"gesund" meaning in All languages combined

See gesund on Wiktionary

Adjective [低地德语]

Forms: gesünner [comparative], gesünnst [superlative]
Etymology: 源自古撒克遜語 gisund,源自原始日耳曼語 *gasundaz。与德語 gesund、荷蘭語 gezond、英語 sound同源。
  1. 健康的
    Sense id: zh-gesund-nds-adj-X~oGfHGn
The following are not (yet) sense-disambiguated
Derived forms: Gesundheit

Adjective [古英语]

Etymology: 源自ġe- + *sund。后半部分继承自原始日耳曼語 *sundaz。 对比古撒克遜語 gisund和古高地德語 gisunt。
  1. 健康的
    Sense id: zh-gesund-ang-adj-X~oGfHGn
The following are not (yet) sense-disambiguated

Adjective [德语]

IPA: /ɡəˈzʊnt/ Audio: De-at-gesund.ogg , De-gesund.ogg Forms: gesunder, gesünder [comparative], am gesündesten [superlative]
Etymology: 源自中古高地德語 gesunt,源自古高地德語 gisunt,源自原始西日耳曼語 *gasund,*sund添加了前缀后的形式,源自原始日耳曼語 *sundaz,源自原始印歐語词干*swen-。sound 的同源對似詞。
  1. 健康的,没有疾病的
    Sense id: zh-gesund-de-adj-2ieG9Wmi
  2. 自然的,正常的
    Sense id: zh-gesund-de-adj-G9MW9y6R
  3. 健康的,有益健康的
    Sense id: zh-gesund-de-adj-8G400j7T
The following are not (yet) sense-disambiguated
Synonyms (健康的,有益健康的): gesundheitsfördernd Derived forms: gesunden, Gesundheit, Gesundbrunnen

Adjective [汉斯立克语]

IPA: /kəˈsunt/ Forms: gesinder [comparative], gesindest [superlative]
  1. 健康地
    Sense id: zh-gesund-hrx-adj-oykUMRbP Categories (other): 有使用例的漢斯立克語詞
The following are not (yet) sense-disambiguated
Derived forms: Gesundheet, Gesundheit

Inflected forms

{
  "antonyms": [
    {
      "sense": "健康的,没有疾病的",
      "word": "krank"
    },
    {
      "sense": "健康的,没有疾病的",
      "word": "kränklich"
    },
    {
      "sense": "健康的,没有疾病的",
      "word": "ungesund"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "ungesund"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "schädlich"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "gesundheitsschädlich"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "gesundheitsgefährdend"
    }
  ],
  "categories": [
    {
      "kind": "other",
      "name": "原始印歐語紅鏈",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "原始印歐語紅鏈/m",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "德語形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "德語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自中古高地德語的德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始印歐語的德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始西日耳曼語的德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古高地德語的德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自中古高地德語的德語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始西日耳曼語的德語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古高地德語的德語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語同源對似詞",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "gesunden"
    },
    {
      "word": "Gesundheit"
    },
    {
      "word": "Gesundbrunnen"
    }
  ],
  "etymology_text": "源自中古高地德語 gesunt,源自古高地德語 gisunt,源自原始西日耳曼語 *gasund,*sund添加了前缀后的形式,源自原始日耳曼語 *sundaz,源自原始印歐語词干*swen-。sound 的同源對似詞。",
  "forms": [
    {
      "form": "gesunder",
      "raw_tags": [
        "強變化主格陽性單數"
      ]
    },
    {
      "form": "gesünder",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "am gesündesten",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "德语",
  "lang_code": "de",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的,没有疾病的"
      ],
      "id": "zh-gesund-de-adj-2ieG9Wmi"
    },
    {
      "glosses": [
        "自然的,正常的"
      ],
      "id": "zh-gesund-de-adj-G9MW9y6R"
    },
    {
      "glosses": [
        "健康的,有益健康的"
      ],
      "id": "zh-gesund-de-adj-8G400j7T"
    }
  ],
  "sounds": [
    {
      "ipa": "/ɡəˈzʊnt/"
    },
    {
      "audio": "De-at-gesund.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d4/De-at-gesund.ogg/De-at-gesund.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/De-at-gesund.ogg",
      "raw_tags": [
        "(奥地利)音频"
      ]
    },
    {
      "audio": "De-gesund.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/ee/De-gesund.ogg/De-gesund.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/De-gesund.ogg",
      "raw_tags": [
        "音频"
      ]
    }
  ],
  "synonyms": [
    {
      "sense": "健康的,有益健康的",
      "word": "gesundheitsfördernd"
    }
  ],
  "word": "gesund"
}

