See Maclaurin series on Wiktionary
{ "etymology_text": "Named after Scottish mathematician Colin Maclaurin (1698-1746), who made extensive use of the series.", "forms": [ { "form": "Maclaurin series", "tags": [ "plural" ] } ], "head_templates": [ { "args": { "1": "Maclaurin series" }, "expansion": "Maclaurin series (plural Maclaurin series)", "name": "en-noun" } ], "lang": "English", "lang_code": "en", "pos": "noun", "senses": [ { "categories": [ { "kind": "other", "name": "English entries with incorrect language header", "parents": [ "Entries with incorrect language header", "Entry maintenance" ], "source": "w" }, { "kind": "other", "name": "Entries with translation boxes", "parents": [], "source": "w" }, { "kind": "other", "name": "Pages with 1 entry", "parents": [], "source": "w" }, { "kind": "other", "name": "Pages with entries", "parents": [], "source": "w" }, { "kind": "other", "name": "Terms with Danish translations", "parents": [], "source": "w" }, { "kind": "other", "name": "Terms with German translations", "parents": [], "source": "w" }, { "kind": "other", "name": "Terms with Italian translations", "parents": [], "source": "w" }, { "kind": "other", "name": "Terms with Japanese translations", "parents": [], "source": "w" }, { "kind": "other", "name": "Terms with Mandarin translations", "parents": [], "source": "w" }, { "kind": "other", "name": "Terms with Romanian translations", "parents": [], "source": "w" }, { "kind": "topical", "langcode": "en", "name": "Calculus", "orig": "en:Calculus", "parents": [ "Mathematical analysis", "Mathematics", "Formal sciences", "Sciences", "All topics", "Fundamental" ], "source": "w" } ], "examples": [ { "ref": "1953, Raymond Lyttleton, The Stability of Rotating Liquid Masses, Paperback edition, Cambridge University Press, published 2013, page 42:", "text": "Analytically there are, of course, two Jacobi series branching off the Maclaurin series, but they are geometrically and physically identical, and involve only an interchange of a and b.", "type": "quote" }, { "text": "1995, Ralph P. Boas, Gerald L. Alexanderson (editor), Dale H. Mugler (editor), Lion Hunting and Other Mathematical Pursuits, Mathematical Association of America, page 88,\nIf the Maclaurin series of f and g converge for |z| < r and g(z) ≠ 0 for 0 ≤ |z| < r, then if the Maclaurin series for f is divided by the Maclaurin series for g by long division (as if the series were polynomials), the resulting series represents f / g for |z| < r." }, { "ref": "1997, Frank Smithies, Cauchy and the Creation of Complex Function Theory, Cambridge University Press, page 203:", "text": "It was almost as a by-product of this work that, in the first Turin memoir, he proved the convergence of the Maclaurin series of a function up to the singularity nearest to the origin (Section 7.5); it was in this context that he created what he called 'calculus of limits', later known as the method of majorants.", "type": "quote" } ], "glosses": [ "Any Taylor series that is centred at 0 (i.e., for which the origin is the reference point used to derive the series from its associated function); for a given infinitely differentiable complex function f, the power series f(0)+(f'(0))/(1!)x+(f(0))/(2!)x²+(f'(0))/(3!)x³+⋯=∑ₙ₌₀ ᪲(f⁽ⁿ⁾(0))/(n!),xⁿ." ], "hypernyms": [ { "sense": "Taylor series centred at 0", "word": "power series" }, { "sense": "Taylor series centred at 0", "word": "Taylor series" } ], "id": "en-Maclaurin_series-en-noun-6emRcdRC", "links": [ [ "calculus", "calculus" ], [ "Taylor series", "Taylor series" ], [ "origin", "origin" ], [ "complex function", "complex function" ], [ "power series", "power series" ] ], "raw_glosses": [ "(calculus) Any Taylor series that is centred at 0 (i.e., for which the origin is the reference point used to derive the series from its associated function); for a given infinitely differentiable complex function f, the power series f(0)+(f'(0))/(1!)x+(f(0))/(2!)x²+(f'(0))/(3!)x³+⋯=∑ₙ₌₀ ᪲(f⁽ⁿ⁾(0))/(n!),xⁿ." ], "topics": [ "calculus", "mathematics", "sciences" ], "translations": [ { "code": "cmn", "lang": "Chinese Mandarin", "sense": "Taylor series centred at 0", "word": "馬克勞林級數" }, { "code": "cmn", "lang": "Chinese Mandarin", "sense": "Taylor series centred at 0", "word": "马克劳林级数" }, { "code": "da", "lang": "Danish", "sense": "Taylor series centred at 0", "word": "Maclaurinrække" }, { "code": "de", "lang": "German", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "Maclaurin-Reihe" }, { "code": "de", "lang": "German", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "maclaurinsche Reihe" }, { "code": "it", "lang": "Italian", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "serie di Maclaurin" }, { "code": "ja", "lang": "Japanese", "sense": "Taylor series centred at 0", "word": "マクローリン級数" }, { "code": "ro", "lang": "Romanian", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "serie Maclaurin" } ], "wikipedia": [ "Colin Maclaurin", "Maclaurin series" ] } ], "word": "Maclaurin series" }
