"derogatorius" meaning in All languages combined

See derogatorius on Wiktionary

Adjective [拉丁語]

Forms: dērogātōria, dērogātōrium [neuter]
Etymology: 源自 dērogō (“廢除或修改法律的一部分;刪除;貶低”),源自 de (“的;來自,遠離”) + rogō (“詢問;請求”)。
  1. 屬於或涉及毀損或部分廢除的;貶損的;修改的
    Sense id: zh-derogatorius-la-adj-toFvnA4z Categories (other): 拉丁語 法律 Topics: law
The following are not (yet) sense-disambiguated
Related terms: dērogātiō, dērogātor, dērogō
{
  "categories": [
    {
      "kind": "other",
      "name": "拉丁語形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語第一和第二類變格形容詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "descendants": [
    {
      "lang": "英語",
      "lang_code": "en",
      "word": "derogator"
    },
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "dérogatoire"
    },
    {
      "lang": "意大利語",
      "lang_code": "it",
      "word": "derogatorio"
    },
    {
      "lang": "葡萄牙語",
      "lang_code": "pt",
      "word": "derrogatório"
    },
    {
      "lang": "羅馬尼亞語",
      "lang_code": "ro",
      "word": "derogatoriu"
    },
    {
      "lang": "西班牙語",
      "lang_code": "es",
      "word": "derogatorio"
    }
  ],
  "etymology_text": "源自 dērogō (“廢除或修改法律的一部分;刪除;貶低”),源自 de (“的;來自,遠離”) + rogō (“詢問;請求”)。",
  "forms": [
    {
      "form": "dērogātōria",
      "raw_tags": [
        "阴性"
      ]
    },
    {
      "form": "dērogātōrium",
      "tags": [
        "neuter"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "adj",
  "pos_title": "形容詞",
  "related": [
    {
      "word": "dērogātiō"
    },
    {
      "word": "dērogātor"
    },
    {
      "word": "dērogō"
    }
  ],
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "拉丁語 法律",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "屬於或涉及毀損或部分廢除的;貶損的;修改的"
      ],
      "id": "zh-derogatorius-la-adj-toFvnA4z",
      "topics": [
        "law"
      ]
    }
  ],
  "word": "derogatorius"
}
{
  "categories": [
    "拉丁語形容詞",
    "拉丁語第一和第二類變格形容詞",
    "拉丁語詞元",
    "有1個詞條的頁面",
    "有詞條的頁面"
  ],
  "descendants": [
    {
      "lang": "英語",
      "lang_code": "en",
      "word": "derogator"
    },
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "dérogatoire"
    },
    {
      "lang": "意大利語",
      "lang_code": "it",
      "word": "derogatorio"
    },
    {
      "lang": "葡萄牙語",
      "lang_code": "pt",
      "word": "derrogatório"
    },
    {
      "lang": "羅馬尼亞語",
      "lang_code": "ro",
      "word": "derogatoriu"
    },
    {
      "lang": "西班牙語",
      "lang_code": "es",
      "word": "derogatorio"
    }
  ],
  "etymology_text": "源自 dērogō (“廢除或修改法律的一部分;刪除;貶低”),源自 de (“的;來自,遠離”) + rogō (“詢問;請求”)。",
  "forms": [
    {
      "form": "dērogātōria",
      "raw_tags": [
        "阴性"
      ]
    },
    {
      "form": "dērogātōrium",
      "tags": [
        "neuter"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "adj",
  "pos_title": "形容詞",
  "related": [
    {
      "word": "dērogātiō"
    },
    {
      "word": "dērogātor"
    },
    {
      "word": "dērogō"
    }
  ],
  "senses": [
    {
      "categories": [
        "拉丁語 法律"
      ],
      "glosses": [
        "屬於或涉及毀損或部分廢除的;貶損的;修改的"
      ],
      "topics": [
        "law"
      ]
    }
  ],
  "word": "derogatorius"
}

Download raw JSONL data for derogatorius meaning in All languages combined (1.2kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-02-06 from the zhwiktionary dump dated 2025-02-02 using wiktextract (0ee4b87 and 9dbd323). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.