See seaborgio on Wiktionary
{
"categories": [
{
"kind": "other",
"name": "含有後綴-io的意大利語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語可數名詞",
"parents": [],
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},
{
"kind": "other",
"name": "意大利語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語陽性名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有3個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
}
],
"etymology_text": "Seaborg + -io",
"forms": [
{
"form": "seaborgi",
"tags": [
"plural"
]
}
],
"lang": "意大利語",
"lang_code": "it",
"pos": "noun",
"pos_title": "名詞",
"senses": [
{
"glosses": [
"𨭎"
],
"id": "zh-seaborgio-it-noun-KxjKJ-CU",
"raw_tags": [
"化"
]
}
],
"sounds": [
{
"ipa": "/seaˈbɔrdʒo/"
}
],
"tags": [
"masculine"
],
"word": "seaborgio"
}
{
"categories": [
{
"kind": "other",
"name": "拉丁語名詞變格形",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "拉丁語非詞元形式",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有3個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
}
],
"lang": "拉丁語",
"lang_code": "la",
"pos": "noun",
"pos_title": "名詞",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "詞元形式為紅鏈的屈折",
"parents": [],
"source": "w"
}
],
"form_of": [
{
"word": "seaborgium"
}
],
"glosses": [
"seaborgium 的與格單數"
],
"id": "zh-seaborgio-la-noun-QYMLYpx3",
"tags": [
"form-of"
]
},
{
"categories": [
{
"kind": "other",
"name": "詞元形式為紅鏈的屈折",
"parents": [],
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],
"form_of": [
{
"word": "seaborgium"
}
],
"glosses": [
"seaborgium 的奪格單數"
],
"id": "zh-seaborgio-la-noun-aAIQmNY-",
"tags": [
"form-of"
]
}
],
"word": "seaborgio"
}
{
"categories": [
{
"kind": "other",
"name": "含有後綴-io的西班牙語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有3個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "西班牙語不可數名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "西班牙語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "西班牙語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "西班牙語陽性名詞",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自Seaborg + -io，以美國核化學家Glenn Seaborg命名。",
"lang": "西班牙語",
"lang_code": "es",
"pos": "noun",
"pos_title": "名詞",
"senses": [
{
"glosses": [
"𨭎"
],
"id": "zh-seaborgio-es-noun-KxjKJ-CU"
}
],
"sounds": [
{
"ipa": "/sea̯.ˈβoɾ.xjo/"
},
{
"audio": "LL-Q1321 (spa)-Millars-seaborgio.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/49/LL-Q1321_(spa)-Millars-seaborgio.wav/LL-Q1321_(spa)-Millars-seaborgio.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/49/LL-Q1321_(spa)-Millars-seaborgio.wav/LL-Q1321_(spa)-Millars-seaborgio.wav.ogg",
"raw_tags": [
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"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1321 (spa)-Millars-seaborgio.wav"
}
],
"tags": [
"masculine",
"uncountable"
],
"word": "seaborgio"
}
{
"categories": [
"含有後綴-io的意大利語詞",
"意大利語可數名詞",
"意大利語名詞",
"意大利語詞元",
"意大利語陽性名詞",
"有3個詞條的頁面",
"有詞條的頁面"
],
"etymology_text": "Seaborg + -io",
"forms": [
{
"form": "seaborgi",
"tags": [
"plural"
]
}
],
"lang": "意大利語",
"lang_code": "it",
"pos": "noun",
"pos_title": "名詞",
"senses": [
{
"glosses": [
"𨭎"
],
"raw_tags": [
"化"
]
}
],
"sounds": [
{
"ipa": "/seaˈbɔrdʒo/"
}
],
"tags": [
"masculine"
],
"word": "seaborgio"
}
{
"categories": [
"拉丁語名詞變格形",
"拉丁語非詞元形式",
"有3個詞條的頁面",
"有詞條的頁面"
],
"lang": "拉丁語",
"lang_code": "la",
"pos": "noun",
"pos_title": "名詞",
"senses": [
{
"categories": [
"詞元形式為紅鏈的屈折"
],
"form_of": [
{
"word": "seaborgium"
}
],
"glosses": [
"seaborgium 的與格單數"
],
"tags": [
"form-of"
]
},
{
"categories": [
"詞元形式為紅鏈的屈折"
],
"form_of": [
{
"word": "seaborgium"
}
],
"glosses": [
"seaborgium 的奪格單數"
],
"tags": [
"form-of"
]
}
],
"word": "seaborgio"
}
{
"categories": [
"含有後綴-io的西班牙語詞",
"有3個詞條的頁面",
"有詞條的頁面",
"西班牙語不可數名詞",
"西班牙語名詞",
"西班牙語詞元",
"西班牙語陽性名詞"
],
"etymology_text": "源自Seaborg + -io，以美國核化學家Glenn Seaborg命名。",
"lang": "西班牙語",
"lang_code": "es",
"pos": "noun",
"pos_title": "名詞",
"senses": [
{
"glosses": [
"𨭎"
]
}
],
"sounds": [
{
"ipa": "/sea̯.ˈβoɾ.xjo/"
},
{
"audio": "LL-Q1321 (spa)-Millars-seaborgio.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/49/LL-Q1321_(spa)-Millars-seaborgio.wav/LL-Q1321_(spa)-Millars-seaborgio.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/49/LL-Q1321_(spa)-Millars-seaborgio.wav/LL-Q1321_(spa)-Millars-seaborgio.wav.ogg",
"raw_tags": [
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"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1321 (spa)-Millars-seaborgio.wav"
}
],
"tags": [
"masculine",
"uncountable"
],
"word": "seaborgio"
}
Download raw JSONL data for seaborgio meaning in All languages combined (2.0kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-03-03 from the zhwiktionary dump dated 2025-03-02 using wiktextract (7dd5d20 and 5a03470). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.