See groda on Wiktionary
{
"categories": [
{
"kind": "other",
"name": "下索布語名詞變格形",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "下索布語非詞元形式",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有2個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
}
],
"lang": "下索布語",
"lang_code": "dsb",
"pos": "noun",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "詞元形式為紅鏈的屈折",
"parents": [],
"source": "w"
}
],
"form_of": [
{
"word": "grod"
}
],
"glosses": [
"grod 的屬格單數"
],
"id": "zh-groda-dsb-noun-Zyk84~SA",
"tags": [
"form-of"
]
},
{
"categories": [
{
"kind": "other",
"name": "詞元形式為紅鏈的屈折",
"parents": [],
"source": "w"
}
],
"form_of": [
{
"word": "grod"
}
],
"glosses": [
"grod 的主格雙數"
],
"id": "zh-groda-dsb-noun-cQuBhzUT",
"tags": [
"form-of"
]
},
{
"categories": [
{
"kind": "other",
"name": "詞元形式為紅鏈的屈折",
"parents": [],
"source": "w"
}
],
"form_of": [
{
"word": "grod"
}
],
"glosses": [
"grod 的賓格雙數"
],
"id": "zh-groda-dsb-noun-HkOOsW9U",
"tags": [
"form-of"
]
}
],
"sounds": [
{
"ipa": "[ˈɡrɔda]"
}
],
"word": "groda"
}
{
"categories": [
{
"kind": "other",
"name": "有2個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自原始西日耳曼語的瑞典語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "瑞典語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "瑞典語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "瑞典語通性名詞",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自原始西日耳曼語 *krodu (“蟾蜍”)，與德語 Kröte有關。",
"lang": "瑞典語",
"lang_code": "sv",
"pos": "noun",
"related": [
{
"word": "grodlår"
},
{
"word": "grodman"
},
{
"word": "grodyngel"
},
{
"word": "lövgroda"
}
],
"senses": [
{
"glosses": [
"蛙"
],
"id": "zh-groda-sv-noun-nvHzdhWT"
},
{
"glosses": [
"洋相"
],
"id": "zh-groda-sv-noun-TfhwdLZN"
}
],
"sounds": [
{
"ipa": "/ˈɡruːda/"
}
],
"tags": [
"common"
],
"word": "groda"
}
{
"categories": [
"下索布語名詞變格形",
"下索布語非詞元形式",
"有2個詞條的頁面",
"有詞條的頁面"
],
"lang": "下索布語",
"lang_code": "dsb",
"pos": "noun",
"senses": [
{
"categories": [
"詞元形式為紅鏈的屈折"
],
"form_of": [
{
"word": "grod"
}
],
"glosses": [
"grod 的屬格單數"
],
"tags": [
"form-of"
]
},
{
"categories": [
"詞元形式為紅鏈的屈折"
],
"form_of": [
{
"word": "grod"
}
],
"glosses": [
"grod 的主格雙數"
],
"tags": [
"form-of"
]
},
{
"categories": [
"詞元形式為紅鏈的屈折"
],
"form_of": [
{
"word": "grod"
}
],
"glosses": [
"grod 的賓格雙數"
],
"tags": [
"form-of"
]
}
],
"sounds": [
{
"ipa": "[ˈɡrɔda]"
}
],
"word": "groda"
}
{
"categories": [
"有2個詞條的頁面",
"有詞條的頁面",
"派生自原始西日耳曼語的瑞典語詞",
"瑞典語名詞",
"瑞典語詞元",
"瑞典語通性名詞"
],
"etymology_text": "源自原始西日耳曼語 *krodu (“蟾蜍”)，與德語 Kröte有關。",
"lang": "瑞典語",
"lang_code": "sv",
"pos": "noun",
"related": [
{
"word": "grodlår"
},
{
"word": "grodman"
},
{
"word": "grodyngel"
},
{
"word": "lövgroda"
}
],
"senses": [
{
"glosses": [
"蛙"
]
},
{
"glosses": [
"洋相"
]
}
],
"sounds": [
{
"ipa": "/ˈɡruːda/"
}
],
"tags": [
"common"
],
"word": "groda"
}
Download raw JSONL data for groda meaning in All languages combined (1.2kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.