"𐌼𐌰𐌹𐍃𐍄𐍃" meaning in All languages combined

{
  "categories": [
    {
      "kind": "other",
      "name": "哥特語形容詞最高級",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "哥特語非詞元形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的哥特語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始日耳曼語的哥特語繼承詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "繼承自原始日耳曼語 *maistaz。",
  "forms": [
    {
      "form": "maists",
      "tags": [
        "romanization"
      ]
    }
  ],
  "lang": "哥特語",
  "lang_code": "got",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "哥特語形容詞最高級",
          "parents": [],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "word": "𐌼𐌹𐌺𐌹𐌻𐍃"
        }
      ],
      "glosses": [
        "最大的，最高程度的；𐌼𐌹𐌺𐌹𐌻𐍃 (mikils)的最高級"
      ],
      "id": "zh-𐌼𐌰𐌹𐍃𐍄𐍃-got-adj-7kzPu7mc",
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "𐌼𐌰𐌹𐍃𐍄𐍃"
}

{
  "categories": [
    "哥特語形容詞最高級",
    "哥特語非詞元形式",
    "有1個詞條的頁面",
    "派生自原始日耳曼語的哥特語詞",
    "源自原始日耳曼語的哥特語繼承詞"
  ],
  "etymology_text": "繼承自原始日耳曼語 *maistaz。",
  "forms": [
    {
      "form": "maists",
      "tags": [
        "romanization"
      ]
    }
  ],
  "lang": "哥特語",
  "lang_code": "got",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        "superlative of/without nocat",
        "哥特語形容詞最高級"
      ],
      "form_of": [
        {
          "word": "𐌼𐌹𐌺𐌹𐌻𐍃"
        }
      ],
      "glosses": [
        "最大的，最高程度的；𐌼𐌹𐌺𐌹𐌻𐍃 (mikils)的最高級"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "𐌼𐌰𐌹𐍃𐍄𐍃"
}