"gezond" meaning in All languages combined

See gezond on Wiktionary

Adjective [荷蘭語]

IPA: /ɣəˈzɔnt/ Audio: Nl-gezond.ogg Forms: gezonder [comparative], gezondst [superlative]
Etymology: 源自中古荷蘭語 gesont ← 古荷蘭語 gisunt ← 原始西日耳曼語 *gasund ← 原始日耳曼語 *gasundaz。與德語 gesund, 古英語 ġesund, 古高地德語 gisunt同源。
  1. 健康的
    Sense id: zh-gezond-nl-adj-X~oGfHGn
  2. 對健康有益的
    Sense id: zh-gezond-nl-adj-W0DBcljY
The following are not (yet) sense-disambiguated
Derived forms: gezondheid, gezondmakend, ongezond

Verb [荷蘭語]

IPA: /ɣəˈzɔnt/ Audio: Nl-gezond.ogg
Etymology: 請參閲主詞條的词源章節。
  1. zonnen的過去分詞。 Tags: form-of Form of: zonnen
    Sense id: zh-gezond-nl-verb-TZzxLhB2
The following are not (yet) sense-disambiguated
{
  "antonyms": [
    {
      "word": "ongezond"
    }
  ],
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自中古荷蘭語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始西日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古荷蘭語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自中古荷蘭語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始西日耳曼語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古荷蘭語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "gezondheid"
    },
    {
      "word": "gezondmakend"
    },
    {
      "word": "ongezond"
    }
  ],
  "descendants": [
    {
      "lang": "南非語",
      "lang_code": "af",
      "word": "gesond"
    },
    {
      "lang": "蘇里南湯加語",
      "lang_code": "srn",
      "word": "gesontu"
    }
  ],
  "etymology_text": "源自中古荷蘭語 gesont ← 古荷蘭語 gisunt ← 原始西日耳曼語 *gasund ← 原始日耳曼語 *gasundaz。與德語 gesund, 古英語 ġesund, 古高地德語 gisunt同源。",
  "forms": [
    {
      "form": "gezonder",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "gezondst",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "荷蘭語",
  "lang_code": "nl",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的"
      ],
      "id": "zh-gezond-nl-adj-X~oGfHGn"
    },
    {
      "glosses": [
        "對健康有益的"
      ],
      "id": "zh-gezond-nl-adj-W0DBcljY"
    }
  ],
  "sounds": [
    {
      "ipa": "/ɣəˈzɔnt/"
    },
    {
      "audio": "Nl-gezond.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a2/Nl-gezond.ogg/Nl-gezond.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-gezond.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "word": "gezond"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "不用作形容詞的荷蘭語過去分詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自中古荷蘭語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始西日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古荷蘭語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自中古荷蘭語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始西日耳曼語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古荷蘭語的荷蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語過去分詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語非詞元形式",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "請參閲主詞條的词源章節。",
  "lang": "荷蘭語",
  "lang_code": "nl",
  "pos": "verb",
  "raw_tags": [
    "不用作形容詞"
  ],
  "senses": [
    {
      "form_of": [
        {
          "word": "zonnen"
        }
      ],
      "glosses": [
        "zonnen的過去分詞。"
      ],
      "id": "zh-gezond-nl-verb-TZzxLhB2",
      "tags": [
        "form-of"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ɣəˈzɔnt/"
    },
    {
      "audio": "Nl-gezond.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a2/Nl-gezond.ogg/Nl-gezond.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-gezond.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "gezond"
}
{
  "antonyms": [
    {
      "word": "ongezond"
    }
  ],
  "categories": [
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自中古荷蘭語的荷蘭語詞",
    "派生自原始日耳曼語的荷蘭語詞",
    "派生自原始西日耳曼語的荷蘭語詞",
    "派生自古荷蘭語的荷蘭語詞",
    "源自中古荷蘭語的荷蘭語繼承詞",
    "源自原始日耳曼語的荷蘭語繼承詞",
    "源自原始西日耳曼語的荷蘭語繼承詞",
    "源自古荷蘭語的荷蘭語繼承詞",
    "荷蘭語形容詞",
    "荷蘭語詞元"
  ],
  "derived": [
    {
      "word": "gezondheid"
    },
    {
      "word": "gezondmakend"
    },
    {
      "word": "ongezond"
    }
  ],
  "descendants": [
    {
      "lang": "南非語",
      "lang_code": "af",
      "word": "gesond"
    },
    {
      "lang": "蘇里南湯加語",
      "lang_code": "srn",
      "word": "gesontu"
    }
  ],
  "etymology_text": "源自中古荷蘭語 gesont ← 古荷蘭語 gisunt ← 原始西日耳曼語 *gasund ← 原始日耳曼語 *gasundaz。與德語 gesund, 古英語 ġesund, 古高地德語 gisunt同源。",
  "forms": [
    {
      "form": "gezonder",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "gezondst",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "荷蘭語",
  "lang_code": "nl",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的"
      ]
    },
    {
      "glosses": [
        "對健康有益的"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ɣəˈzɔnt/"
    },
    {
      "audio": "Nl-gezond.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a2/Nl-gezond.ogg/Nl-gezond.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-gezond.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "word": "gezond"
}

{
  "categories": [
    "不用作形容詞的荷蘭語過去分詞",
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自中古荷蘭語的荷蘭語詞",
    "派生自原始日耳曼語的荷蘭語詞",
    "派生自原始西日耳曼語的荷蘭語詞",
    "派生自古荷蘭語的荷蘭語詞",
    "源自中古荷蘭語的荷蘭語繼承詞",
    "源自原始日耳曼語的荷蘭語繼承詞",
    "源自原始西日耳曼語的荷蘭語繼承詞",
    "源自古荷蘭語的荷蘭語繼承詞",
    "荷蘭語過去分詞",
    "荷蘭語非詞元形式"
  ],
  "etymology_text": "請參閲主詞條的词源章節。",
  "lang": "荷蘭語",
  "lang_code": "nl",
  "pos": "verb",
  "raw_tags": [
    "不用作形容詞"
  ],
  "senses": [
    {
      "form_of": [
        {
          "word": "zonnen"
        }
      ],
      "glosses": [
        "zonnen的過去分詞。"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ɣəˈzɔnt/"
    },
    {
      "audio": "Nl-gezond.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a2/Nl-gezond.ogg/Nl-gezond.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-gezond.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "gezond"
}

Download raw JSONL data for gezond meaning in All languages combined (2.5kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.