"augmentati" meaning in All languages combined

See augmentati on Wiktionary

Verb [伊多語]

  1. augmentar的複數名詞化被動主動分詞 Tags: form-of Form of: augmentar
    Sense id: zh-augmentati-io-verb-RZdB5tVq
The following are not (yet) sense-disambiguated

Verb [拉丁語]

  1. augmentātus 的屈折变化形式:
    主格/呼格陽性複數
    Tags: form-of Form of: augmentātus
    Sense id: zh-augmentati-la-verb-pHsIZ-FT
  2. augmentātus 的屈折变化形式:
    屬格陽性/中性單數
    Tags: form-of Form of: augmentātus
    Sense id: zh-augmentati-la-verb-1n0rvCa6
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "伊多語分詞變格形",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "伊多語非詞元形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "伊多語",
  "lang_code": "io",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "augmentar"
        }
      ],
      "glosses": [
        "augmentar的複數名詞化被動主動分詞"
      ],
      "id": "zh-augmentati-io-verb-RZdB5tVq",
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "augmentati"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "拉丁語分詞變格形",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語非詞元形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "augmentātus"
        }
      ],
      "glosses": [
        "augmentātus 的屈折变化形式:",
        "主格/呼格陽性複數"
      ],
      "id": "zh-augmentati-la-verb-pHsIZ-FT",
      "tags": [
        "form-of"
      ]
    },
    {
      "form_of": [
        {
          "word": "augmentātus"
        }
      ],
      "glosses": [
        "augmentātus 的屈折变化形式:",
        "屬格陽性/中性單數"
      ],
      "id": "zh-augmentati-la-verb-1n0rvCa6",
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "augmentati"
}
{
  "categories": [
    "伊多語分詞變格形",
    "伊多語非詞元形式",
    "有2個詞條的頁面"
  ],
  "lang": "伊多語",
  "lang_code": "io",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "augmentar"
        }
      ],
      "glosses": [
        "augmentar的複數名詞化被動主動分詞"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "augmentati"
}

{
  "categories": [
    "拉丁語分詞變格形",
    "拉丁語非詞元形式",
    "有2個詞條的頁面"
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "senses": [
    {
      "form_of": [
        {
          "word": "augmentātus"
        }
      ],
      "glosses": [
        "augmentātus 的屈折变化形式:",
        "主格/呼格陽性複數"
      ],
      "tags": [
        "form-of"
      ]
    },
    {
      "form_of": [
        {
          "word": "augmentātus"
        }
      ],
      "glosses": [
        "augmentātus 的屈折变化形式:",
        "屬格陽性/中性單數"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "augmentati"
}

Download raw JSONL data for augmentati meaning in All languages combined (0.8kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-10-06 from the zhwiktionary dump dated 2024-10-02 using wiktextract (9f93753 and c1a3a36). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.