"Siebert" meaning in All languages combined

{
  "categories": [
    {
      "kind": "other",
      "name": "原始日耳曼語紅鏈",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "原始日耳曼語紅鏈/m",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的英語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自德語的英語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "德語姓氏，對應原始日耳曼語 *segaz (“勝利”) + *berhtaz (“明亮的”)。",
  "forms": [
    {
      "form": "Sieberts",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "英語姓氏",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "姓氏。"
      ],
      "id": "zh-Siebert-en-name-sQDpCZq1"
    }
  ],
  "word": "Siebert"
}

{
  "categories": [
    "原始日耳曼語紅鏈",
    "原始日耳曼語紅鏈/m",
    "派生自原始日耳曼語的英語詞",
    "派生自德語的英語詞",
    "英語不可數名詞",
    "英語專有名詞",
    "英語詞元"
  ],
  "etymology_text": "德語姓氏，對應原始日耳曼語 *segaz (“勝利”) + *berhtaz (“明亮的”)。",
  "forms": [
    {
      "form": "Sieberts",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "英語姓氏"
      ],
      "glosses": [
        "姓氏。"
      ]
    }
  ],
  "word": "Siebert"
}

{
  "called_from": "extractor/zh/page/parse_section/192",
  "msg": "Unhandled subtitle: 統計",
  "path": [
    "Siebert"
  ],
  "section": "英語",
  "subsection": "統計",
  "title": "Siebert",
  "trace": ""
}