"Zenóbia" meaning in All languages combined

See Zenóbia on Wiktionary

Proper name [匈牙利語]

Etymology: 借自古希臘語 Ζηνοβῐ́ᾱ (Zēnobíā)。參見英語 Zenobia。
  1. 女性歷史人名,等價於英語Zenobia
    Sense id: zh-Zenóbia-hu-name-1lSIJwxW Categories (other): 來自古希臘語的匈牙利語女性名字, 匈牙利語名字
The following are not (yet) sense-disambiguated

Proper name [葡萄牙語]

  1. 女性歷史人名,等價於英語Zenobia
    Sense id: zh-Zenóbia-pt-name-1lSIJwxW Categories (other): 來自古希臘語的葡萄牙語女性名字, 葡萄牙語名字
The following are not (yet) sense-disambiguated

Download JSONL data for Zenóbia meaning in All languages combined (1.5kB)

{
  "categories": [
    {
      "kind": "other",
      "name": "匈牙利語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "匈牙利語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的匈牙利語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的匈牙利語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自古希臘語 Ζηνοβῐ́ᾱ (Zēnobíā)。參見英語 Zenobia。",
  "lang": "匈牙利語",
  "lang_code": "hu",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "來自古希臘語的匈牙利語女性名字",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "匈牙利語名字",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "女性歷史人名,等價於英語Zenobia"
      ],
      "id": "zh-Zenóbia-hu-name-1lSIJwxW"
    }
  ],
  "word": "Zenóbia"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "葡萄牙語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "葡萄牙語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "葡萄牙語陰性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "葡萄牙語",
  "lang_code": "pt",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "來自古希臘語的葡萄牙語女性名字",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "葡萄牙語名字",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "女性歷史人名,等價於英語Zenobia"
      ],
      "id": "zh-Zenóbia-pt-name-1lSIJwxW"
    }
  ],
  "tags": [
    "feminine"
  ],
  "word": "Zenóbia"
}
{
  "categories": [
    "匈牙利語專有名詞",
    "匈牙利語詞元",
    "派生自古希臘語的匈牙利語詞",
    "源自古希臘語的匈牙利語借詞"
  ],
  "etymology_text": "借自古希臘語 Ζηνοβῐ́ᾱ (Zēnobíā)。參見英語 Zenobia。",
  "lang": "匈牙利語",
  "lang_code": "hu",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "來自古希臘語的匈牙利語女性名字",
        "匈牙利語名字"
      ],
      "glosses": [
        "女性歷史人名,等價於英語Zenobia"
      ]
    }
  ],
  "word": "Zenóbia"
}

{
  "categories": [
    "葡萄牙語專有名詞",
    "葡萄牙語詞元",
    "葡萄牙語陰性名詞"
  ],
  "lang": "葡萄牙語",
  "lang_code": "pt",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "來自古希臘語的葡萄牙語女性名字",
        "葡萄牙語名字"
      ],
      "glosses": [
        "女性歷史人名,等價於英語Zenobia"
      ]
    }
  ],
  "tags": [
    "feminine"
  ],
  "word": "Zenóbia"
}

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-07-04 from the zhwiktionary dump dated 2024-07-01 using wiktextract (c690d5d and b5d1315). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.