{ "etymology_text": "Named after Scottish mathematician Colin Maclaurin (1698-1746), who made extensive use of the series.", "forms": [ { "form": "Maclaurin series", "tags": [ "plural" ] } ], "head_templates": [ { "args": { "1": "Maclaurin series" }, "expansion": "Maclaurin series (plural Maclaurin series)", "name": "en-noun" } ], "hypernyms": [ { "sense": "Taylor series centred at 0", "word": "power series" }, { "sense": "Taylor series centred at 0", "word": "Taylor series" } ], "lang": "English", "lang_code": "en", "pos": "noun", "senses": [ { "categories": [ "English countable nouns", "English entries with incorrect language header", "English eponyms", "English lemmas", "English multiword terms", "English nouns", "English terms with quotations", "Entries with translation boxes", "Pages with 1 entry", "Pages with entries", "Terms with Danish translations", "Terms with German translations", "Terms with Italian translations", "Terms with Japanese translations", "Terms with Mandarin translations", "Terms with Romanian translations", "en:Calculus" ], "examples": [ { "ref": "1953, Raymond Lyttleton, The Stability of Rotating Liquid Masses, Paperback edition, Cambridge University Press, published 2013, page 42:", "text": "Analytically there are, of course, two Jacobi series branching off the Maclaurin series, but they are geometrically and physically identical, and involve only an interchange of a and b.", "type": "quote" }, { "text": "1995, Ralph P. Boas, Gerald L. Alexanderson (editor), Dale H. Mugler (editor), Lion Hunting and Other Mathematical Pursuits, Mathematical Association of America, page 88,\nIf the Maclaurin series of f and g converge for |z| < r and g(z) ≠ 0 for 0 ≤ |z| < r, then if the Maclaurin series for f is divided by the Maclaurin series for g by long division (as if the series were polynomials), the resulting series represents f / g for |z| < r." }, { "ref": "1997, Frank Smithies, Cauchy and the Creation of Complex Function Theory, Cambridge University Press, page 203:", "text": "It was almost as a by-product of this work that, in the first Turin memoir, he proved the convergence of the Maclaurin series of a function up to the singularity nearest to the origin (Section 7.5); it was in this context that he created what he called 'calculus of limits', later known as the method of majorants.", "type": "quote" } ], "glosses": [ "Any Taylor series that is centred at 0 (i.e., for which the origin is the reference point used to derive the series from its associated function); for a given infinitely differentiable complex function f, the power series f(0)+(f'(0))/(1!)x+(f(0))/(2!)x²+(f'(0))/(3!)x³+⋯=∑ₙ₌₀ ᪲(f⁽ⁿ⁾(0))/(n!),xⁿ." ], "links": [ [ "calculus", "calculus" ], [ "Taylor series", "Taylor series" ], [ "origin", "origin" ], [ "complex function", "complex function" ], [ "power series", "power series" ] ], "raw_glosses": [ "(calculus) Any Taylor series that is centred at 0 (i.e., for which the origin is the reference point used to derive the series from its associated function); for a given infinitely differentiable complex function f, the power series f(0)+(f'(0))/(1!)x+(f(0))/(2!)x²+(f'(0))/(3!)x³+⋯=∑ₙ₌₀ ᪲(f⁽ⁿ⁾(0))/(n!),xⁿ." ], "topics": [ "calculus", "mathematics", "sciences" ], "wikipedia": [ "Colin Maclaurin", "Maclaurin series" ] } ], "translations": [ { "code": "cmn", "lang": "Chinese Mandarin", "sense": "Taylor series centred at 0", "word": "馬克勞林級數" }, { "code": "cmn", "lang": "Chinese Mandarin", "sense": "Taylor series centred at 0", "word": "马克劳林级数" }, { "code": "da", "lang": "Danish", "sense": "Taylor series centred at 0", "word": "Maclaurinrække" }, { "code": "de", "lang": "German", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "Maclaurin-Reihe" }, { "code": "de", "lang": "German", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "maclaurinsche Reihe" }, { "code": "it", "lang": "Italian", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "serie di Maclaurin" }, { "code": "ja", "lang": "Japanese", "sense": "Taylor series centred at 0", "word": "マクローリン級数" }, { "code": "ro", "lang": "Romanian", "sense": "Taylor series centred at 0", "tags": [ "feminine" ], "word": "serie Maclaurin" } ], "word": "Maclaurin series" }
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