"fruor" meaning in All languages combined

See fruor on Wiktionary

Verb [拉丁語]

Forms: fruī, frūctus sum
Etymology: 来自原始意大利語 *frūgjōr,來自原始印歐語 *bʰruHg- (“使用,享受”)。類似於英語 brook (詞源1)。
  1. 享有,享受,受益,利用……(+奪格)
    Sense id: zh-fruor-la-verb-19f3QFDh
The following are not (yet) sense-disambiguated
Derived forms: frūniscor, frūmen, fruitare Related terms: frūctus, frūx

Inflected forms

{
  "categories": [
    {
      "kind": "other",
      "name": "來自原始印歐語詞根*bʰruHg-的拉丁語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語動詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始印歐語的拉丁語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始意大利語的拉丁語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始意大利語的拉丁語繼承詞",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "frūniscor"
    },
    {
      "word": "frūmen"
    },
    {
      "word": "fruitare"
    }
  ],
  "etymology_text": "来自原始意大利語 *frūgjōr,來自原始印歐語 *bʰruHg- (“使用,享受”)。類似於英語 brook (詞源1)。",
  "forms": [
    {
      "form": "fruī",
      "raw_tags": [
        "现在时不定式"
      ]
    },
    {
      "form": "frūctus sum",
      "raw_tags": [
        "完成时主动式"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "related": [
    {
      "word": "frūctus"
    },
    {
      "word": "frūx"
    }
  ],
  "senses": [
    {
      "glosses": [
        "享有,享受,受益,利用……(+奪格)"
      ],
      "id": "zh-fruor-la-verb-19f3QFDh"
    }
  ],
  "word": "fruor"
}
{
  "categories": [
    "來自原始印歐語詞根*bʰruHg-的拉丁語詞",
    "拉丁語動詞",
    "拉丁語詞元",
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自原始印歐語的拉丁語詞",
    "派生自原始意大利語的拉丁語詞",
    "源自原始意大利語的拉丁語繼承詞"
  ],
  "derived": [
    {
      "word": "frūniscor"
    },
    {
      "word": "frūmen"
    },
    {
      "word": "fruitare"
    }
  ],
  "etymology_text": "来自原始意大利語 *frūgjōr,來自原始印歐語 *bʰruHg- (“使用,享受”)。類似於英語 brook (詞源1)。",
  "forms": [
    {
      "form": "fruī",
      "raw_tags": [
        "现在时不定式"
      ]
    },
    {
      "form": "frūctus sum",
      "raw_tags": [
        "完成时主动式"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "related": [
    {
      "word": "frūctus"
    },
    {
      "word": "frūx"
    }
  ],
  "senses": [
    {
      "glosses": [
        "享有,享受,受益,利用……(+奪格)"
      ]
    }
  ],
  "word": "fruor"
}

Download raw JSONL data for fruor meaning in All languages combined (0.8kB)

{
  "called_from": "extractor/zh/page/parse_section/192",
  "msg": "Unhandled subtitle: 派生语汇",
  "path": [
    "fruor"
  ],
  "section": "拉丁語",
  "subsection": "派生语汇",
  "title": "fruor",
  "trace": ""
}

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.