"gospodin" meaning in All languages combined

See gospodin on Wiktionary

Noun [塞尔维亚-克罗地亚语]

IPA: /ɡospǒdin/ Forms: госпо̀дин
Etymology: 源自原始斯拉夫語 *gospodinъ,源自*gospodь (“主,主人,大人”)。
  1. 紳士
    Sense id: zh-gospodin-sh-noun-ONHHvci4
  2. 先生
    Sense id: zh-gospodin-sh-noun-zZjkPaMb
The following are not (yet) sense-disambiguated
Related terms: gospođa, gospođica, Gospod, Gospa

Noun [罗马尼亚语]

Forms: gospodini [plural]
Etymology: 借自教會斯拉夫語 господинъ (gospodinŭ)。
  1. 上帝 Tags: obsolete
    Sense id: zh-gospodin-ro-noun-kRBlnU9d Categories (other): 有棄用詞義的羅馬尼亞語詞
  2. 主人,大人 Tags: obsolete
    Sense id: zh-gospodin-ro-noun-Ixsrp9QD Categories (other): 有棄用詞義的羅馬尼亞語詞
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自教會斯拉夫語的羅馬尼亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自教會斯拉夫語的羅馬尼亞語借詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自教會斯拉夫語 господинъ (gospodinŭ)。",
  "forms": [
    {
      "form": "gospodini",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "罗马尼亚语",
  "lang_code": "ro",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "有棄用詞義的羅馬尼亞語詞",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "上帝"
      ],
      "id": "zh-gospodin-ro-noun-kRBlnU9d",
      "tags": [
        "obsolete"
      ]
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "有棄用詞義的羅馬尼亞語詞",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "主人,大人"
      ],
      "id": "zh-gospodin-ro-noun-Ixsrp9QD",
      "tags": [
        "obsolete"
      ]
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "gospodin"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "原始斯拉夫語紅鏈",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "原始斯拉夫語紅鏈/m",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "塞爾維亞-克羅地亞語 男人",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "塞爾維亞-克羅地亞語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "塞爾維亞-克羅地亞語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "塞爾維亞-克羅地亞語陽性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始斯拉夫語的塞爾維亞-克羅地亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始斯拉夫語的塞爾維亞-克羅地亞語繼承詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自原始斯拉夫語 *gospodinъ,源自*gospodь (“主,主人,大人”)。",
  "forms": [
    {
      "form": "госпо̀дин",
      "raw_tags": [
        "西里爾字母拼寫"
      ]
    }
  ],
  "lang": "塞尔维亚-克罗地亚语",
  "lang_code": "sh",
  "pos": "noun",
  "related": [
    {
      "word": "gospođa"
    },
    {
      "word": "gospođica"
    },
    {
      "word": "Gospod"
    },
    {
      "word": "Gospa"
    }
  ],
  "senses": [
    {
      "glosses": [
        "紳士"
      ],
      "id": "zh-gospodin-sh-noun-ONHHvci4"
    },
    {
      "glosses": [
        "先生"
      ],
      "id": "zh-gospodin-sh-noun-zZjkPaMb"
    }
  ],
  "sounds": [
    {
      "ipa": "/ɡospǒdin/"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "gospodin"
}
{
  "categories": [
    "原始斯拉夫語紅鏈",
    "原始斯拉夫語紅鏈/m",
    "塞爾維亞-克羅地亞語 男人",
    "塞爾維亞-克羅地亞語名詞",
    "塞爾維亞-克羅地亞語詞元",
    "塞爾維亞-克羅地亞語陽性名詞",
    "有2個詞條的頁面",
    "派生自原始斯拉夫語的塞爾維亞-克羅地亞語詞",
    "源自原始斯拉夫語的塞爾維亞-克羅地亞語繼承詞"
  ],
  "etymology_text": "源自原始斯拉夫語 *gospodinъ,源自*gospodь (“主,主人,大人”)。",
  "forms": [
    {
      "form": "госпо̀дин",
      "raw_tags": [
        "西里爾字母拼寫"
      ]
    }
  ],
  "lang": "塞尔维亚-克罗地亚语",
  "lang_code": "sh",
  "pos": "noun",
  "related": [
    {
      "word": "gospođa"
    },
    {
      "word": "gospođica"
    },
    {
      "word": "Gospod"
    },
    {
      "word": "Gospa"
    }
  ],
  "senses": [
    {
      "glosses": [
        "紳士"
      ]
    },
    {
      "glosses": [
        "先生"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ɡospǒdin/"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "gospodin"
}

{
  "categories": [
    "有2個詞條的頁面",
    "派生自教會斯拉夫語的羅馬尼亞語詞",
    "源自教會斯拉夫語的羅馬尼亞語借詞",
    "羅馬尼亞語可數名詞",
    "羅馬尼亞語名詞",
    "羅馬尼亞語詞元"
  ],
  "etymology_text": "借自教會斯拉夫語 господинъ (gospodinŭ)。",
  "forms": [
    {
      "form": "gospodini",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "罗马尼亚语",
  "lang_code": "ro",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "有棄用詞義的羅馬尼亞語詞"
      ],
      "glosses": [
        "上帝"
      ],
      "tags": [
        "obsolete"
      ]
    },
    {
      "categories": [
        "有棄用詞義的羅馬尼亞語詞"
      ],
      "glosses": [
        "主人,大人"
      ],
      "tags": [
        "obsolete"
      ]
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "gospodin"
}

Download raw JSONL data for gospodin meaning in All languages combined (1.6kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-05 from the zhwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.