"Berbecariu" meaning in All languages combined

See Berbecariu on Wiktionary

Proper name [羅馬尼亞語]

Audio: LL-Q7913 (ron)-KlaudiuMihaila-Berbecariu.wav Forms: lui Berbecariu
Etymology: 源自 berbecar。
  1. 來自職業的姓氏
    Sense id: zh-Berbecariu-ro-name-iQlji4Jh Categories (other): 來自職業的羅馬尼亞語姓氏, 羅馬尼亞語姓氏
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "羅馬尼亞語陽性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "源自 berbecar。",
  "forms": [
    {
      "form": "lui Berbecariu",
      "raw_tags": [
        "屬格/與格"
      ]
    }
  ],
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "來自職業的羅馬尼亞語姓氏",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "羅馬尼亞語姓氏",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "來自職業的姓氏"
      ],
      "id": "zh-Berbecariu-ro-name-iQlji4Jh"
    }
  ],
  "sounds": [
    {
      "audio": "LL-Q7913 (ron)-KlaudiuMihaila-Berbecariu.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/7/7d/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/7/7d/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav.ogg",
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q7913 (ron)-KlaudiuMihaila-Berbecariu.wav"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Berbecariu"
}
{
  "categories": [
    "有1個詞條的頁面",
    "有詞條的頁面",
    "羅馬尼亞語專有名詞",
    "羅馬尼亞語詞元",
    "羅馬尼亞語陽性名詞"
  ],
  "etymology_text": "源自 berbecar。",
  "forms": [
    {
      "form": "lui Berbecariu",
      "raw_tags": [
        "屬格/與格"
      ]
    }
  ],
  "lang": "羅馬尼亞語",
  "lang_code": "ro",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "來自職業的羅馬尼亞語姓氏",
        "羅馬尼亞語姓氏"
      ],
      "glosses": [
        "來自職業的姓氏"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "LL-Q7913 (ron)-KlaudiuMihaila-Berbecariu.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/7/7d/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/7/7d/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav/LL-Q7913_(ron)-KlaudiuMihaila-Berbecariu.wav.ogg",
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q7913 (ron)-KlaudiuMihaila-Berbecariu.wav"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "Berbecariu"
}

Download raw JSONL data for Berbecariu meaning in All languages combined (1.0kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.