See Borgia on Wiktionary
{ "categories": [ { "kind": "other", "name": "有2個詞條的頁面", "parents": [], "source": "w" }, { "kind": "other", "name": "有詞條的頁面", "parents": [], "source": "w" }, { "kind": "other", "name": "派生自意大利語的英語詞", "parents": [], "source": "w" }, { "kind": "other", "name": "派生自西班牙語的英語詞", "parents": [], "source": "w" }, { "kind": "other", "name": "源自意大利語的英語借詞", "parents": [], "source": "w" }, { "kind": "other", "name": "英語不可數名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "英語專有名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "英語詞元", "parents": [], "source": "w" } ], "etymology_text": "借自意大利語 Borgia,源自西班牙語 Borja。", "lang": "英語", "lang_code": "en", "pos": "name", "pos_title": "專有名詞", "senses": [ { "categories": [ { "kind": "other", "name": "英語姓氏", "parents": [], "source": "w" } ], "glosses": [ "姓氏。尤指文藝復興時期的波吉亞家族" ], "id": "zh-Borgia-en-name-6i0FIruI" } ], "word": "Borgia" } { "categories": [ { "kind": "other", "name": "性別遵照被指代者的意大利語名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "意大利語專有名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "意大利語詞元", "parents": [], "source": "w" }, { "kind": "other", "name": "意大利語陰性名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "意大利語陽性名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "有2個詞條的頁面", "parents": [], "source": "w" }, { "kind": "other", "name": "有不規則複數的意大利語專有名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "有多種性別的意大利語名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "有詞條的頁面", "parents": [], "source": "w" }, { "kind": "other", "name": "派生自西班牙語的意大利語詞", "parents": [], "source": "w" }, { "kind": "other", "name": "源自西班牙語的意大利語借詞", "parents": [], "source": "w" } ], "etymology_text": "西班牙語 Borja 的意大利語化。", "lang": "意大利語", "lang_code": "it", "pos": "name", "pos_title": "專有名詞", "raw_tags": [ "遵詞義" ], "senses": [ { "categories": [ { "kind": "other", "name": "意大利語姓氏", "parents": [], "source": "w" } ], "glosses": [ "姓氏" ], "id": "zh-Borgia-it-name-uF8m3xJp" }, { "glosses": [ "波吉亞家族" ], "id": "zh-Borgia-it-name-krdTITfJ" } ], "tags": [ "feminine", "masculine" ], "word": "Borgia" }
{ "categories": [ "性別遵照被指代者的意大利語名詞", "意大利語專有名詞", "意大利語詞元", "意大利語陰性名詞", "意大利語陽性名詞", "有2個詞條的頁面", "有不規則複數的意大利語專有名詞", "有多種性別的意大利語名詞", "有詞條的頁面", "派生自西班牙語的意大利語詞", "源自西班牙語的意大利語借詞" ], "etymology_text": "西班牙語 Borja 的意大利語化。", "lang": "意大利語", "lang_code": "it", "pos": "name", "pos_title": "專有名詞", "raw_tags": [ "遵詞義" ], "senses": [ { "categories": [ "意大利語姓氏" ], "glosses": [ "姓氏" ] }, { "glosses": [ "波吉亞家族" ] } ], "tags": [ "feminine", "masculine" ], "word": "Borgia" } { "categories": [ "有2個詞條的頁面", "有詞條的頁面", "派生自意大利語的英語詞", "派生自西班牙語的英語詞", "源自意大利語的英語借詞", "英語不可數名詞", "英語專有名詞", "英語詞元" ], "etymology_text": "借自意大利語 Borgia,源自西班牙語 Borja。", "lang": "英語", "lang_code": "en", "pos": "name", "pos_title": "專有名詞", "senses": [ { "categories": [ "英語姓氏" ], "glosses": [ "姓氏。尤指文藝復興時期的波吉亞家族" ] } ], "word": "Borgia" }
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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-02-26 from the zhwiktionary dump dated 2025-02-21 using wiktextract (ce0be54 and f2e72e5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.