"abrogatoria" meaning in All languages combined

See abrogatoria on Wiktionary

Adjective [Italian]

IPA: /a.bro.ɡaˈtɔ.rja/
Rhymes: -ɔrja Head templates: {{head|it|adjective form}} abrogatoria
  1. feminine singular of abrogatorio Tags: feminine, form-of, singular Form of: abrogatorio
    Sense id: en-abrogatoria-it-adj-L7y849Aj Categories (other): Italian entries with incorrect language header, Pages with 2 entries

Adjective [Spanish]

IPA: /abɾoɡaˈtoɾja/, [a.β̞ɾo.ɣ̞aˈt̪o.ɾja]
Rhymes: -oɾja Head templates: {{head|es|adjective form}} abrogatoria
  1. feminine singular of abrogatorio Tags: feminine, form-of, singular Form of: abrogatorio
    Sense id: en-abrogatoria-es-adj-L7y849Aj Categories (other): Pages with 2 entries, Spanish entries with incorrect language header
{
  "head_templates": [
    {
      "args": {
        "1": "it",
        "2": "adjective form"
      },
      "expansion": "abrogatoria",
      "name": "head"
    }
  ],
  "hyphenation": [
    "a‧bro‧ga‧tò‧ria"
  ],
  "lang": "Italian",
  "lang_code": "it",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Italian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with 2 entries",
          "parents": [],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "word": "abrogatorio"
        }
      ],
      "glosses": [
        "feminine singular of abrogatorio"
      ],
      "id": "en-abrogatoria-it-adj-L7y849Aj",
      "links": [
        [
          "abrogatorio",
          "abrogatorio#Italian"
        ]
      ],
      "tags": [
        "feminine",
        "form-of",
        "singular"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/a.bro.ɡaˈtɔ.rja/"
    },
    {
      "rhymes": "-ɔrja"
    }
  ],
  "word": "abrogatoria"
}

{
  "head_templates": [
    {
      "args": {
        "1": "es",
        "2": "adjective form"
      },
      "expansion": "abrogatoria",
      "name": "head"
    }
  ],
  "hyphenation": [
    "a‧bro‧ga‧to‧ria"
  ],
  "lang": "Spanish",
  "lang_code": "es",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Pages with 2 entries",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Spanish entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "word": "abrogatorio"
        }
      ],
      "glosses": [
        "feminine singular of abrogatorio"
      ],
      "id": "en-abrogatoria-es-adj-L7y849Aj",
      "links": [
        [
          "abrogatorio",
          "abrogatorio#Spanish"
        ]
      ],
      "tags": [
        "feminine",
        "form-of",
        "singular"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/abɾoɡaˈtoɾja/"
    },
    {
      "ipa": "[a.β̞ɾo.ɣ̞aˈt̪o.ɾja]"
    },
    {
      "rhymes": "-oɾja"
    }
  ],
  "word": "abrogatoria"
}
{
  "head_templates": [
    {
      "args": {
        "1": "it",
        "2": "adjective form"
      },
      "expansion": "abrogatoria",
      "name": "head"
    }
  ],
  "hyphenation": [
    "a‧bro‧ga‧tò‧ria"
  ],
  "lang": "Italian",
  "lang_code": "it",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        "Italian 5-syllable words",
        "Italian adjective forms",
        "Italian entries with incorrect language header",
        "Italian non-lemma forms",
        "Italian terms with IPA pronunciation",
        "Pages with 2 entries",
        "Rhymes:Italian/ɔrja",
        "Rhymes:Italian/ɔrja/5 syllables"
      ],
      "form_of": [
        {
          "word": "abrogatorio"
        }
      ],
      "glosses": [
        "feminine singular of abrogatorio"
      ],
      "links": [
        [
          "abrogatorio",
          "abrogatorio#Italian"
        ]
      ],
      "tags": [
        "feminine",
        "form-of",
        "singular"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/a.bro.ɡaˈtɔ.rja/"
    },
    {
      "rhymes": "-ɔrja"
    }
  ],
  "word": "abrogatoria"
}

{
  "head_templates": [
    {
      "args": {
        "1": "es",
        "2": "adjective form"
      },
      "expansion": "abrogatoria",
      "name": "head"
    }
  ],
  "hyphenation": [
    "a‧bro‧ga‧to‧ria"
  ],
  "lang": "Spanish",
  "lang_code": "es",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        "Pages with 2 entries",
        "Rhymes:Spanish/oɾja",
        "Rhymes:Spanish/oɾja/5 syllables",
        "Spanish 5-syllable words",
        "Spanish adjective forms",
        "Spanish entries with incorrect language header",
        "Spanish non-lemma forms",
        "Spanish terms with IPA pronunciation"
      ],
      "form_of": [
        {
          "word": "abrogatorio"
        }
      ],
      "glosses": [
        "feminine singular of abrogatorio"
      ],
      "links": [
        [
          "abrogatorio",
          "abrogatorio#Spanish"
        ]
      ],
      "tags": [
        "feminine",
        "form-of",
        "singular"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/abɾoɡaˈtoɾja/"
    },
    {
      "ipa": "[a.β̞ɾo.ɣ̞aˈt̪o.ɾja]"
    },
    {
      "rhymes": "-oɾja"
    }
  ],
  "word": "abrogatoria"
}

Download raw JSONL data for abrogatoria meaning in All languages combined (1.5kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-09-22 from the enwiktionary dump dated 2024-09-20 using wiktextract (af5c55c and 66545a6). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.