"Kerberos" meaning in All languages combined

{
  "categories": [
    {
      "kind": "other",
      "name": "古希臘語紅鏈",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "古希臘語紅鏈/l",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的英語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自古希臘語 Κέρβερος (Kérberos)。",
  "lang": "英語",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "alt_of": [
        {
          "word": "Cerberus"
        }
      ],
      "glosses": [
        "Cerberus的另一種拼寫法"
      ],
      "id": "zh-Kerberos-en-name-1NWyq-Js",
      "tags": [
        "alt-of"
      ]
    },
    {
      "glosses": [
        "冥衛四"
      ],
      "id": "zh-Kerberos-en-name-GXFspJcp",
      "topics": [
        "astronomy"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈkɜːbəɹəs/"
    },
    {
      "ipa": "/ˈkɜɹbəɹəs/"
    }
  ],
  "word": "Kerberos"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "派生自古希臘語的捷克語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的捷克語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自古希臘語 Κέρβερος (Kérberos)。",
  "lang": "捷克語",
  "lang_code": "cs",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "刻耳柏洛斯"
      ],
      "id": "zh-Kerberos-cs-name-HrOejSEF",
      "raw_tags": [
        "希臘神話",
        "動物名詞"
      ]
    },
    {
      "glosses": [
        "冥衛四"
      ],
      "id": "zh-Kerberos-cs-name-GXFspJcp",
      "raw_tags": [
        "非動物名詞"
      ],
      "topics": [
        "astronomy"
      ]
    }
  ],
  "tags": [
    "error-lua-exec"
  ],
  "word": "Kerberos"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "芬蘭語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "芬蘭語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "芬蘭語",
  "lang_code": "fi",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "刻耳柏洛斯"
      ],
      "id": "zh-Kerberos-fi-name-HrOejSEF",
      "raw_tags": [
        "希臘神話"
      ]
    }
  ],
  "word": "Kerberos"
}

{
  "categories": [
    "派生自古希臘語的捷克語詞",
    "源自古希臘語的捷克語借詞"
  ],
  "etymology_text": "源自古希臘語 Κέρβερος (Kérberos)。",
  "lang": "捷克語",
  "lang_code": "cs",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "刻耳柏洛斯"
      ],
      "raw_tags": [
        "希臘神話",
        "動物名詞"
      ]
    },
    {
      "glosses": [
        "冥衛四"
      ],
      "raw_tags": [
        "非動物名詞"
      ],
      "topics": [
        "astronomy"
      ]
    }
  ],
  "tags": [
    "error-lua-exec"
  ],
  "word": "Kerberos"
}

{
  "categories": [
    "芬蘭語專有名詞",
    "芬蘭語詞元"
  ],
  "lang": "芬蘭語",
  "lang_code": "fi",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "刻耳柏洛斯"
      ],
      "raw_tags": [
        "希臘神話"
      ]
    }
  ],
  "word": "Kerberos"
}

{
  "categories": [
    "古希臘語紅鏈",
    "古希臘語紅鏈/l",
    "派生自古希臘語的英語詞",
    "英語不可數名詞",
    "英語專有名詞",
    "英語詞元"
  ],
  "etymology_text": "源自古希臘語 Κέρβερος (Kérberos)。",
  "lang": "英語",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "alt_of": [
        {
          "word": "Cerberus"
        }
      ],
      "glosses": [
        "Cerberus的另一種拼寫法"
      ],
      "tags": [
        "alt-of"
      ]
    },
    {
      "glosses": [
        "冥衛四"
      ],
      "topics": [
        "astronomy"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈkɜːbəɹəs/"
    },
    {
      "ipa": "/ˈkɜɹbəɹəs/"
    }
  ],
  "word": "Kerberos"
}

{
  "called_from": "luaexec/683",
  "msg": "LUA error in #invoke('cs-headword', 'show', '專有名詞') parent ('Template:Cs-proper noun', {'g': 'm'})",
  "path": [
    "Kerberos",
    "cs-proper noun",
    "#invoke",
    "#invoke"
  ],
  "section": "捷克語",
  "subsection": "專有名詞",
  "title": "Kerberos",
  "trace": "[string \"cs-headword\"]:133: Unrecognized gender: 'm'"
}