated by Olivier Vinet, Le pouvoir de l’univers est en vous : Partez à la découverte de votre origine cosmique [The Power of the Universe Is within You: Discover Your Cosmic Origin], Guy Trédaniel, →ISBN:",
          "text": "Si l’on calcule le nombre total de protons et d’électrons constituant la matière atomique ordinaire, le résultat obtenu est de 1 suivi de 80 zéros, soit 100 trédécillions ! Cela équivaut à 25 quadrilliards [translating million sextillion] (25 x 10²⁷) de planètes Terre.",
          "type": "quote"
        },
        {
          "english": "At that time, one forint was worth four hundred octillion pengős […]",
          "ref": "2021, Thomas Andrieu, L’or et l’argent : Guide complet pour comprendre et investir [Gold and Silver: A Complete Guide to Understanding and Investing], JDH Éditions, →ISBN, page 175:",
          "text": "À ce moment-là, un forint valait quatre cents quadrilliards pengő […]",
          "type": "quote"
        }
      ],
      "glosses": [
        "octillion (10²⁷)"
      ],
      "id": "en-quadrilliard-fr-num-KuZO6~Sd",
      "links": [
        [
          "octillion",
          "octillion"
        ]
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      "tags": [
        "masculine"
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  ],
  "sounds": [
    {
      "ipa": "/kwa.dʁi.ljaʁ/"
    },
    {
      "ipa": "/ka.dʁi.ljaʁ/"
    },
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  "word": "quadrilliard"
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  "etymology_text": "From French quadrilliard, equivalent to quadri- + -illiard.",
  "forms": [
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  "lang": "English",
  "lang_code": "en",
  "pos": "num",
  "related": [
    {
      "word": "Previous: quadrillion. Next: quintillion."
    }
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          "ref": "2002 June 19, bruce, “Re: Australians did it again! (?)”, in alt.fan.robert-jordan (Usenet), message-ID <cs9qea.as3.ln@ID-92747.user.dfncis.de>:",
          "text": "Ugh. An Australian should use Australian numbers (the same as British), not American. 10^27 is 1,000 quadrillion (or a quadrilliard). An octillion would be 10^48.",
          "type": "quote"
        },
        {
          "ref": "2003 December 3, arie, “Re: Why Women \"Test\" Men, and What Men can Do About It”, in alt.support.loneliness (Usenet), message-ID <bqkc2m$dg9$1@news.tudelft.nl>:",
          "text": "Your estimation was quite accurate. In a body of 75 kg of water, there are roughly 2.5 x 10^28. That's 25 octillion (US) or 25 quadrilliard (EU).",
          "type": "quote"
        },
        {
          "ref": "2007, Reinhard Wobst, “Life After DES: New Methods, New Attacks”, in Angelika Shafir, transl., Cryptology Unlocked, John Wiley & Sons, Ltd, →ISBN, section 3 (IDEA: A Special-Class Algoritmh), subsection 5 (Cryptanalyzing IDEA), page 239:",
          "text": "There are weak keys in the sense that their use by foisting chosen plaintexts can be proved, which could be interesting for chip cards with a ‘burnt-in key’. First of all, however, these keys can be easily avoided—one only needs to XOR all subkeys with the hexadecimal number 0x0dae—and second, the probability that such a key can be caught is 2⁻⁹⁶; that is about one out of 10²⁹ randomly selected keys (this number even has a name: 100 quadrilliards).",
          "type": "quote"
        },
        {
          "ref": "2014 May 16, Lela Buckingham, “Chapter 3: Systems of Measurement”, in Fundamental Laboratory Mathematics: Required Calculations for the Medical Laboratory Professional, Philadelphia: F. A. Davis Company, →ISBN, Box 3-3: Terms for Large Numbers, page 47:",
          "text": "In the European system, 10⁹ is a milliard, 10¹² is a billion, 10¹⁵ is a billiard, 10¹⁸ is a trillion, 10²¹ is a trilliard, 10²⁴ is a quadrillion, and 10²⁷ is a quadrilliard. To avoid confusion in expressing these numbers, the SI prefixes are preferred.",
          "type": "quote"
        }
      ],
      "glosses": [
        "A thousand million million million million: 1 followed by twenty-seven zeros, 10²⁷."
      ],
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  "synonyms": [
    {
      "word": "a short scale octillion"
    }
  ],
  "word": "quadrilliard"
}

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      "name": "af"
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  ],
  "etymology_text": "From quadri- (“four”) + -illiard.",
  "forms": [
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  ],
  "lang": "French",
  "lang_code": "fr",
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          "english": "fr. 53ⱽᴵ 695 236ⱽ 076 014ᴵⱽ 489 752ᴵᴵᴵ 446 593ᴵᴵ 034 515ᴵ 466 398,33 / According to our proposals, this number would be stated as follows: 53 undecillion 695 decillion 236 nonillion 76 octillion 14 septillion 489 sextillion 752 quintillion 446 quadrillion 593 trillion 34 billion 515 million 466 thousand 398 francs and 33 centimes.",
          "ref": "1921, Louis-Gustave Du Pasquier, Le développement de la notion de nombre [The Development of the Notion of Number] (Mémoires de l’Université de Neuchâtel [Memoirs of the University of Neuchâtel]; 3), page 125:",
          "text": "fr. 53ⱽᴵ 695 236ⱽ 076 014ᴵⱽ 489 752ᴵᴵᴵ 446 593ᴵᴵ 034 515ᴵ 466 398,33 / D’après nos propositions, ce nombre s’énoncerait ainsi : 53 sextillions 695 quintilliards 236 quintillions 76 quadrilliards 14 quadrillions 489 trilliards 752 trillions 446 billiards 593 billions 34 milliards 515 millions 466 mille 398 francs et 33 centimes.",
          "type": "quote"
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          "english": "If we calculate the total number of protons and electrons that make up ordinary atomic matter, the result is 1 followed by 80 zeros, or 100 quinvigintillion! This is equivalent to 25 octillion (25 x 10²⁷) planet Earths.",
          "ref": "2017, Deepak Chopra, Menas Kafatos, translated by Olivier Vinet, Le pouvoir de l’univers est en vous : Partez à la découverte de votre origine cosmique [The Power of the Universe Is within You: Discover Your Cosmic Origin], Guy Trédaniel, →ISBN:",
          "text": "Si l’on calcule le nombre total de protons et d’électrons constituant la matière atomique ordinaire, le résultat obtenu est de 1 suivi de 80 zéros, soit 100 trédécillions ! Cela équivaut à 25 quadrilliards [translating million sextillion] (25 x 10²⁷) de planètes Terre.",
          "type": "quote"
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        {
          "english": "At that time, one forint was worth four hundred octillion pengős […]",
          "ref": "2021, Thomas Andrieu, L’or et l’argent : Guide complet pour comprendre et investir [Gold and Silver: A Complete Guide to Understanding and Investing], JDH Éditions, →ISBN, page 175:",
          "text": "À ce moment-là, un forint valait quatre cents quadrilliards pengő […]",
          "type": "quote"
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      "glosses": [
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