"сброд" meaning in All languages combined

{
  "categories": [
    {
      "kind": "other",
      "name": "俄語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語無生名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語紅鏈",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語紅鏈/l",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語陽性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "含有前綴с-的俄語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有多餘標題行參數的俄語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始斯拉夫語的俄語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始斯拉夫語的俄語繼承詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "來自сбреда́ться (sbredátʹsja, “聚集到一個地方”)，с- (s-) + броди́ть (brodítʹ, “漫遊”)，源頭來自原始斯拉夫語 *brodìti。",
  "forms": [
    {
      "form": "sbrod",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "сбро́да",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "俄語",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "暴民，烏合之眾"
      ],
      "id": "zh-сброд-ru-noun-uMRqCZoZ",
      "tags": [
        "derogatory"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "masculine",
    "uncountable"
  ],
  "word": "сброд"
}

{
  "categories": [
    "俄語不可數名詞",
    "俄語名詞",
    "俄語無生名詞",
    "俄語紅鏈",
    "俄語紅鏈/l",
    "俄語詞元",
    "俄語陽性名詞",
    "含有前綴с-的俄語詞",
    "有多餘標題行參數的俄語詞",
    "派生自原始斯拉夫語的俄語詞",
    "源自原始斯拉夫語的俄語繼承詞"
  ],
  "etymology_text": "來自сбреда́ться (sbredátʹsja, “聚集到一個地方”)，с- (s-) + броди́ть (brodítʹ, “漫遊”)，源頭來自原始斯拉夫語 *brodìti。",
  "forms": [
    {
      "form": "sbrod",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "сбро́да",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "俄語",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "暴民，烏合之眾"
      ],
      "tags": [
        "derogatory"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "masculine",
    "uncountable"
  ],
  "word": "сброд"
}