"стекольщиков" meaning in All languages combined

See стекольщиков on Wiktionary

Noun [Russian]

IPA: [sʲtʲɪˈkolʲɕːɪkəf] Forms: стеко́льщиков [canonical], stekólʹščikov [romanization]
Head templates: {{head|ru|noun form|g=m-an-p|head=стеко́льщиков}} стеко́льщиков • (stekólʹščikov) m anim pl
  1. genitive/accusative plural of стеко́льщик (stekólʹščik) Tags: accusative, form-of, genitive, plural Form of: стеко́льщик (extra: stekólʹščik)
    Sense id: en-стекольщиков-ru-noun-2YB8jESw Categories (other): Russian entries with incorrect language header

Download JSONL data for стекольщиков meaning in All languages combined (1.0kB)

{
  "forms": [
    {
      "form": "стеко́льщиков",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "stekólʹščikov",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "noun form",
        "g": "m-an-p",
        "head": "стеко́льщиков"
      },
      "expansion": "стеко́льщиков • (stekólʹščikov) m anim pl",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Russian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "extra": "stekólʹščik",
          "word": "стеко́льщик"
        }
      ],
      "glosses": [
        "genitive/accusative plural of стеко́льщик (stekólʹščik)"
      ],
      "id": "en-стекольщиков-ru-noun-2YB8jESw",
      "links": [
        [
          "стеко́льщик",
          "стекольщик#Russian"
        ]
      ],
      "tags": [
        "accusative",
        "form-of",
        "genitive",
        "plural"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[sʲtʲɪˈkolʲɕːɪkəf]"
    }
  ],
  "word": "стекольщиков"
}
{
  "forms": [
    {
      "form": "стеко́льщиков",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "stekólʹščikov",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "noun form",
        "g": "m-an-p",
        "head": "стеко́льщиков"
      },
      "expansion": "стеко́льщиков • (stekólʹščikov) m anim pl",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "Russian 4-syllable words",
        "Russian entries with incorrect language header",
        "Russian non-lemma forms",
        "Russian noun forms",
        "Russian terms with IPA pronunciation"
      ],
      "form_of": [
        {
          "extra": "stekólʹščik",
          "word": "стеко́льщик"
        }
      ],
      "glosses": [
        "genitive/accusative plural of стеко́льщик (stekólʹščik)"
      ],
      "links": [
        [
          "стеко́льщик",
          "стекольщик#Russian"
        ]
      ],
      "tags": [
        "accusative",
        "form-of",
        "genitive",
        "plural"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[sʲtʲɪˈkolʲɕːɪkəf]"
    }
  ],
  "word": "стекольщиков"
}

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-07-01 from the enwiktionary dump dated 2024-06-20 using wiktextract (e79c026 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.