See begåvad on Wiktionary
{
"categories": [
{
"kind": "other",
"name": "有1個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自中古低地德語的瑞典語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古瑞典語的瑞典語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "瑞典語過去分詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "瑞典語非詞元形式",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自古瑞典語 begava，源自中古低地德語 begaven。",
"lang": "瑞典語",
"lang_code": "sv",
"pos": "verb",
"pos_title": "分詞",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "瑞典語過去分詞",
"parents": [],
"source": "w"
}
],
"form_of": [
{
"word": "begåva"
}
],
"glosses": [
"begåva 的過去時分詞"
],
"id": "zh-begåvad-sv-verb-~l6xL5nM",
"tags": [
"form-of"
]
}
],
"sounds": [
{
"audio": "Sv-begåvad.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/Sv-begåvad.ogg/Sv-begåvad.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Sv-begåvad.ogg"
}
],
"tags": [
"participle"
],
"word": "begåvad"
}
{
"antonyms": [
{
"word": "obegåvad"
}
],
"categories": [
{
"kind": "other",
"name": "有1個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自中古低地德語的瑞典語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古瑞典語的瑞典語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "瑞典語形容詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "瑞典語詞元",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自古瑞典語 begava，源自中古低地德語 begaven。",
"forms": [
{
"form": "mer begåvad",
"tags": [
"comparative"
]
},
{
"form": "mest begåvad",
"tags": [
"superlative"
]
}
],
"lang": "瑞典語",
"lang_code": "sv",
"pos": "adj",
"pos_title": "形容詞",
"related": [
{
"word": "begåva"
},
{
"word": "begåvning"
}
],
"senses": [
{
"glosses": [
"有才華的，有天賦的"
],
"id": "zh-begåvad-sv-adj-BwCHbx0M"
}
],
"sounds": [
{
"audio": "Sv-begåvad.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/Sv-begåvad.ogg/Sv-begåvad.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Sv-begåvad.ogg"
}
],
"word": "begåvad"
}
{
"categories": [
"有1個詞條的頁面",
"有詞條的頁面",
"派生自中古低地德語的瑞典語詞",
"派生自古瑞典語的瑞典語詞",
"瑞典語過去分詞",
"瑞典語非詞元形式"
],
"etymology_text": "源自古瑞典語 begava，源自中古低地德語 begaven。",
"lang": "瑞典語",
"lang_code": "sv",
"pos": "verb",
"pos_title": "分詞",
"senses": [
{
"categories": [
"瑞典語過去分詞"
],
"form_of": [
{
"word": "begåva"
}
],
"glosses": [
"begåva 的過去時分詞"
],
"tags": [
"form-of"
]
}
],
"sounds": [
{
"audio": "Sv-begåvad.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/Sv-begåvad.ogg/Sv-begåvad.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Sv-begåvad.ogg"
}
],
"tags": [
"participle"
],
"word": "begåvad"
}
{
"antonyms": [
{
"word": "obegåvad"
}
],
"categories": [
"有1個詞條的頁面",
"有詞條的頁面",
"派生自中古低地德語的瑞典語詞",
"派生自古瑞典語的瑞典語詞",
"瑞典語形容詞",
"瑞典語詞元"
],
"etymology_text": "源自古瑞典語 begava，源自中古低地德語 begaven。",
"forms": [
{
"form": "mer begåvad",
"tags": [
"comparative"
]
},
{
"form": "mest begåvad",
"tags": [
"superlative"
]
}
],
"lang": "瑞典語",
"lang_code": "sv",
"pos": "adj",
"pos_title": "形容詞",
"related": [
{
"word": "begåva"
},
{
"word": "begåvning"
}
],
"senses": [
{
"glosses": [
"有才華的，有天賦的"
]
}
],
"sounds": [
{
"audio": "Sv-begåvad.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/Sv-begåvad.ogg/Sv-begåvad.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Sv-begåvad.ogg"
}
],
"word": "begåvad"
}
Download raw JSONL data for begåvad meaning in All languages combined (1.6kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-03-03 from the zhwiktionary dump dated 2025-03-02 using wiktextract (7dd5d20 and 5a03470). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.