"oord" meaning in All languages combined

See oord on Wiktionary

Noun [英语]

  1. urad的古旧形式。 Tags: form-of Form of: urad
    Sense id: zh-oord-en-noun-LWSM7CNZ Categories (other): 英語古舊形式
The following are not (yet) sense-disambiguated

Noun [荷兰语]

IPA: /oːrt/ Audio: Nl-oord.ogg Forms: oorden [plural], oordje [neuter, diminutive]
Etymology: 源自中古荷蘭語 ort、oort,源自古荷蘭語 ort,源自原始西日耳曼語 *oʀd,源自原始日耳曼語 *uzdaz。
  1. 地方
    Sense id: zh-oord-nl-noun-FGKn2FMe
  2. 地區,區域
    Sense id: zh-oord-nl-noun-YUsFoUAn
The following are not (yet) sense-disambiguated
Derived forms: bedevaartsoord, droomoord

Download JSONL data for oord meaning in All languages combined (2.4kB)

{
  "categories": [
    {
      "kind": "other",
      "name": "英語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "英语",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "英語古舊形式",
          "parents": [],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "word": "urad"
        }
      ],
      "glosses": [
        "urad的古旧形式。"
      ],
      "id": "zh-oord-en-noun-LWSM7CNZ",
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "uncountable"
  ],
  "word": "oord"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "派生自中古荷蘭語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始西日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古荷蘭語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自中古荷蘭語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始西日耳曼語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古荷蘭語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語中性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "bedevaartsoord"
    },
    {
      "word": "droomoord"
    }
  ],
  "etymology_text": "源自中古荷蘭語 ort、oort,源自古荷蘭語 ort,源自原始西日耳曼語 *oʀd,源自原始日耳曼語 *uzdaz。",
  "forms": [
    {
      "form": "oorden",
      "tags": [
        "plural"
      ]
    },
    {
      "form": "oordje",
      "tags": [
        "neuter",
        "diminutive"
      ]
    }
  ],
  "lang": "荷兰语",
  "lang_code": "nl",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "地方"
      ],
      "id": "zh-oord-nl-noun-FGKn2FMe"
    },
    {
      "glosses": [
        "地區,區域"
      ],
      "id": "zh-oord-nl-noun-YUsFoUAn"
    }
  ],
  "sounds": [
    {
      "ipa": "/oːrt/"
    },
    {
      "audio": "Nl-oord.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/2/28/Nl-oord.ogg/Nl-oord.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-oord.ogg",
      "raw_tags": [
        "音频"
      ]
    }
  ],
  "tags": [
    "neuter"
  ],
  "word": "oord"
}
{
  "categories": [
    "英語不可數名詞",
    "英語名詞",
    "英語詞元"
  ],
  "lang": "英语",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "英語古舊形式"
      ],
      "form_of": [
        {
          "word": "urad"
        }
      ],
      "glosses": [
        "urad的古旧形式。"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "uncountable"
  ],
  "word": "oord"
}

{
  "categories": [
    "派生自中古荷蘭語的荷蘭語詞",
    "派生自原始日耳曼語的荷蘭語詞",
    "派生自原始西日耳曼語的荷蘭語詞",
    "派生自古荷蘭語的荷蘭語詞",
    "源自中古荷蘭語的荷蘭語繼承詞",
    "源自原始日耳曼語的荷蘭語繼承詞",
    "源自原始西日耳曼語的荷蘭語繼承詞",
    "源自古荷蘭語的荷蘭語繼承詞",
    "荷蘭語中性名詞",
    "荷蘭語名詞",
    "荷蘭語詞元"
  ],
  "derived": [
    {
      "word": "bedevaartsoord"
    },
    {
      "word": "droomoord"
    }
  ],
  "etymology_text": "源自中古荷蘭語 ort、oort,源自古荷蘭語 ort,源自原始西日耳曼語 *oʀd,源自原始日耳曼語 *uzdaz。",
  "forms": [
    {
      "form": "oorden",
      "tags": [
        "plural"
      ]
    },
    {
      "form": "oordje",
      "tags": [
        "neuter",
        "diminutive"
      ]
    }
  ],
  "lang": "荷兰语",
  "lang_code": "nl",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "地方"
      ]
    },
    {
      "glosses": [
        "地區,區域"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/oːrt/"
    },
    {
      "audio": "Nl-oord.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/2/28/Nl-oord.ogg/Nl-oord.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-oord.ogg",
      "raw_tags": [
        "音频"
      ]
    }
  ],
  "tags": [
    "neuter"
  ],
  "word": "oord"
}

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-07-01 from the zhwiktionary dump dated 2024-06-20 using wiktextract (e79c026 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.