"Bernstein basis polynomial" meaning in English

{
  "etymology_text": "Named after Sergei Natanovich Bernstein (1880–1968), a Russian and Soviet mathematician of Jewish origin.",
  "forms": [
    {
      "form": "Bernstein basis polynomials",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {},
      "expansion": "Bernstein basis polynomial (plural Bernstein basis polynomials)",
      "name": "en-noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
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          "source": "w"
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          "kind": "topical",
          "langcode": "en",
          "name": "Mathematical analysis",
          "orig": "en:Mathematical analysis",
          "parents": [
            "Mathematics",
            "Formal sciences",
            "Sciences",
            "All topics",
            "Fundamental"
          ],
          "source": "w"
        }
      ],
      "glosses": [
        "Any polynomial of the form b_i,n(t)=n choose itⁱ(1-t)ⁿ⁻ⁱ!!, being the iᵗʰ term of the binomial expansion of (t+(1-t))ⁿ!."
      ],
      "holonyms": [
        {
          "word": "Bernstein polynomial"
        }
      ],
      "id": "en-Bernstein_basis_polynomial-en-noun--kWcWU9E",
      "links": [
        [
          "mathematical analysis",
          "mathematical analysis"
        ],
        [
          "polynomial",
          "polynomial"
        ],
        [
          "binomial expansion",
          "binomial expansion"
        ]
      ],
      "meronyms": [
        {
          "word": "binomial coefficient"
        }
      ],
      "qualifier": "numerical analysis",
      "raw_glosses": [
        "(mathematical analysis, numerical analysis) Any polynomial of the form b_i,n(t)=n choose itⁱ(1-t)ⁿ⁻ⁱ!!, being the iᵗʰ term of the binomial expansion of (t+(1-t))ⁿ!."
      ],
      "related": [
        {
          "word": "Beziér curve"
        }
      ],
      "topics": [
        "mathematical-analysis",
        "mathematics",
        "sciences"
      ],
      "wikipedia": [
        "Sergei Natanovich Bernstein"
      ]
    }
  ],
  "word": "Bernstein basis polynomial"
}

{
  "etymology_text": "Named after Sergei Natanovich Bernstein (1880–1968), a Russian and Soviet mathematician of Jewish origin.",
  "forms": [
    {
      "form": "Bernstein basis polynomials",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {},
      "expansion": "Bernstein basis polynomial (plural Bernstein basis polynomials)",
      "name": "en-noun"
    }
  ],
  "holonyms": [
    {
      "word": "Bernstein polynomial"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "meronyms": [
    {
      "word": "binomial coefficient"
    }
  ],
  "pos": "noun",
  "related": [
    {
      "word": "Beziér curve"
    }
  ],
  "senses": [
    {
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        "English countable nouns",
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        "English multiword terms",
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        "Pages with 1 entry",
        "Pages with entries",
        "en:Mathematical analysis"
      ],
      "glosses": [
        "Any polynomial of the form b_i,n(t)=n choose itⁱ(1-t)ⁿ⁻ⁱ!!, being the iᵗʰ term of the binomial expansion of (t+(1-t))ⁿ!."
      ],
      "links": [
        [
          "mathematical analysis",
          "mathematical analysis"
        ],
        [
          "polynomial",
          "polynomial"
        ],
        [
          "binomial expansion",
          "binomial expansion"
        ]
      ],
      "qualifier": "numerical analysis",
      "raw_glosses": [
        "(mathematical analysis, numerical analysis) Any polynomial of the form b_i,n(t)=n choose itⁱ(1-t)ⁿ⁻ⁱ!!, being the iᵗʰ term of the binomial expansion of (t+(1-t))ⁿ!."
      ],
      "topics": [
        "mathematical-analysis",
        "mathematics",
        "sciences"
      ],
      "wikipedia": [
        "Sergei Natanovich Bernstein"
      ]
    }
  ],
  "word": "Bernstein basis polynomial"
}