See superderivative on Wiktionary
{ "etymology_templates": [ { "args": { "1": "en", "2": "super", "3": "derivative" }, "expansion": "super- + derivative", "name": "prefix" } ], "etymology_text": "From super- + derivative.", "forms": [ { "form": "superderivatives", "tags": [ "plural" ] } ], "head_templates": [ { "args": {}, "expansion": "superderivative (plural superderivatives)", "name": "en-noun" } ], "lang": "English", "lang_code": "en", "pos": "noun", "senses": [ { "categories": [ { "kind": "other", "name": "English entries with incorrect language header", "parents": [ "Entries with incorrect language header", "Entry maintenance" ], "source": "w" }, { "kind": "other", "name": "English terms prefixed with super-", "parents": [], "source": "w" }, { "kind": "other", "name": "Pages with 1 entry", "parents": [], "source": "w" }, { "kind": "other", "name": "Pages with entries", "parents": [], "source": "w" }, { "kind": "topical", "langcode": "en", "name": "Mathematics", "orig": "en:Mathematics", "parents": [ "Formal sciences", "Sciences", "All topics", "Fundamental" ], "source": "w" } ], "examples": [ { "ref": "2016, Simon Li, Ekaterina Shemyakova, Theodore Voronov, “Differential operators on the superline, Berezinians, and Darboux transformations”, in arXiv:", "text": "We distinguish non-degenerate operators as those with an invertible top coefficient in the expansion in the superderivative D.", "type": "quote" } ], "glosses": [ "A generalization of a derivative that can be applied to a superfunction." ], "id": "en-superderivative-en-noun-fpowH~2V", "links": [ [ "mathematics", "mathematics" ], [ "generalization", "generalization" ], [ "derivative", "derivative" ], [ "superfunction", "superfunction" ] ], "raw_glosses": [ "(mathematics) A generalization of a derivative that can be applied to a superfunction." ], "topics": [ "mathematics", "sciences" ] } ], "sounds": [ { "audio": "LL-Q1860 (eng)-Flame, not lame-superderivative.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/da/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/da/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav.ogg" } ], "word": "superderivative" }
{ "etymology_templates": [ { "args": { "1": "en", "2": "super", "3": "derivative" }, "expansion": "super- + derivative", "name": "prefix" } ], "etymology_text": "From super- + derivative.", "forms": [ { "form": "superderivatives", "tags": [ "plural" ] } ], "head_templates": [ { "args": {}, "expansion": "superderivative (plural superderivatives)", "name": "en-noun" } ], "lang": "English", "lang_code": "en", "pos": "noun", "senses": [ { "categories": [ "English countable nouns", "English entries with incorrect language header", "English lemmas", "English nouns", "English terms prefixed with super-", "English terms with quotations", "Pages with 1 entry", "Pages with entries", "en:Mathematics" ], "examples": [ { "ref": "2016, Simon Li, Ekaterina Shemyakova, Theodore Voronov, “Differential operators on the superline, Berezinians, and Darboux transformations”, in arXiv:", "text": "We distinguish non-degenerate operators as those with an invertible top coefficient in the expansion in the superderivative D.", "type": "quote" } ], "glosses": [ "A generalization of a derivative that can be applied to a superfunction." ], "links": [ [ "mathematics", "mathematics" ], [ "generalization", "generalization" ], [ "derivative", "derivative" ], [ "superfunction", "superfunction" ] ], "raw_glosses": [ "(mathematics) A generalization of a derivative that can be applied to a superfunction." ], "topics": [ "mathematics", "sciences" ] } ], "sounds": [ { "audio": "LL-Q1860 (eng)-Flame, not lame-superderivative.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/da/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/da/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav/LL-Q1860_%28eng%29-Flame%2C_not_lame-superderivative.wav.ogg" } ], "word": "superderivative" }
Download raw JSONL data for superderivative meaning in All languages combined (1.9kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-02-15 from the enwiktionary dump dated 2025-02-02 using wiktextract (ca09fec and c40eb85). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.