"auzit" meaning in 羅馬尼亞語

See auzit in All languages combined, or Wiktionary

Noun

IPA: [a.uˈzit]
Etymology: auzi 的過去分詞,或繼承自拉丁語 audītus。對照意大利語 udito、葡萄牙語 ouvido、西班牙語 oído。
  1. 聽覺
    Sense id: zh-auzit-ro-noun-Awh494lK
The following are not (yet) sense-disambiguated
Synonyms: auz, auzire

Verb

IPA: [a.uˈzit]
Etymology: auzi 的過去分詞,或繼承自拉丁語 audītus。對照意大利語 udito、葡萄牙語 ouvido、西班牙語 oído。
  1. auzi 的過去時分詞 Tags: form-of Form of: auzi
    Sense id: zh-auzit-ro-verb-yqxgdWfz
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自拉丁語的羅馬尼亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自拉丁語的羅馬尼亞語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語過去分詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語非詞元形式",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "auzi 的過去分詞,或繼承自拉丁語 audītus。對照意大利語 udito、葡萄牙語 ouvido、西班牙語 oído。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "auzi"
        }
      ],
      "glosses": [
        "auzi 的過去時分詞"
      ],
      "id": "zh-auzit-ro-verb-yqxgdWfz",
      "tags": [
        "form-of"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[a.uˈzit]"
    }
  ],
  "word": "auzit"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自拉丁語的羅馬尼亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自拉丁語的羅馬尼亞語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "auzi 的過去分詞,或繼承自拉丁語 audītus。對照意大利語 udito、葡萄牙語 ouvido、西班牙語 oído。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "聽覺"
      ],
      "id": "zh-auzit-ro-noun-Awh494lK"
    }
  ],
  "sounds": [
    {
      "ipa": "[a.uˈzit]"
    }
  ],
  "synonyms": [
    {
      "word": "auz"
    },
    {
      "word": "auzire"
    }
  ],
  "tags": [
    "neuter"
  ],
  "word": "auzit"
}
{
  "categories": [
    "有1個詞條的頁面",
    "派生自拉丁語的羅馬尼亞語詞",
    "源自拉丁語的羅馬尼亞語繼承詞",
    "羅馬尼亞語過去分詞",
    "羅馬尼亞語非詞元形式"
  ],
  "etymology_text": "auzi 的過去分詞,或繼承自拉丁語 audītus。對照意大利語 udito、葡萄牙語 ouvido、西班牙語 oído。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "auzi"
        }
      ],
      "glosses": [
        "auzi 的過去時分詞"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[a.uˈzit]"
    }
  ],
  "word": "auzit"
}

{
  "categories": [
    "有1個詞條的頁面",
    "派生自拉丁語的羅馬尼亞語詞",
    "源自拉丁語的羅馬尼亞語繼承詞",
    "羅馬尼亞語名詞",
    "羅馬尼亞語詞元"
  ],
  "etymology_text": "auzi 的過去分詞,或繼承自拉丁語 audītus。對照意大利語 udito、葡萄牙語 ouvido、西班牙語 oído。",
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "聽覺"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[a.uˈzit]"
    }
  ],
  "synonyms": [
    {
      "word": "auz"
    },
    {
      "word": "auzire"
    }
  ],
  "tags": [
    "neuter"
  ],
  "word": "auzit"
}

Download raw JSONL data for auzit meaning in 羅馬尼亞語 (1.1kB)


This page is a part of the kaikki.org machine-readable 羅馬尼亞語 dictionary. This dictionary is based on structured data extracted on 2024-10-03 from the zhwiktionary dump dated 2024-10-02 using wiktextract (593e81e and 59b8406). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.