"păstra" meaning in All languages combined

See păstra on Wiktionary

Verb [羅馬尼亞語]

IPA: /pəsˈtra/ Audio: LL-Q7913 (ron)-Filosoful-păstra.wav Forms: păstrează, păstrat
Etymology: 源自希臘語 παστρεύω (pastrévo),可能經由保加利亞語 пастря (pastrja)傳入。對照阿爾巴尼亞語 pastroj、阿羅馬尼亞語 pãstrescu、spãstrescu。另一種認為來自拉丁語 *parsitāre 的說法不大可能。
  1. 保持,維持 Tags: transitive
    Sense id: zh-păstra-ro-verb-RBd9hS7r
The following are not (yet) sense-disambiguated
Derived forms: păstrare, păstrător

Download JSONL data for păstra meaning in All languages combined (1.6kB)

{
  "categories": [
    {
      "kind": "other",
      "name": "派生自保加利亞語的羅馬尼亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自希臘語的羅馬尼亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語動詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語第一類變位動詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "păstrare"
    },
    {
      "word": "păstrător"
    }
  ],
  "etymology_text": "源自希臘語 παστρεύω (pastrévo),可能經由保加利亞語 пастря (pastrja)傳入。對照阿爾巴尼亞語 pastroj、阿羅馬尼亞語 pãstrescu、spãstrescu。另一種認為來自拉丁語 *parsitāre 的說法不大可能。",
  "forms": [
    {
      "form": "păstrează",
      "raw_tags": [
        "第三人稱單數現在式"
      ]
    },
    {
      "form": "păstrat",
      "raw_tags": [
        "過去分詞"
      ]
    }
  ],
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "保持,維持"
      ],
      "id": "zh-păstra-ro-verb-RBd9hS7r",
      "tags": [
        "transitive"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/pəsˈtra/"
    },
    {
      "audio": "LL-Q7913 (ron)-Filosoful-păstra.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f3/LL-Q7913_(ron)-Filosoful-păstra.wav/LL-Q7913_(ron)-Filosoful-păstra.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f3/LL-Q7913_(ron)-Filosoful-păstra.wav/LL-Q7913_(ron)-Filosoful-păstra.wav.ogg",
      "raw_tags": [
        "音頻"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q7913 (ron)-Filosoful-păstra.wav"
    }
  ],
  "word": "păstra"
}
{
  "categories": [
    "派生自保加利亞語的羅馬尼亞語詞",
    "派生自希臘語的羅馬尼亞語詞",
    "羅馬尼亞語動詞",
    "羅馬尼亞語第一類變位動詞",
    "羅馬尼亞語詞元"
  ],
  "derived": [
    {
      "word": "păstrare"
    },
    {
      "word": "păstrător"
    }
  ],
  "etymology_text": "源自希臘語 παστρεύω (pastrévo),可能經由保加利亞語 пастря (pastrja)傳入。對照阿爾巴尼亞語 pastroj、阿羅馬尼亞語 pãstrescu、spãstrescu。另一種認為來自拉丁語 *parsitāre 的說法不大可能。",
  "forms": [
    {
      "form": "păstrează",
      "raw_tags": [
        "第三人稱單數現在式"
      ]
    },
    {
      "form": "păstrat",
      "raw_tags": [
        "過去分詞"
      ]
    }
  ],
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "保持,維持"
      ],
      "tags": [
        "transitive"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/pəsˈtra/"
    },
    {
      "audio": "LL-Q7913 (ron)-Filosoful-păstra.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f3/LL-Q7913_(ron)-Filosoful-păstra.wav/LL-Q7913_(ron)-Filosoful-păstra.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f3/LL-Q7913_(ron)-Filosoful-păstra.wav/LL-Q7913_(ron)-Filosoful-păstra.wav.ogg",
      "raw_tags": [
        "音頻"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q7913 (ron)-Filosoful-păstra.wav"
    }
  ],
  "word": "păstra"
}

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-07-01 from the zhwiktionary dump dated 2024-06-20 using wiktextract (e79c026 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.