See heroina on Wiktionary
{
"categories": [
{
"kind": "other",
"name": "有5個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "芬蘭語名詞變格形",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "芬蘭語非詞元形式",
"parents": [],
"source": "w"
}
],
"lang": "芬蘭語",
"lang_code": "fi",
"pos": "noun",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "芬蘭語紅鏈",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "芬蘭語紅鏈/m",
"parents": [],
"source": "w"
}
],
"form_of": [
{
"word": "hera"
}
],
"glosses": [
"hera 的向格复数形式。"
],
"id": "zh-heroina-fi-noun-q1RbkplK",
"tags": [
"form-of"
]
}
],
"word": "heroina"
}
{
"categories": [
{
"kind": "other",
"name": "意大利語可數名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有5個詞條的頁面",
"parents": [],
"source": "w"
}
],
"forms": [
{
"form": "heroine",
"tags": [
"plural"
]
},
{
"form": "heroe",
"tags": [
"masculine"
]
}
],
"lang": "意大利語",
"lang_code": "it",
"pos": "noun",
"senses": [
{
"alt_of": [
{
"word": "eroina"
}
],
"categories": [
{
"kind": "other",
"name": "有棄用詞義的意大利語詞",
"parents": [],
"source": "w"
}
],
"glosses": [
"(棄用) eroina的另一種拼寫法"
],
"id": "zh-heroina-it-noun-6H8o6naS",
"tags": [
"alt-of"
]
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
{
"kind": "other",
"name": "拉丁語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "拉丁語第一類變格名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "拉丁語第一類變格陰性名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "拉丁語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "拉丁語陰性名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有5個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古希臘語的拉丁語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自古希臘語的拉丁語借詞",
"parents": [],
"source": "w"
}
],
"descendants": [
{
"lang": "英語",
"lang_code": "en",
"word": "heroine"
},
{
"lang": "德語",
"lang_code": "de",
"word": "Heroin"
}
],
"etymology_text": "借自古希臘語 ἡρωίνη (hērōínē)。",
"forms": [
{
"form": "hērōīnae",
"raw_tags": [
"属格"
]
}
],
"lang": "拉丁語",
"lang_code": "la",
"pos": "noun",
"senses": [
{
"glosses": [
"女性半神半人"
],
"id": "zh-heroina-la-noun-MFNyc1vh"
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
{
"kind": "other",
"name": "有5個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "波蘭語 娛樂性藥物",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "波蘭語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "波蘭語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自德語的波蘭語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自德語的波蘭語借詞",
"parents": [],
"source": "w"
}
],
"derived": [
{
"word": "heroinowy"
}
],
"etymology_text": "借自德語 Heroin。",
"forms": [
{
"form": "heroinowy",
"raw_tags": [
"相關形容詞"
]
}
],
"lang": "波蘭語",
"lang_code": "pl",
"pos": "noun",
"senses": [
{
"glosses": [
"海洛因"
],
"id": "zh-heroina-pl-noun-aci5kqWL"
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
{
"kind": "other",
"name": "塞爾維亞-克羅地亞語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "塞爾維亞-克羅地亞語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "塞爾維亞-克羅地亞語陰性名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有5個詞條的頁面",
"parents": [],
"source": "w"
}
],
"forms": [
{
"form": "херои́на",
"raw_tags": [
"西里爾字母拼寫"
]
}
],
"lang": "塞爾維亞-克羅地亞語",
"lang_code": "sh",
"pos": "noun",
"senses": [
{
"glosses": [
"女英雄"
],
"id": "zh-heroina-sh-noun-IVJJTy1J"
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
"塞爾維亞-克羅地亞語名詞",
"塞爾維亞-克羅地亞語詞元",
"塞爾維亞-克羅地亞語陰性名詞",
"有5個詞條的頁面"
],
"forms": [
{
"form": "херои́на",
"raw_tags": [
"西里爾字母拼寫"
]
}
],
"lang": "塞爾維亞-克羅地亞語",
"lang_code": "sh",
"pos": "noun",
"senses": [
{
"glosses": [
"女英雄"
]
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
"意大利語可數名詞",
"意大利語名詞",
"意大利語詞元",
"有5個詞條的頁面"
],
"forms": [
{
"form": "heroine",
"tags": [
"plural"
]
},
{
"form": "heroe",
"tags": [
"masculine"
]
}
],
"lang": "意大利語",
"lang_code": "it",
"pos": "noun",
"senses": [
{
"alt_of": [
{
"word": "eroina"
}
],
"categories": [
"有棄用詞義的意大利語詞"
],
"glosses": [
"(棄用) eroina的另一種拼寫法"
],
"tags": [
"alt-of"
]
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
"拉丁語名詞",
"拉丁語第一類變格名詞",
"拉丁語第一類變格陰性名詞",
"拉丁語詞元",
"拉丁語陰性名詞",
"有5個詞條的頁面",
"派生自古希臘語的拉丁語詞",
"源自古希臘語的拉丁語借詞"
],
"descendants": [
{
"lang": "英語",
"lang_code": "en",
"word": "heroine"
},
{
"lang": "德語",
"lang_code": "de",
"word": "Heroin"
}
],
"etymology_text": "借自古希臘語 ἡρωίνη (hērōínē)。",
"forms": [
{
"form": "hērōīnae",
"raw_tags": [
"属格"
]
}
],
"lang": "拉丁語",
"lang_code": "la",
"pos": "noun",
"senses": [
{
"glosses": [
"女性半神半人"
]
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
"有5個詞條的頁面",
"波蘭語 娛樂性藥物",
"波蘭語名詞",
"波蘭語詞元",
"派生自德語的波蘭語詞",
"源自德語的波蘭語借詞"
],
"derived": [
{
"word": "heroinowy"
}
],
"etymology_text": "借自德語 Heroin。",
"forms": [
{
"form": "heroinowy",
"raw_tags": [
"相關形容詞"
]
}
],
"lang": "波蘭語",
"lang_code": "pl",
"pos": "noun",
"senses": [
{
"glosses": [
"海洛因"
]
}
],
"tags": [
"feminine"
],
"word": "heroina"
}
{
"categories": [
"有5個詞條的頁面",
"芬蘭語名詞變格形",
"芬蘭語非詞元形式"
],
"lang": "芬蘭語",
"lang_code": "fi",
"pos": "noun",
"senses": [
{
"categories": [
"芬蘭語紅鏈",
"芬蘭語紅鏈/m"
],
"form_of": [
{
"word": "hera"
}
],
"glosses": [
"hera 的向格复数形式。"
],
"tags": [
"form-of"
]
}
],
"word": "heroina"
}
Download raw JSONL data for heroina meaning in All languages combined (2.3kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-09-27 from the zhwiktionary dump dated 2024-09-20 using wiktextract (3f344ef and 66545a6). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.