See зомбировав on Wiktionary
{
"forms": [
{
"form": "зомби́ровав",
"tags": [
"canonical"
]
},
{
"form": "zombírovav",
"tags": [
"romanization"
]
}
],
"head_templates": [
{
"args": {
"1": "ru",
"2": "past adverbial participle",
"head": "зомби́ровав"
},
"expansion": "зомби́ровав • (zombírovav)",
"name": "head"
}
],
"lang": "Russian",
"lang_code": "ru",
"pos": "verb",
"senses": [
{
"categories": [
{
"_dis": "50 50",
"kind": "other",
"name": "Pages with 1 entry",
"parents": [],
"source": "w+disamb"
},
{
"_dis": "50 50",
"kind": "other",
"name": "Pages with entries",
"parents": [],
"source": "w+disamb"
},
{
"_dis": "50 50",
"kind": "other",
"name": "Russian entries with incorrect language header",
"parents": [],
"source": "w+disamb"
}
],
"form_of": [
{
"extra": "zombírovatʹ",
"word": "зомби́ровать"
}
],
"glosses": [
"short past adverbial imperfective participle of зомби́ровать (zombírovatʹ)"
],
"id": "en-зомбировав-ru-verb-KMtDYqrc",
"links": [
[
"зомби́ровать",
"зомбировать#Russian"
]
],
"tags": [
"adverbial",
"form-of",
"imperfective",
"participle",
"past",
"short-form"
]
},
{
"categories": [
{
"_dis": "50 50",
"kind": "other",
"name": "Pages with 1 entry",
"parents": [],
"source": "w+disamb"
},
{
"_dis": "50 50",
"kind": "other",
"name": "Pages with entries",
"parents": [],
"source": "w+disamb"
},
{
"_dis": "50 50",
"kind": "other",
"name": "Russian entries with incorrect language header",
"parents": [],
"source": "w+disamb"
}
],
"form_of": [
{
"extra": "zombírovatʹ",
"word": "зомби́ровать"
}
],
"glosses": [
"short past adverbial perfective participle of зомби́ровать (zombírovatʹ)"
],
"id": "en-зомбировав-ru-verb-ZOC5kC4B",
"links": [
[
"зомби́ровать",
"зомбировать#Russian"
]
],
"tags": [
"adverbial",
"form-of",
"participle",
"past",
"perfective",
"short-form"
]
}
],
"sounds": [
{
"ipa": "[zɐm⁽ʲ⁾ˈbʲirəvəf]"
}
],
"word": "зомбировав"
}
{
"categories": [
"Pages with 1 entry",
"Pages with entries",
"Russian 4-syllable words",
"Russian entries with incorrect language header",
"Russian non-lemma forms",
"Russian past adverbial participles",
"Russian terms with IPA pronunciation"
],
"forms": [
{
"form": "зомби́ровав",
"tags": [
"canonical"
]
},
{
"form": "zombírovav",
"tags": [
"romanization"
]
}
],
"head_templates": [
{
"args": {
"1": "ru",
"2": "past adverbial participle",
"head": "зомби́ровав"
},
"expansion": "зомби́ровав • (zombírovav)",
"name": "head"
}
],
"lang": "Russian",
"lang_code": "ru",
"pos": "verb",
"senses": [
{
"form_of": [
{
"extra": "zombírovatʹ",
"word": "зомби́ровать"
}
],
"glosses": [
"short past adverbial imperfective participle of зомби́ровать (zombírovatʹ)"
],
"links": [
[
"зомби́ровать",
"зомбировать#Russian"
]
],
"tags": [
"adverbial",
"form-of",
"imperfective",
"participle",
"past",
"short-form"
]
},
{
"form_of": [
{
"extra": "zombírovatʹ",
"word": "зомби́ровать"
}
],
"glosses": [
"short past adverbial perfective participle of зомби́ровать (zombírovatʹ)"
],
"links": [
[
"зомби́ровать",
"зомбировать#Russian"
]
],
"tags": [
"adverbial",
"form-of",
"participle",
"past",
"perfective",
"short-form"
]
}
],
"sounds": [
{
"ipa": "[zɐm⁽ʲ⁾ˈbʲirəvəf]"
}
],
"word": "зомбировав"
}
Download raw JSONL data for зомбировав meaning in All languages combined (1.4kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-07-20 from the enwiktionary dump dated 2025-07-01 using wiktextract (45c4a21 and f1c2b61). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.