"вздоров" meaning in All languages combined

See вздоров on Wiktionary

Noun [Russian]

IPA: [ˈvzdorəf] Forms: вздо́ров [canonical], vzdórov [romanization]
Head templates: {{head|ru|noun form|g=m-in-p|head=вздо́ров}} вздо́ров • (vzdórov) m inan pl
  1. genitive plural of вздор (vzdor) Tags: form-of, genitive, plural Form of: вздор (extra: vzdor)
    Sense id: en-вздоров-ru-noun-7r~MGuaE Categories (other): Pages with 1 entry, Pages with entries, Russian entries with incorrect language header
{
  "forms": [
    {
      "form": "вздо́ров",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "vzdórov",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "noun form",
        "g": "m-in-p",
        "head": "вздо́ров"
      },
      "expansion": "вздо́ров • (vzdórov) m inan pl",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Russian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "extra": "vzdor",
          "word": "вздор"
        }
      ],
      "glosses": [
        "genitive plural of вздор (vzdor)"
      ],
      "id": "en-вздоров-ru-noun-7r~MGuaE",
      "links": [
        [
          "вздор",
          "вздор#Russian"
        ]
      ],
      "tags": [
        "form-of",
        "genitive",
        "plural"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈvzdorəf]"
    }
  ],
  "word": "вздоров"
}
{
  "forms": [
    {
      "form": "вздо́ров",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "vzdórov",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "noun form",
        "g": "m-in-p",
        "head": "вздо́ров"
      },
      "expansion": "вздо́ров • (vzdórov) m inan pl",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "Pages with 1 entry",
        "Pages with entries",
        "Russian 2-syllable words",
        "Russian entries with incorrect language header",
        "Russian non-lemma forms",
        "Russian noun forms",
        "Russian terms with IPA pronunciation"
      ],
      "form_of": [
        {
          "extra": "vzdor",
          "word": "вздор"
        }
      ],
      "glosses": [
        "genitive plural of вздор (vzdor)"
      ],
      "links": [
        [
          "вздор",
          "вздор#Russian"
        ]
      ],
      "tags": [
        "form-of",
        "genitive",
        "plural"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈvzdorəf]"
    }
  ],
  "word": "вздоров"
}

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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-08 from the enwiktionary dump dated 2024-12-04 using wiktextract (bb46d54 and 0c3c9f6). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.