"Bergman" meaning in All languages combined

See Bergman on Wiktionary

Proper name [波蘭語]

Etymology: 源自德語 Bergmann。
  1. 男性姓氏
    Sense id: zh-Bergman-pl-name-wFMgi5g- Categories (other): 波蘭語姓氏, 波蘭語男性姓氏
The following are not (yet) sense-disambiguated

Proper name [波蘭語]

Etymology: 源自德語 Bergmann。
  1. 女性姓氏
    Sense id: zh-Bergman-pl-name-4wpDcETF Categories (other): 波蘭語女性姓氏, 波蘭語姓氏
The following are not (yet) sense-disambiguated
Derived forms: Bergmanowa, Bergmanówna

Proper name [瑞典語]

Forms: Bergmans
Etymology: 源自 berg (“山”) + man (“男人”)。
  1. 姓氏
    Sense id: zh-Bergman-sv-name-uF8m3xJp Categories (other): 瑞典語姓氏
The following are not (yet) sense-disambiguated

Proper name [英語]

  1. 姓氏。
    Sense id: zh-Bergman-en-name-sQDpCZq1 Categories (other): 英語姓氏
  2. 街區名,位於加拿大艾伯塔埃德蒙頓東部。
    Sense id: zh-Bergman-en-name-6yqTQjap
The following are not (yet) sense-disambiguated

Proper name [荷蘭語]

IPA: /ˈbɛrx.mɑn/
Etymology: 源自 bergman。
  1. 姓氏
    Sense id: zh-Bergman-nl-name-uF8m3xJp Categories (other): 荷蘭語姓氏
The following are not (yet) sense-disambiguated

Inflected forms

{
  "categories": [
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "英語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "英語姓氏",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "姓氏。"
      ],
      "id": "zh-Bergman-en-name-sQDpCZq1"
    },
    {
      "glosses": [
        "街區名,位於加拿大艾伯塔埃德蒙頓東部。"
      ],
      "id": "zh-Bergman-en-name-6yqTQjap"
    }
  ],
  "word": "Bergman"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自 bergman。",
  "lang": "荷蘭語",
  "lang_code": "nl",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "荷蘭語姓氏",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "姓氏"
      ],
      "id": "zh-Bergman-nl-name-uF8m3xJp"
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈbɛrx.mɑn/"
    }
  ],
  "word": "Bergman"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "來自德語的波蘭語姓氏",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語個人名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語陽性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自德語的波蘭語詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自德語 Bergmann。",
  "lang": "波蘭語",
  "lang_code": "pl",
  "pos": "name",
  "raw_tags": [
    "個人"
  ],
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "波蘭語姓氏",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "波蘭語男性姓氏",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "男性姓氏"
      ],
      "id": "zh-Bergman-pl-name-wFMgi5g-"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Bergman"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "來自德語的波蘭語姓氏",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語無屈折名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "波蘭語陰性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自德語的波蘭語詞",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "Bergmanowa"
    },
    {
      "word": "Bergmanówna"
    }
  ],
  "etymology_text": "源自德語 Bergmann。",
  "lang": "波蘭語",
  "lang_code": "pl",
  "pos": "name",
  "raw_tags": [
    "無屈折"
  ],
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "波蘭語女性姓氏",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "波蘭語姓氏",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "女性姓氏"
      ],
      "id": "zh-Bergman-pl-name-4wpDcETF"
    }
  ],
  "tags": [
    "feminine"
  ],
  "word": "Bergman"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "有4個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語複合詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "瑞典語通性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自 berg (“山”) + man (“男人”)。",
  "forms": [
    {
      "form": "Bergmans",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "瑞典語",
  "lang_code": "sv",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "瑞典語姓氏",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "姓氏"
      ],
      "id": "zh-Bergman-sv-name-uF8m3xJp"
    }
  ],
  "tags": [
    "common"
  ],
  "word": "Bergman"
}
{
  "categories": [
    "來自德語的波蘭語姓氏",
    "有4個詞條的頁面",
    "有詞條的頁面",
    "波蘭語個人名詞",
    "波蘭語專有名詞",
    "波蘭語詞元",
    "波蘭語陽性名詞",
    "派生自德語的波蘭語詞"
  ],
  "etymology_text": "源自德語 Bergmann。",
  "lang": "波蘭語",
  "lang_code": "pl",
  "pos": "name",
  "raw_tags": [
    "個人"
  ],
  "senses": [
    {
      "categories": [
        "波蘭語姓氏",
        "波蘭語男性姓氏"
      ],
      "glosses": [
        "男性姓氏"
      ]
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Bergman"
}

{
  "categories": [
    "來自德語的波蘭語姓氏",
    "有4個詞條的頁面",
    "有詞條的頁面",
    "波蘭語專有名詞",
    "波蘭語無屈折名詞",
    "波蘭語詞元",
    "波蘭語陰性名詞",
    "派生自德語的波蘭語詞"
  ],
  "derived": [
    {
      "word": "Bergmanowa"
    },
    {
      "word": "Bergmanówna"
    }
  ],
  "etymology_text": "源自德語 Bergmann。",
  "lang": "波蘭語",
  "lang_code": "pl",
  "pos": "name",
  "raw_tags": [
    "無屈折"
  ],
  "senses": [
    {
      "categories": [
        "波蘭語女性姓氏",
        "波蘭語姓氏"
      ],
      "glosses": [
        "女性姓氏"
      ]
    }
  ],
  "tags": [
    "feminine"
  ],
  "word": "Bergman"
}

{
  "categories": [
    "有4個詞條的頁面",
    "有詞條的頁面",
    "瑞典語專有名詞",
    "瑞典語複合詞",
    "瑞典語詞元",
    "瑞典語通性名詞"
  ],
  "etymology_text": "源自 berg (“山”) + man (“男人”)。",
  "forms": [
    {
      "form": "Bergmans",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "瑞典語",
  "lang_code": "sv",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "瑞典語姓氏"
      ],
      "glosses": [
        "姓氏"
      ]
    }
  ],
  "tags": [
    "common"
  ],
  "word": "Bergman"
}

{
  "categories": [
    "有4個詞條的頁面",
    "有詞條的頁面",
    "英語不可數名詞",
    "英語專有名詞",
    "英語詞元"
  ],
  "lang": "英語",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "英語姓氏"
      ],
      "glosses": [
        "姓氏。"
      ]
    },
    {
      "glosses": [
        "街區名,位於加拿大艾伯塔埃德蒙頓東部。"
      ]
    }
  ],
  "word": "Bergman"
}

{
  "categories": [
    "有4個詞條的頁面",
    "有詞條的頁面",
    "荷蘭語專有名詞",
    "荷蘭語詞元"
  ],
  "etymology_text": "源自 bergman。",
  "lang": "荷蘭語",
  "lang_code": "nl",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "荷蘭語姓氏"
      ],
      "glosses": [
        "姓氏"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈbɛrx.mɑn/"
    }
  ],
  "word": "Bergman"
}

Download raw JSONL data for Bergman meaning in All languages combined (2.1kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.