"noksansız" meaning in 土耳其語

See noksansız in All languages combined, or Wiktionary

Adjective

  1. 完美的,沒有缺陷的
    Sense id: zh-noksansız-tr-adj-IZumeyl1
The following are not (yet) sense-disambiguated
Synonyms (完美的,沒有缺陷的): eksiksiz
{
  "categories": [
    {
      "kind": "other",
      "name": "土耳其語形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "土耳其語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "土耳其語",
  "lang_code": "tr",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "完美的,沒有缺陷的"
      ],
      "id": "zh-noksansız-tr-adj-IZumeyl1"
    }
  ],
  "synonyms": [
    {
      "sense": "完美的,沒有缺陷的",
      "word": "eksiksiz"
    }
  ],
  "word": "noksansız"
}
{
  "categories": [
    "土耳其語形容詞",
    "土耳其語詞元",
    "有1個詞條的頁面"
  ],
  "lang": "土耳其語",
  "lang_code": "tr",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "完美的,沒有缺陷的"
      ]
    }
  ],
  "synonyms": [
    {
      "sense": "完美的,沒有缺陷的",
      "word": "eksiksiz"
    }
  ],
  "word": "noksansız"
}

Download raw JSONL data for noksansız meaning in 土耳其語 (0.3kB)


This page is a part of the kaikki.org machine-readable 土耳其語 dictionary. This dictionary is based on structured data extracted on 2024-11-05 from the zhwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.