"comjat" meaning in All languages combined

See comjat on Wiktionary

Noun [奧克語]

IPA: /kunˈdʒat/ Audio: LL-Q942602-Davidgrosclaude-comjat.wav
Etymology: 繼承自古奧克語 comjat,繼承自拉丁語 commeātus。同源詞包括法語 congé。
  1. 請假
    Sense id: zh-comjat-oc-noun-vvFcQwX8
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "奧克語可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "奧克語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "奧克語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "奧克語陽性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古奧克語的奧克語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自拉丁語的奧克語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古奧克語的奧克語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自拉丁語的奧克語繼承詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "繼承自古奧克語 comjat,繼承自拉丁語 commeātus。同源詞包括法語 congé。",
  "lang": "奧克語",
  "lang_code": "oc",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "請假"
      ],
      "id": "zh-comjat-oc-noun-vvFcQwX8"
    }
  ],
  "sounds": [
    {
      "ipa": "/kunˈdʒat/"
    },
    {
      "audio": "LL-Q942602-Davidgrosclaude-comjat.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/cf/LL-Q942602-Davidgrosclaude-comjat.wav/LL-Q942602-Davidgrosclaude-comjat.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/cf/LL-Q942602-Davidgrosclaude-comjat.wav/LL-Q942602-Davidgrosclaude-comjat.wav.ogg",
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q942602-Davidgrosclaude-comjat.wav"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "comjat"
}
{
  "categories": [
    "奧克語可數名詞",
    "奧克語名詞",
    "奧克語詞元",
    "奧克語陽性名詞",
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自古奧克語的奧克語詞",
    "派生自拉丁語的奧克語詞",
    "源自古奧克語的奧克語繼承詞",
    "源自拉丁語的奧克語繼承詞"
  ],
  "etymology_text": "繼承自古奧克語 comjat,繼承自拉丁語 commeātus。同源詞包括法語 congé。",
  "lang": "奧克語",
  "lang_code": "oc",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "請假"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/kunˈdʒat/"
    },
    {
      "audio": "LL-Q942602-Davidgrosclaude-comjat.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/cf/LL-Q942602-Davidgrosclaude-comjat.wav/LL-Q942602-Davidgrosclaude-comjat.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/cf/LL-Q942602-Davidgrosclaude-comjat.wav/LL-Q942602-Davidgrosclaude-comjat.wav.ogg",
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q942602-Davidgrosclaude-comjat.wav"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "comjat"
}

Download raw JSONL data for comjat meaning in All languages combined (1.0kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.