{
  "antonyms": [
    {
      "word": "krank"
    }
  ],
  "categories": [
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "漢斯立克語形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "漢斯立克語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "Gesundheet"
    },
    {
      "word": "Gesundheit"
    }
  ],
  "forms": [
    {
      "form": "gesinder",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "gesindest",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "汉斯立克语",
  "lang_code": "hrx",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "有使用例的漢斯立克語詞",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "text": "Sie sin nommol gesund.",
          "translation": "他们又恢复健康了。"
        },
        {
          "text": "Er is en gesunder Mann.",
          "translation": "他是一个健康的人。"
        }
      ],
      "glosses": [
        "健康地"
      ],
      "id": "zh-gesund-hrx-adj-oykUMRbP"
    }
  ],
  "sounds": [
    {
      "ipa": "/kəˈsunt/"
    }
  ],
  "word": "gesund"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "低地德語形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "低地德語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的低地德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古撒克遜語的低地德語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的低地德語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古撒克遜語的低地德語繼承詞",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "Gesundheit"
    }
  ],
  "etymology_text": "源自古撒克遜語 gisund,源自原始日耳曼語 *gasundaz。与德語 gesund、荷蘭語 gezond、英語 sound同源。",
  "forms": [
    {
      "form": "gesünner",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "gesünnst",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "低地德语",
  "lang_code": "nds",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的"
      ],
      "id": "zh-gesund-nds-adj-X~oGfHGn"
    }
  ],
  "word": "gesund"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "古英語形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "古英語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "含有前綴ge-的古英語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的古英語詞",
      "parents": [],
      "source": "w"
    }
  ],
  "descendants": [
    {
      "descendants": [
        {
          "lang": "英語",
          "lang_code": "en",
          "word": "sound"
        },
        {
          "lang": "低地蘇格蘭語",
          "lang_code": "sco",
          "word": "sound"
        }
      ],
      "lang": "中古英語",
      "lang_code": "enm",
      "word": "ȝesund"
    }
  ],
  "etymology_text": "源自ġe- + *sund。后半部分继承自原始日耳曼語 *sundaz。 对比古撒克遜語 gisund和古高地德語 gisunt。",
  "lang": "古英语",
  "lang_code": "ang",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的"
      ],
      "id": "zh-gesund-ang-adj-X~oGfHGn"
    }
  ],
  "word": "gesund"
}
{
  "categories": [
    "低地德語形容詞",
    "低地德語詞元",
    "有4個詞條的頁面",
    "有詞條的頁面",
    "派生自原始日耳曼語的低地德語詞",
    "派生自古撒克遜語的低地德語詞",
    "源自原始日耳曼語的低地德語繼承詞",
    "源自古撒克遜語的低地德語繼承詞"
  ],
  "derived": [
    {
      "word": "Gesundheit"
    }
  ],
  "etymology_text": "源自古撒克遜語 gisund,源自原始日耳曼語 *gasundaz。与德語 gesund、荷蘭語 gezond、英語 sound同源。",
  "forms": [
    {
      "form": "gesünner",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "gesünnst",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "低地德语",
  "lang_code": "nds",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的"
      ]
    }
  ],
  "word": "gesund"
}

{
  "categories": [
    "古英語形容詞",
    "古英語詞元",
    "含有前綴ge-的古英語詞",
    "有4個詞條的頁面",
    "有詞條的頁面",
    "派生自原始日耳曼語的古英語詞"
  ],
  "descendants": [
    {
      "descendants": [
        {
          "lang": "英語",
          "lang_code": "en",
          "word": "sound"
        },
        {
          "lang": "低地蘇格蘭語",
          "lang_code": "sco",
          "word": "sound"
        }
      ],
      "lang": "中古英語",
      "lang_code": "enm",
      "word": "ȝesund"
    }
  ],
  "etymology_text": "源自ġe- + *sund。后半部分继承自原始日耳曼語 *sundaz。 对比古撒克遜語 gisund和古高地德語 gisunt。",
  "lang": "古英语",
  "lang_code": "ang",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的"
      ]
    }
  ],
  "word": "gesund"
}

