See heroala on Wiktionary
Download JSONL data for heroala meaning in All languages combined (0.5kB)
{
"categories": [
{
"kind": "other",
"name": "伊多語形容詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "伊多語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "含有後綴-ala的伊多語詞",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自 heroo + -ala。",
"lang": "伊多語",
"lang_code": "io",
"pos": "adj",
"senses": [
{
"glosses": [
"英雄的"
],
"id": "zh-heroala-io-adj-CYhsnveN"
}
],
"synonyms": [
{
"sense": "英雄的",
"word": "heroatra"
}
],
"word": "heroala"
}
{
"categories": [
"伊多語形容詞",
"伊多語詞元",
"含有後綴-ala的伊多語詞"
],
"etymology_text": "源自 heroo + -ala。",
"lang": "伊多語",
"lang_code": "io",
"pos": "adj",
"senses": [
{
"glosses": [
"英雄的"
]
}
],
"synonyms": [
{
"sense": "英雄的",
"word": "heroatra"
}
],
"word": "heroala"
}
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-07-01 from the zhwiktionary dump dated 2024-06-20 using wiktextract (e79c026 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.