"hartz" meaning in All languages combined

See hartz on Wiktionary

Noun [巴斯克語]

Audio: Eus-hartz.ogg
Etymology: (1330年) 源自原始巴斯克語 *har̄c,來源不明。可能源自高盧語 artos (“熊”) ← 原始印歐語 *h₂ŕ̥tḱos (“熊”)。可能與阿基坦語男子名Harsus有關。
  1. Sense id: zh-hartz-eu-noun-zldqqAis
The following are not (yet) sense-disambiguated
Synonyms: artz Derived forms: azkonar
{
  "categories": [
    {
      "kind": "other",
      "name": "巴斯克語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "巴斯克語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始印歐語的巴斯克語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始巴斯克語的巴斯克語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自高盧語的巴斯克語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始巴斯克語的巴斯克語繼承詞",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "azkonar"
    }
  ],
  "etymology_text": "(1330年) 源自原始巴斯克語 *har̄c,來源不明。可能源自高盧語 artos (“熊”) ← 原始印歐語 *h₂ŕ̥tḱos (“熊”)。可能與阿基坦語男子名Harsus有關。",
  "lang": "巴斯克語",
  "lang_code": "eu",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "熊"
      ],
      "id": "zh-hartz-eu-noun-zldqqAis"
    }
  ],
  "sounds": [
    {
      "audio": "Eus-hartz.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a6/Eus-hartz.ogg/Eus-hartz.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Eus-hartz.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "synonyms": [
    {
      "word": "artz"
    }
  ],
  "word": "hartz"
}
{
  "categories": [
    "巴斯克語名詞",
    "巴斯克語詞元",
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自原始印歐語的巴斯克語詞",
    "派生自原始巴斯克語的巴斯克語詞",
    "派生自高盧語的巴斯克語詞",
    "源自原始巴斯克語的巴斯克語繼承詞"
  ],
  "derived": [
    {
      "word": "azkonar"
    }
  ],
  "etymology_text": "(1330年) 源自原始巴斯克語 *har̄c,來源不明。可能源自高盧語 artos (“熊”) ← 原始印歐語 *h₂ŕ̥tḱos (“熊”)。可能與阿基坦語男子名Harsus有關。",
  "lang": "巴斯克語",
  "lang_code": "eu",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "熊"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "Eus-hartz.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a6/Eus-hartz.ogg/Eus-hartz.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Eus-hartz.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "synonyms": [
    {
      "word": "artz"
    }
  ],
  "word": "hartz"
}

Download raw JSONL data for hartz meaning in All languages combined (0.9kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-01-10 from the zhwiktionary dump dated 2025-01-01 using wiktextract (df33d17 and 4ed51a5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.