{
  "antonyms": [
    {
      "sense": "健康的,没有疾病的",
      "word": "krank"
    },
    {
      "sense": "健康的,没有疾病的",
      "word": "kränklich"
    },
    {
      "sense": "健康的,没有疾病的",
      "word": "ungesund"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "ungesund"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "schädlich"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "gesundheitsschädlich"
    },
    {
      "sense": "健康的,有益健康的",
      "word": "gesundheitsgefährdend"
    }
  ],
  "categories": [
    "原始印歐語紅鏈",
    "原始印歐語紅鏈/m",
    "德語形容詞",
    "德語詞元",
    "有4個詞條的頁面",
    "有詞條的頁面",
    "派生自中古高地德語的德語詞",
    "派生自原始印歐語的德語詞",
    "派生自原始日耳曼語的德語詞",
    "派生自原始西日耳曼語的德語詞",
    "派生自古高地德語的德語詞",
    "源自中古高地德語的德語繼承詞",
    "源自原始西日耳曼語的德語繼承詞",
    "源自古高地德語的德語繼承詞",
    "英語同源對似詞"
  ],
  "derived": [
    {
      "word": "gesunden"
    },
    {
      "word": "Gesundheit"
    },
    {
      "word": "Gesundbrunnen"
    }
  ],
  "etymology_text": "源自中古高地德語 gesunt,源自古高地德語 gisunt,源自原始西日耳曼語 *gasund,*sund添加了前缀后的形式,源自原始日耳曼語 *sundaz,源自原始印歐語词干*swen-。sound 的同源對似詞。",
  "forms": [
    {
      "form": "gesunder",
      "raw_tags": [
        "強變化主格陽性單數"
      ]
    },
    {
      "form": "gesünder",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "am gesündesten",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "德语",
  "lang_code": "de",
  "pos": "adj",
  "senses": [
    {
      "glosses": [
        "健康的,没有疾病的"
      ]
    },
    {
      "glosses": [
        "自然的,正常的"
      ]
    },
    {
      "glosses": [
        "健康的,有益健康的"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ɡəˈzʊnt/"
    },
    {
      "audio": "De-at-gesund.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d4/De-at-gesund.ogg/De-at-gesund.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/De-at-gesund.ogg",
      "raw_tags": [
        "(奥地利)音频"
      ]
    },
    {
      "audio": "De-gesund.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/ee/De-gesund.ogg/De-gesund.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/De-gesund.ogg",
      "raw_tags": [
        "音频"
      ]
    }
  ],
  "synonyms": [
    {
      "sense": "健康的,有益健康的",
      "word": "gesundheitsfördernd"
    }
  ],
  "word": "gesund"
}

{
  "antonyms": [
    {
      "word": "krank"
    }
  ],
  "categories": [
    "有4個詞條的頁面",
    "有詞條的頁面",
    "漢斯立克語形容詞",
    "漢斯立克語詞元"
  ],
  "derived": [
    {
      "word": "Gesundheet"
    },
    {
      "word": "Gesundheit"
    }
  ],
  "forms": [
    {
      "form": "gesinder",
      "tags": [
        "comparative"
      ]
    },
    {
      "form": "gesindest",
      "tags": [
        "superlative"
      ]
    }
  ],
  "lang": "汉斯立克语",
  "lang_code": "hrx",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        "有使用例的漢斯立克語詞"
      ],
      "examples": [
        {
          "text": "Sie sin nommol gesund.",
          "translation": "他们又恢复健康了。"
        },
        {
          "text": "Er is en gesunder Mann.",
          "translation": "他是一个健康的人。"
        }
      ],
      "glosses": [
        "健康地"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/kəˈsunt/"
    }
  ],
  "word": "gesund"
}

Download raw JSONL data for gesund meaning in All languages combined (4.4kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.